Saadar naman aapke charno me.. ❤ Thanks a ton boss🎉🎉🎉
@ENGINEERINGSTREAMLINEDКүн бұрын
@@gauravshakrawal4336 Thanks for such kind words 😀. Just tried to explain in a simple way.
@manjuvenibikkina342425 күн бұрын
Thank you 🙏🙏🙏
@ENGINEERINGSTREAMLINED25 күн бұрын
Thanks for the appreciation
@drugbaba28 күн бұрын
WHAT THAT 2 REPRESENTS
@ENGINEERINGSTREAMLINED27 күн бұрын
The number represents the strength of the flux field. The greater the flux of field through a small surface enclosing a given point, the greater the value of divergence at that point.
@yehansajana666929 күн бұрын
True living god.
@ENGINEERINGSTREAMLINED29 күн бұрын
Thanks for such kind words
@NayanChoudhary-wy3lzАй бұрын
Hello sir....our sir had taught us the formula of solid angle as 2πR^2(1-cos theta) is it tight???
@sandeshadhikari36372 ай бұрын
Best video ever watched
@ENGINEERINGSTREAMLINED2 ай бұрын
Thanks for the appreciation
@rabbihasan67672 ай бұрын
Great explanation 🎉
@ENGINEERINGSTREAMLINED2 ай бұрын
Thanks for the appreciation
@omitbadgers56642 ай бұрын
Good explained, thank you
@ENGINEERINGSTREAMLINED2 ай бұрын
Glad you liked the video
@ENGINEERINGSTREAMLINED2 ай бұрын
Check out the complete video on pressure by clicking on the link below kzbin.info/www/bejne/p4ibkJWGeLBke9ksi=G3xWpOXXUiOQkkpd
@vishnupasunuti-kp6sg2 ай бұрын
But why those are used at aeroplane... You didn't tell that🤔
@ENGINEERINGSTREAMLINED2 ай бұрын
Pitot tubes are used on airplanes as speedometers to measure their speed.
@orwelgeorge80613 ай бұрын
5:10 how did u justify lenght of AB u skipped the most important derivation?
@ENGINEERINGSTREAMLINED3 ай бұрын
Triangle BDO is a right angled triangle at point D with angle BOD = theta and OB = r. So, we can write sin(theta) = BD/ r. On rearranging, we get BD =r *sin(theta). In triangle ABD, angle ADB = d(phi). Now, we use the formula mentioned at 4:39, l = r * theta. So in triangle ABD, AB here represents l and d(phi) represents theta and BD represents r. Finally we can write AB = r sin(theta) * d(phi). I hope it gets clear now.
@captainamericawhyso59173 ай бұрын
Isn't bernoulli's equation about a moving fluid inside a pipe? How do we take the equation between 1 and 2?
@ENGINEERINGSTREAMLINED3 ай бұрын
In the video, Bernoulli's equation is applied at points 1 and 2 which are inside a pipe with a fluid flowing through it.
@captainamericawhyso59173 ай бұрын
Thank you very much, sir, for replying to my question. My confusion was about point 2 actually. Because all the fluid inside the pitot tube is in static equilibrium and does not move, and so point 2 isn't moving either. But then i remembered that in other problems, for example when draining a large tank we also apply the Bernulli equation between a point that's not moving( at the top) and a point that is moving(at the outlet).
@ENGINEERINGSTREAMLINED3 ай бұрын
@@captainamericawhyso5917 Yes. You are right. At a point, inside a flowing fluid, the fluid may come to rest but still you can apply Bernoulli's equation.
@TechWithVideep3 ай бұрын
This is the best explanation of solid angle till now! Thank you 🫡
@ENGINEERINGSTREAMLINED3 ай бұрын
Thanks for the appreciation 😊
@nahianafsan96293 ай бұрын
Simple explanation but effective video. Thanks.
@ENGINEERINGSTREAMLINED3 ай бұрын
Thanks for the appreciation 😊
@FateymaRiaaz3 ай бұрын
The best explanation out there, really. You covered all the points. Thank you!❤️
@ENGINEERINGSTREAMLINED3 ай бұрын
I am happy that you liked the explanation 😊
@user-nd8vd1em4b3 ай бұрын
first of all great video explanation, understood it all some suggestions fo ryou to attract more audience 1) Change the case of your channel name to a normal one, i.e. "Engineering Streamlined", it is more pleasant 2) Dont insert this music file to every video and part, either put slow music ( any artist, but not vocals) or just audio is enough 3) I know that the videos are made through powerpoint, which is not a problem, but try using a different intro, a more simpler one, or make it using AI done, you will look much more proffesional than ever
@ENGINEERINGSTREAMLINED3 ай бұрын
Thank you very much for those thoughtful suggestions. I will try to implement them in my next video.
@md.shafiullahkhan78963 ай бұрын
What is sanctions meeting .
@ENGINEERINGSTREAMLINED3 ай бұрын
I didn't understand your question? Is this related to this video?
