MolloyMaths

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@Jafilkhan. 6 күн бұрын

sortest path is SCGIT -->>34 Is it correct or not ply confirm me.

@ProsperChinonge-wq6if 10 күн бұрын

helpful

@padraigfitzpatrick762 11 күн бұрын

The square root of w^2 is plus or minus w, so you only need to find one value of w then just get the negative of that. That means you don’t need to write it in the generalised format and the question is much easier. Excellent set of videos, though!

@molloymaths1092 11 күн бұрын

Yes but it's part of a general procedure for higher powers. Thanks for your comment.

@kjoter 18 күн бұрын

thank you

@molloymaths1092 17 күн бұрын

You're welcome.

@caoilainndoyle2320 19 күн бұрын

these solutions are wrong. q 7 - look at the marking scheme. your answer is not correct.

@molloymaths1092 19 күн бұрын

Other than the fact that I didn't convert to minutes and seconds in part (e), I can't see what you are talking about.

@AmirmahdiAlinaghipour 23 күн бұрын

amazing

@nxtgamming3510 27 күн бұрын

Legend is learning 1 day before exam

@richardslater677 29 күн бұрын

You can do a general proof by contradiction to show that the square roots of all positive integers (that are not perfect squares) are irrational.

@I.am.nedzamba Ай бұрын

Thank you very much

@molloymaths1092 Ай бұрын

You're welcome.

@SassouKhabou Ай бұрын

Thank you for this! Very clear and straightforward and actually makes Gauss-Jordan elimination fun!

@molloymaths1092 Ай бұрын

Thanks. Glad it helps.

@musaabubakar4293 Ай бұрын

Wow! Thank you so much for making me great

@molloymaths1092 Ай бұрын

No problem. Thanks.

@tradingchris Ай бұрын

Not a gauss-jordan!

@molloymaths1092 Ай бұрын

Yes it is! When using RREF it's Gauss Jordan Elimination. When using REF it's Gaussian Elimination. I have used RREF in this video. I think I mention Gauss Jordan at the end of the video. Thanks for the comment.

@valeriereid2337 Ай бұрын

Thank you.

@molloymaths1092 Ай бұрын

You're welcome.

@user-dy5uv8xv4k Ай бұрын

Vos explications sont tellement simples, j'ai le bac à passer et j'me fais une remise à niveau force à vous

@molloymaths1092 Ай бұрын

Merci. Bonne chance.

@briska8945 2 ай бұрын

Can equation #7 be factorized any further into (x - 1)(2x + 5)?

@molloymaths1092 2 ай бұрын

Yes it can. The idea is to simplify the fraction so either way is fine. Thanks for the comment.

@Meatbrick 2 ай бұрын

Safe to say I couldnt understand anything past 9:00. Could you leave a trail of references and math topics that a student could look into to better understand?

@molloymaths1092 2 ай бұрын

You'll have to be more specific.

@HarshPundir-gt4qj 2 ай бұрын

Where are you from brother

@molloymaths1092 2 ай бұрын

Ireland

@matukajackline6920 3 ай бұрын

The work is moving on fantastically😅😅

@molloymaths1092 2 ай бұрын

Great

@andrewrangecroft805 3 ай бұрын

Will watch this later, need it for my engineering foundation maths. Eeep

@molloymaths1092 3 ай бұрын

Good luck

@Gradekeeper376 3 ай бұрын

I am grateful that teachers like you exist

@molloymaths1092 3 ай бұрын

Thank you.

@BabooBRamkissoon 3 ай бұрын

Thanks ❤

@molloymaths1092 3 ай бұрын

You're welcome!

@offthepathworks9171 3 ай бұрын

Lovely video, great intro to the formula used for parametric diff.

@molloymaths1092 3 ай бұрын

Thanks.

@gn_apollo6534 3 ай бұрын

Can you do the physics paper by any chance?

@molloymaths1092 3 ай бұрын

Sorry. I'm afraid I will not be doing the Physics paper.

@gn_apollo6534 3 ай бұрын

@@molloymaths1092 by any chance could you just do the circular motion question on its q7.

@yuanli5619 3 ай бұрын

For the force diagram, could you just symbolically put R as normal force, Ff as friction and such? Like I didn't specifically include the actual value of those forces.

@molloymaths1092 3 ай бұрын

Yes. I see in previous marking schemes that they didn't include all the values. Have a look at last year's marking scheme for the connected particles question. I probably over did it a bit.

@robwhitty 3 ай бұрын

Thanks for clarifying

@robwhitty 3 ай бұрын

Thanks for reply U would be forgiven to think it wasn’t a right angle triangle I would suggest the examiners made it look anything but a right angle triangle in their sketch which I feel is sloppy for a state exam Would you agree ? Really enjoy your channel

@molloymaths1092 3 ай бұрын

There is a little square at O indicating a right angle. With 3-D questions, right angles very often don't appear to be right angles in the diagram. You've got to imagine the real-life situation as described.

@ahjpbtw8360 4 ай бұрын

Could you please do the 2024 applied maths paper solutions🙏🏿

@molloymaths1092 3 ай бұрын

I'll try and get them done this week.

