hakim bi maza aroo

Great message

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Ayy Maa yarr. Kichaa sheli renian❤😂

Alhumdulilah bo jaam 🤲

Bo sheeli bo jam

youtube.com/@bethenorth6492

We love to wait for your next vedios plzz

Pochi breyam lkn kehlkiyo kwt de no horem has d Sahi 😂😂😂😂😂😂😂

Fun I I I I I I yup that's what I'm thinking too thanks for letting me know what your plans to 😊

Good morning and Packers draft of Ii men in I y u us too I only have a you up for a while I think you up I use to get uuuiyuyy I think is uui7yu it was a you up to today I really don't want to do anything else to do it up yet you uu😅

Tuytutyyttutre you up to your your system fast ❤

Yu to 5ryrufyigogihiuhuf

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Great❤

Bo jm❤

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Hhhhh nice video i like it

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Bo jam 🎉🎉🎉🎉

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Hahaha Bo jm lkn Audio quality bo khrb

Bo sheeli 🎉🎉🎉🎉🎉🎉

😂😂😂😂😂😂😂that ws funny 🤣🤣🤣🤣🤣🤣🤣🤣

Bo sheli video mza arer

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Tan content angyor la wexen tan Facebook horo restam 😂

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Hahaha 😂.

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Hahaahahahha bo maza arer Mujaddid sir and team 👍👍

Really that was funny😂😂 doing well sheali chitrar

- The room is a rectangular box with dimensions 6m x 6m x 2m (height) - The window is 1m x 2m, and when opened, it allows air to enter the room with a speed of 10m/s - The train's speed is 100 km/h, which is approximately 27.78 m/s (we'll use this value to calculate the air flow rate) - The room is initially at a higher temperature than the outside air - We want to cool down the room to a comfortable temperature (let's assume a 10°C drop) Calculations: 1. Air flow rate: The window's area is 1m x 2m = 2m². With an air speed of 10m/s, the air flow rate (Q) can be calculated as: Q = A x V = 2m² x 10m/s = 20m³/s Since the train is moving at 27.78 m/s, we need to consider the relative air speed. Let's assume the air enters the room at an angle, so the effective air speed is the vector sum of the train's speed and the air speed: Ve = √(V_train² + V_air²) = √(27.78² + 10²) ≈ 30.14 m/s Now, we can calculate the air flow rate considering the train's speed: Q_e = A x Ve = 2m² x 30.14 m/s ≈ 60.28 m³/s 1. Room volume: The room's volume (V_room) is: V_room = 6m x 6m x 2m = 72m³ 1. Cooling time: To estimate the cooling time, we'll use the concept of heat transfer and the air flow rate. Let's assume the room's initial temperature is 30°C, and we want to cool it down to 20°C. The heat transfer rate (Q_heat) can be approximated as: Q_heat ≈ ρ x Cp x V_room x ΔT where ρ is the air density (approximately 1.2 kg/m³), Cp is the specific heat capacity of air (approximately 1005 J/kg°C), and ΔT is the temperature difference (10°C). Q_heat ≈ 1.2 kg/m³ x 1005 J/kg°C x 72m³ x 10°C ≈ 8640 J/s Now, we can estimate the cooling time (t_cooling) by dividing the heat transfer rate by the air flow rate and the temperature difference: t_cooling ≈ Q_heat / (Q_e x ΔT) ≈ 8640 J/s / (60.28 m³/s x 10°C) ≈ 143.5 seconds Therefore, it will take approximately 143.5 seconds (or around 2.4 minutes) to cool down the room by 10°C, assuming the window is open and the air flows in at the calculated rate. 🤣🤣🤣🤣🤣🤣 generated by Ai

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