Oligo- and poly- aniline basics
11:40
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@fabioronci799
@fabioronci799 5 күн бұрын
Thank you for this nice explanation. Is there a specific reason for not considering other ions like dithionate (S2O62-, +5) and dithionite (S2O42-, +3)?
@420gan3
@420gan3 7 күн бұрын
Savior
@genres381
@genres381 12 күн бұрын
Could you explain why projector operator method works. You've done lots of videos doing it but no explanation.
@lseinjr1
@lseinjr1 11 күн бұрын
The explanation is far more complicated than describing the method. Ultimately, the method exploits the fact that reducible representations are linear combinations of irreducible representations that are orthogonal to each other. In a sense, irreducible representations act like eigenfunctions with different eigenvalues (which are orthogonal to each other. Irreducible representations form a "complete set" the same way that the eigenfunctions of an operator in QM do. More directly, it is a consequence of the Great Orthogonality Theorem.
@sophiamattey4156
@sophiamattey4156 13 күн бұрын
saved my life 6 years later THANK U
@gauravjyotid.kalita3417
@gauravjyotid.kalita3417 16 күн бұрын
More videos on formal charges, valency and ionic charges
@lseinjr1
@lseinjr1 15 күн бұрын
Will do!
@linjunghua2245
@linjunghua2245 18 күн бұрын
Very helpful!
@lseinjr1
@lseinjr1 15 күн бұрын
I'm glad it was helpful!
@uchiha-madara777
@uchiha-madara777 20 күн бұрын
Thanks for the derivation i kept finding videos but none of them explained it that simple
@lseinjr1
@lseinjr1 19 күн бұрын
Glad it helped!
@cricketcraze2125
@cricketcraze2125 25 күн бұрын
sir plz make the video for the no of unshifted atoms
@Onyedikachi-s2y
@Onyedikachi-s2y 25 күн бұрын
This was very helpful...but I didn't get the reason we excluded water
@lseinjr1
@lseinjr1 24 күн бұрын
The concentration of water is so large relative to everything else that, for all practical purposes, its concentration does not change. And - if it doesn't change, why bother to keep track of it? [Note that we use the same rule for pure solid and liquids - because their "concentration" does not change, since the concentration is effectively the density, and the density changes very little. Does that make sense?]
@Hummus_Yummus
@Hummus_Yummus Ай бұрын
You are my favourite man alive! This was explained very clearly and thoroughly, and I had no trouble at all understanding it. The music at the start was a really nice surprise as well! You don't see that kinda thing often!
@lseinjr1
@lseinjr1 15 күн бұрын
You're very welcome!
@srijanasharma6913
@srijanasharma6913 Ай бұрын
❤❤
@saoudjutt253
@saoudjutt253 Ай бұрын
Dear professor, i have a query regarding the s1 contribution in ligand group orbital of E degenerate orbital corresponding to x- axis. I consulted with miselar and tarr's inorganic chemistry where the author mentioned that the contribution of each s orbital should be equal to be one in the case of ammonia. But in this video it seems that, the contribution of s1 orbital has been increased beyond 1 in the ligand group orbitals. It would be nice of you if you could spare some time for my query
@lseinjr1
@lseinjr1 Ай бұрын
I assume you are talking about ammonia? Each s1 orbital has the same coefficient in A1, but that is definitely NOT true for E, not the least reason being that each E has one node; at a node, the orbital contribution is zero. Btw, Miessler and Tarr is a poor resource for group theory. They show few complete examples. "Concepts and Models of Inorganic Chemistry",. 3rd edition (has to be third or greater), by Douglas, McDaniel, and Alexander. Does that make sense?
@saoudjutt253
@saoudjutt253 Ай бұрын
@lseinjr1 Dear Professor, thank you for clearing my query regarding the contribution of s1 orbital under the E representation.
@merricchristraj3151
@merricchristraj3151 Ай бұрын
thanks
@alireza-df1gz
@alireza-df1gz Ай бұрын
Nice
@jaidenl5597
@jaidenl5597 Ай бұрын
Great video thanks!