@DivyaV-iw7wb3 ай бұрын
4:50 sir, how u can write v1 del t A1
@ENGINEERINGSTREAMLINED3 ай бұрын
The volume of region 1 is written in terms of velocity, area and time. The unit of volume is m^3. If we write units of velocity, area and time then (m/s)*(m^2)* s = m^3.
@divs4983 ай бұрын
@@ENGINEERINGSTREAMLINED thank you sir
@DivyaV-iw7wb3 ай бұрын
sir how limit del t=0 (3:56)
@ENGINEERINGSTREAMLINED3 ай бұрын
Limit in a formula means that we've limited or shortened the formula to a certain extent or in a range of values. In the present video, when we say at Limit ∆t ->0 it means that we have restricted the formula to a short interval of time only. So, for a short instant of time dBsystem /dt gives instantaneous change in B of a system with time. You can check this link for more detail explanation on limits math.stackexchange.com/questions/3920654/why-is-delta-x-tending-to-be-zero-in-dy-dx-and-not-delta-y-tending-to-be-0
@DivyaV-iw7wb3 ай бұрын
sir how to substitute limit del t=0 3:56
@ENGINEERINGSTREAMLINED3 ай бұрын
Limit in a formula means that we've limited or shortened the formula to a certain extent or in a range of values. In the present video, when we say at Limit ∆t ->0 it means that we have restricted the formula to a short interval of time only. So, for a short instant of time dBsystem /dt gives instantaneous change in B of a system with time. You can check this link for more detail explanation on limits math.stackexchange.com/questions/3920654/why-is-delta-x-tending-to-be-zero-in-dy-dx-and-not-delta-y-tending-to-be-0
@10.gauravjungkarki693 ай бұрын
my prof has not explained this topic yet but i am sure you explained much better than he will ever do. Thanks!
@ENGINEERINGSTREAMLINED3 ай бұрын
Thanks for such kind words
@michaelkennedy66544 ай бұрын
Is this your animation? If so it looks like someone else borrowed it. kzbin.info/www/bejne/hYC3Zoetap1motEsi=rJVLoiWK600G0pus
@sharanbalajimanickamoorthy36394 ай бұрын
Amazing video, keep posting more ones like this
@ENGINEERINGSTREAMLINED4 ай бұрын
Thanks for the appreciation
@suranjanroy75284 ай бұрын
Really great video.Thank you sir
@ENGINEERINGSTREAMLINED4 ай бұрын
Glad you liked the video
@mewanan2824 ай бұрын
BEST ONE
@ENGINEERINGSTREAMLINED4 ай бұрын
Thanks
@mewanan2824 ай бұрын
THANKS
@ENGINEERINGSTREAMLINED4 ай бұрын
😀
@rupeshkarar4 ай бұрын
Great explanation
@ENGINEERINGSTREAMLINED4 ай бұрын
Glad you liked the explanation
@henrytzuo85174 ай бұрын
THANK YOU SO MUCH!
@ENGINEERINGSTREAMLINED4 ай бұрын
Glad you liked the video
@nishaantil75034 ай бұрын
Thank u very much sir
@ENGINEERINGSTREAMLINED4 ай бұрын
I hope this video clears your doubts.
@nishaantil75034 ай бұрын
@@ENGINEERINGSTREAMLINED yes sir 🙏🙏
@jtammyjas4 ай бұрын
The demonstration assumes that the height of beaker 2 is rising as beaker 1 is lowering. If, for example, beaker 2 is actually a river drawing the water away, then all of beaker 1 will empty. correct? If the tube on the downside is significantly wider than the tube on the upside so that the weight of the water on the downside is increased (say, if the both tubes were completely filled at the beginning and then released so that no air is allowed to enter from either side but water can escape), would that affect the maximum height of the siphon?
@ENGINEERINGSTREAMLINED4 ай бұрын
The maximum height of the siphon is not dependent on the dimensions of the pipe. It is only dependent on the atmospheric pressure, density of fluid and acceleration due to gravity (g). So, using a tube with wider diameter on the downside will not affect the maximum height of the siphon.
@cleison-em7bk4 ай бұрын
the box of stagnation pressure should be larger than the static pressure
@ENGINEERINGSTREAMLINED4 ай бұрын
Yes. In the pipe flow, I have shown stagnation pressure greater than static pressure. I think you have commented about the last part of the video where stagnation pressure and static pressure boxes of a pitot tube are shown of the same size. The boxes just show the two pressure chambers not their magnitude or value.
@cleison-em7bk4 ай бұрын
@@ENGINEERINGSTREAMLINED oh thanks for your comment . i really appreciate your answer
@ENGINEERINGSTREAMLINED4 ай бұрын
@@cleison-em7bk You are welcome
@nishaantil75035 ай бұрын
Why thita is varying fron 0 to pi/2 not from 0 to pi
@ENGINEERINGSTREAMLINED5 ай бұрын
Theta is varying from 0 to pi/2 because for a surface emission, the radiation is emitted only within the hemispherical volume. If you see the figure at the last part of the video, it is a hemisphere and theta can only be varied between 0 and pi/2. But if you consider volume emission, then emission will happen within a sphere and theta will vary from 0 to pi.