@ahjpbtw8360 3 ай бұрын

@@molloymaths1092 thank you so much

@robwhitty 4 ай бұрын

Is the triangle RHO supposed to be or assumed to be a right angles triangle ?

@molloymaths1092 3 ай бұрын

Yes. It is given as a right angled triangle in the question.

@irishdrilltunes4577 4 ай бұрын

why is RVA = v1 - V2 and not V2 - V1. if its final vel - initial vel. same with u

@molloymaths1092 4 ай бұрын

V1 and V2 are final velocities of the two particles. The difference is the relative velocity (After)

@leehaengboklix2503 4 ай бұрын

was the best long question on the paper honestly

@jaycraine8335 4 ай бұрын

Would u lose many marks if u switched the null hypothesis and alternative hypothesis but still got the right answer and right conclusion

@molloymaths1092 4 ай бұрын

Not many I would imagine. I would think HPC at least.

@mapspablo104 4 ай бұрын

Well explained

@molloymaths1092 4 ай бұрын

Thanks

@calibvr 4 ай бұрын

man you are the king you have helped me so much i used to be failing hl maths 🙏

@molloymaths1092 4 ай бұрын

Thanks. Glad to have helped.

@Ghosted9 4 ай бұрын

have paper 2 tmr cheers for the help

@molloymaths1092 4 ай бұрын

Good luck.

@Justprettytingz 4 ай бұрын

For simultaneous equations can't you minus the two equations instead of adding them

@molloymaths1092 4 ай бұрын

I think I did after multiplying by minus 3.

@padraigoshea4634 4 ай бұрын

Any predictions for tomorrow?

@molloymaths1092 4 ай бұрын

Difficult to predict. Hopefully it will be at the same level as paper 1.

@pinkrose6543 4 ай бұрын

for part c, how do u know when the cosine / sine value is the reference angle, and not just the angle?

@molloymaths1092 4 ай бұрын

In part c, you have to solve two equations. Sin t = 0 and Cos t = 1/2. In all these cases there will be two solutions. Sin and Cos (and indeed Tan) are positive in two quadrants and negative in two quadrants so you will get two solutions between 0 to 360 degrees. Any angle greater than 90 degrees will require you to look for the reference angle, find the Sin, Cos or Tan of the reference angle, and then decide what the sign will be.

@pinkrose6543 4 ай бұрын

@@molloymaths1092 ok thank you so much!

@Shawnmusic1224 4 ай бұрын

For part C why did you do cos 135 could it not have been cos 45???

@molloymaths1092 4 ай бұрын

45 is in the 1st quadrant. 135 (and Q) are in the second quadrant. 45 is therefore only the reference angle. If you did the cos of 45 you would get (1/root2, 1/root2) so the sign would be incorrect.

@Shawnmusic1224 4 ай бұрын

@@molloymaths1092 thank you so much you're a life saver! Maths paper 2 is tomorrow 🤞

@molloymaths1092 4 ай бұрын

@@Shawnmusic1224 Best of luck.

@justinferizaj2203 4 ай бұрын

what do you think the mark split would be for c(ii) if you got the other side of the angle (5/12pi) ?

@molloymaths1092 4 ай бұрын

I don't have the marking scheme. so I'd only be guessing, but I'd say mid or high partial credit.

@Minrx 4 ай бұрын

im cooked

@toyindada905 4 ай бұрын

Thank you so much, so explanatory 😊

@molloymaths1092 4 ай бұрын

No problem. You're welcome.

@padraigoshea4634 4 ай бұрын

What was your thoughts on the paper? I thought it was easy enough

@molloymaths1092 4 ай бұрын

Looks fairly straight forward. Certainly better than last year.

@berryamv2296 4 ай бұрын

I got the simultaneous equation wrong 😑

@molloymaths1092 4 ай бұрын

Don't worry. Most of the marks should go towards the correct method.

@irishdrilltunes4577 4 ай бұрын

Is there somewhere I can donate or something or take you out for a drink. Cause I don’t think a like or sub is enough to show my gratitude

@molloymaths1092 4 ай бұрын

Not necessary. Glad to have helped. Thanks for your comment.

@irishdrilltunes4577 4 ай бұрын

You don’t even understand how much you have helped me

@molloymaths1092 4 ай бұрын

Glad to have helped.

@irishdrilltunes4577 4 ай бұрын

I fuckin love you

@anjumara783 4 ай бұрын

Why he is after tan wasting time

@molloymaths1092 4 ай бұрын

Don't understand the question!!

@adamrocketer6140 4 ай бұрын

Mr molloy u the goat u carry me all year

@molloymaths1092 4 ай бұрын

Thanks. Glad to hear it.

@KryDu-lv3jk 4 ай бұрын

Exactly what I am seeking . Thanks

@molloymaths1092 4 ай бұрын

Great. Glad it helped.

@Eoghan0C 4 ай бұрын

Very helpful, thank you!

@molloymaths1092 4 ай бұрын

You're welcome.

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