@HeyKevinYT
@HeyKevinYT Ай бұрын
Do people split the core orbitals into different parts like in the valence orbitals?
@lseinjr1
@lseinjr1 Ай бұрын
No, not usually. They DO tend to model the core orbitals with six (6) Gaussians, whereas in split valence orbitals, each orbital function is modeled by one (1) to three (3) Gaussians.
@HeyKevinYT
@HeyKevinYT Ай бұрын
Thanks for the explanation. When I heard it in my VASP lecture yesterday, the nomenclature seemed very cryptic. Now it's clear to me.
@danielc.martin
@danielc.martin 2 ай бұрын
Great!
@ShornaBrown
@ShornaBrown 2 ай бұрын
@KSI
@joshuakay5917
@joshuakay5917 2 ай бұрын
Very clear and concise, appreciate the video a lot 🙏🏾
@lseinjr1
@lseinjr1 2 ай бұрын
Glad it was helpful!
@louisdown6912
@louisdown6912 2 ай бұрын
super helpful video, excellently explained
@lseinjr1
@lseinjr1 2 ай бұрын
Glad it was helpful!
@viragoth_fr
@viragoth_fr 2 ай бұрын
Thx from France ! I'm searching for a good explication of these kind of basis set and this video give me all I wanted !
@charmy3021
@charmy3021 2 ай бұрын
It's me again. Last year you've saved me from physical chemistry. Now I think your videos will help me get through Inorganic Chemistry. Thanks a lot Sir!
@lseinjr1
@lseinjr1 2 ай бұрын
I'm glad I could help!
@panyakorntaweechat8586
@panyakorntaweechat8586 2 ай бұрын
Can we prove the 3rd Hund's rule by using this equation.
@lseinjr1
@lseinjr1 Ай бұрын
No. This equation (in the video) is for a very special case.
@ghauri3502
@ghauri3502 2 ай бұрын
how to find number of extraction (n) from this formula?
@lseinjr1
@lseinjr1 Ай бұрын
The number of extractions will be a given, for the given situation.
@haddouabdelghani6911
@haddouabdelghani6911 2 ай бұрын
Hello professor , I hope you are doing well !
@luch7778
@luch7778 3 ай бұрын
my calculus is so rough and this brought everything back for me. Thank you
@youdontwannaknow5813
@youdontwannaknow5813 3 ай бұрын
Thank you for explaining this I was having a hard time with this topic in quantum chem
@PBeigi
@PBeigi 3 ай бұрын
very impressive tutorial. thanks
@dave_strings_8880
@dave_strings_8880 3 ай бұрын
Thank you Iseinjr are you gonna review any of their other albums ?
@charmy3021
@charmy3021 3 ай бұрын
Hello Professor! Thanks for this video. It helped me solved a specific book exercise that has been bothering me for days now. Thanks for the help! Happy World Teacher's Month!😁🏆🎉
@kazuyamishima1713
@kazuyamishima1713 4 ай бұрын
Thank you so much. This video helped a lot!!❤
@MatheusPereiraSales-m4o
@MatheusPereiraSales-m4o 4 ай бұрын
Great video. Later, can you solve this same problem, but using Kim's method? I'm trying it on my own, but I'm not able to choose with basis function to use, as the c3v character table presents all linear, quadratic and cubic functions for the irreducible representations. Take A1 for instance irrep linear quadratic cubic A1 z x^2 -+y^2, z^2 z^3, x(x^2 - 3y^2), z(x^2 + y^2) Depending on which function I chose, I get differenct orbital coefficient values
@lseinjr1
@lseinjr1 3 ай бұрын
There's a very useful trick for A1 in any point group. Since it is totally symmetric, we can always use the basis function "1". Multiply each atomic orbital by "1", then add. So for molecular group orbitals the A1 is immediately (s1 + s2 +s3), unnornalized, where s1, s2, s3 are the H atomic 1s orbitals on hydrogens 1, 2, and 3, respectively. It is completely legitimate. Does this make sense?