@nishaantil75035 ай бұрын
@@ENGINEERINGSTREAMLINED can you plz make video on how angle 0 to pi cover whole volume of sphere
@ENGINEERINGSTREAMLINED5 ай бұрын
@@nishaantil7503 Ok. But making a video will take few days.
@nishaantil75035 ай бұрын
@@ENGINEERINGSTREAMLINED no problem
@nishaantil75035 ай бұрын
@@ENGINEERINGSTREAMLINED thank u very much 🙏🙏
@Spirit3655 ай бұрын
Which branch
@ENGINEERINGSTREAMLINED5 ай бұрын
Thermal Engineering
@phillyCheesesteak18015 ай бұрын
Amazing explanation. Very clear and helpful. Thank you. ❤
@ENGINEERINGSTREAMLINED5 ай бұрын
I am glad you liked the explanation
@user-pm1io5fk5p5 ай бұрын
Outstanding 😊
@ENGINEERINGSTREAMLINED5 ай бұрын
Thank you for the comment
@ingenium58315 ай бұрын
Thanks. Showing the Pi Theorem very explicitly on that example was very useful. To check if I got it right, I have used another problem in parallel to try it out and it worked :-) (even though I needed to use repeating parameters which differed only in the exponent, leading to an equation with two unknowns. But choosing one unknown as one solved the issue)
@ENGINEERINGSTREAMLINED5 ай бұрын
I am glad the video was useful for you.
@thequestion75506 ай бұрын
School has failed you.
@ENGINEERINGSTREAMLINED6 ай бұрын
Did you like the video or did not like the video?
@thequestion75506 ай бұрын
Started out good but then went south when proven phenomenology was glossed over as an impossibility. @@ENGINEERINGSTREAMLINED
@fijjikhan21256 ай бұрын
Well explained...thumbs up
@ENGINEERINGSTREAMLINED6 ай бұрын
Thank you very much for the comment
@p.jaisha88186 ай бұрын
Water. Reason : Water is less denser than oil
@ENGINEERINGSTREAMLINED6 ай бұрын
Water is denser than oil
@thaerthaer11207 ай бұрын
You don't explain what's the meaning of why we have 2 unit vectors ??what's the reason for that and how it's come 2 ?
@ENGINEERINGSTREAMLINED7 ай бұрын
Which time frame in the video are you referring to?
@philstuf8 ай бұрын
What a fantastic explanation of how a PITOT tube works... Excellent job.
@ENGINEERINGSTREAMLINED8 ай бұрын
Thanks for the compliment. I am happy that you liked the explanation 😃
@karthikp26508 ай бұрын
Sorry I didn't understand
@ENGINEERINGSTREAMLINED8 ай бұрын
Which part you didn't understand?
@RiyaMathur-oq5qk8 ай бұрын
Love from India
@ENGINEERINGSTREAMLINED8 ай бұрын
Thanks for the appreciation😀
@user-om6wp2qm4k9 ай бұрын
If the Siphon working is due to weight difference, then what is it that keeps the particles linked together like the chain that constantly pulls water. If liquid particles are not linked together, they can't create siphons.
@ENGINEERINGSTREAMLINED9 ай бұрын
I think you have not understood the concept clearly. The first theory of siphoning which I discussed due to weight difference is used by a man named Vittorio Zonca which failed as I said in the video. Subsequently I said, siphoning happens due to pressure difference. In the beaker which is at a higher elevation, the end of the pipe is at atmospheric pressure and the end of the pipe on the other beaker (at lower elevation) is at a lower pressure (vacuum) which initiates the flow of the liquid. The liquid flow stops when the liquid level on both the beakers becomes equal resulting the pressure on both the sides to become equal.
@andrewdemos30099 ай бұрын
This is badass
@ENGINEERINGSTREAMLINED9 ай бұрын
Did you like the explanation?
@luc61527 ай бұрын
sure is, especially the intro!
@sackolistran61169 ай бұрын
This is great video. But I am interested in how to calculate the time required for the liquid level in both reservoirs to be at the same level.
@ENGINEERINGSTREAMLINED9 ай бұрын
Thanks for the comment. I will have to think how to calculate the time required for the liquid level in both reservoirs to be at the same level. If I get the answer, I will comment it here.
@davideviglione51427 ай бұрын
Is it a differential equation in which we can calculate time constant?
@sackolistran61167 ай бұрын
I know that, but can you solve that differential equation and write the solution.
@manfredbogner97999 ай бұрын
sehr gut
@ENGINEERINGSTREAMLINED9 ай бұрын
Danke🙂
@anshulgupta975410 ай бұрын
Thanks for the fantastic explanation. Not only did it help me to revise a few concepts but also helped me understand those concepts in a much better way. Subscribed the channel, looking forward to more such content
@ENGINEERINGSTREAMLINED10 ай бұрын
I am glad that you liked the explanation. I will continue to make more videos related to fluid mechanics and heat transfer. Thanks for the appreciation.