@MatheusPereiraSales-m4o
@MatheusPereiraSales-m4o 2 ай бұрын
@@lseinjr1 Thank you very much for your response, it made complete sense. Eventually I managed to solve this problem, but I had to redraw my coordinates system. I tried to make more or less a "3D" system, just like the methane video. Some time later, I redrawed it to a simple 2D case, with the NH3 lone pair ponting outside the notebook's plane. I'll try to solve it on a 3D coordinates system later on
@muhammadzain2838
@muhammadzain2838 4 ай бұрын
Can you please show ,how did you reduce the dieterici equation
@EffigyOfficial
@EffigyOfficial 4 ай бұрын
The way people use B is genuinely the most frustrating part of physical chemistry to me. Maybe this isn't confusing to people taking an in person class but I've been self learning the course over summer and its tripping me up all the time. My formula sheet says E_J = (J(J+1)*h_bar^2)/(2*I) just like you wrote on the whiteboard but my formula sheet says that it equals hcBJ(J+1). If you do a unit alaysis for this B, you'll find that it has the units m^-1 which is the same unit you're using but saying that E=BJ*(J+1). What's going on here? I also did a unit alysis for (J(J+1)*h_bar^2)=(2*I) and I confirmed that it's in Joules. This begs the quesiton how you could possibly be writing E_J = (J(J+1)*h_bar^2)/(2*I)=BJ*(J+1). If you're using B in m^-1, this is simply wrong. J is just an integer so you're just going to get another value for m^-1 if you use BJ*(J+1). (J(J+1)*h_bar^2)/(2*I) gives you joules.
@saraguedes7632
@saraguedes7632 4 ай бұрын
Hey, can you do a 3/2 reaction?
@alessandrac1940
@alessandrac1940 4 ай бұрын
Thanks so much. This vid singlehandedly saved my life. Just a question though... if this was an electrochemical cell, wouldn't E standard have to be positive? Cause it is negative in this example.
@deraldjtuckerii
@deraldjtuckerii 4 ай бұрын
Thanks for this video! I re-opened an Atkins and Friedman text after many years and tried a problem based on this concept. What I found is an expression for Lamba(max)T = (ehc)/(5k) and when I calculate the value, it differs from the text by less than a factor of 3. I found my answer by taking the ln of both sides and I was able to cancel the constant/lambda terms. Your video helps me understand the assumption that the wavelength is very short, reducing the exponential term to 0.
@mariyappillaiv5262
@mariyappillaiv5262 5 ай бұрын
Tq sir kindly send Rigid Rotor-wave equation and solution
@chimeziefavour3697
@chimeziefavour3697 5 ай бұрын
You used 20⁰c and you didn't add it to 293.15K to convert it
@rayano97
@rayano97 5 ай бұрын
Thank you so much ❤
@zk33m
@zk33m 5 ай бұрын
6 years ago and ure still helping students. thank you so much
@muthiahpillaipalanichamy3939
@muthiahpillaipalanichamy3939 5 ай бұрын
good. Thank you
@atharvasharma384
@atharvasharma384 5 ай бұрын
Sir how many plane of symmetry will be there in phenanthrene
@lseinjr1
@lseinjr1 5 ай бұрын
Two (2). It has symmetry group C2v.
@BKsperspective
@BKsperspective 6 ай бұрын
thank you this makes so much sense!
@Heisenberg-210
@Heisenberg-210 6 ай бұрын
Thank you so much sir! Love your teach style, not so fast!
@lseinjr1
@lseinjr1 6 ай бұрын
Glad to hear that!
@york3538
@york3538 7 ай бұрын
Thank you so much! I was struggling so much with this kind of problem! 😁
@lseinjr1
@lseinjr1 6 ай бұрын
Happy to help!
@umbraemilitos
@umbraemilitos 7 ай бұрын
I think by looking at the character table for C3V, we can find Gamma-Trace by adding A1 to E.
@starktony1780
@starktony1780 7 ай бұрын
thanks man
@lseinjr1
@lseinjr1 7 ай бұрын
Happy to help
@happyfrezar2813
@happyfrezar2813 7 ай бұрын
Thank you so so much!❤