Is there also any theoretical explanation why this is working? Could be interesting. And have you some proof how much faster it is than clasical method?

nice bro

X = 2,16 4^2,16 =19,973 19,973 ≈ 20

X = 2,75

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Wrong

When we do R3->R3-3R1 then last element of R3 should be -11/2

Sorry ... In my previous comment, i typed the answer wrong...the answer is *4804604*

Thank you

n=4

But in Calculator answer is something else ?

X = +-7

25x = 250 x = log 250 / log 25 x = 1.71534 25^1.71534 = 250

x=log250/log25=(log25+log10)/log25=1+1/2log5 x≈1+1/(2×0.699)≈1199/699≈1.71532 Deviation is about 0.00003 25^1.71532≈249.985

x=log180/log6=(2log6+log5)/log6=2+log5/(log2+log3) x≈2+0.699/(0.301+0.477)≈2255/778≈2.898 Deviation is about 0.0002 6^2.898≈179.92

You can simplify it further by doing: 4^x = 16 * 3 Taking log base 4 on both sides, x = log4(16*3) x=log4(16) + log4(3) x=2+log4(3) You can do it with the answer you found aswell by seeing that 1+log4(12) = 1+log4(4*3) = 1+log4(4)+log4(3) = 2+log4(3)

GOODBYE

I think you should have explained in more detail the following: 5*√3*i × (-5)*√3*i = (-25)*(+3)*(-1) = (-75)*(-1) = +75 ✓

x=2?

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x=log50/2log5=(log5+log10)/2log5≈(0.7+1)/(2×0.7)≈17/14≈1.214. Deviation is about 0.001.

Mai class 10 ke student ho fbise board sai and Menai thumnail daikh kr question solve kiya and ans check krnai kai liai ap ke video daikhe or mera answer sai hai. yai tricky problem hai? 🤔9th and 10th ke math per yai concept he to pera hai.

15×256²=983040.

x=log15/log3=(log3+log5)/log3≈(0.48+0.7)/0.48≈59/24≈2.4583. Deviation of only 0.0066.

Firstly, you should not write "log" without giving any base. Many people write "log()" intending base 10 (Caution: other people intend base e then, which is "ln()" !), but they should write "log_10_()" or just "lg()" instead. Secondly, it is more straightforward to use the base 4 for the logarithm, as the exponential equation has base 4, too: 4^x = 48 x = log_4_(48) x = 2.79248... In this form, you can type in into many modern calculators to get the numerical value of the solution x. However, if you want to simplify this, you can write = log_4_(16 * 3) = log_4_(16) + log_4_(3) = log_4_(4^2) + log_4_(3) = 2 + log_4_(3) If you want to transform it to base 10, which I write lg(), you can use the base converting rule: log_4_(...) = lg(...) / lg(4) In this case x = 2 + log_4_(3) = 2 + lg(3)/lg(4) which is equal to = 1 + log_4_(12) given in the video. Instead of lg(), you can also use ln() in the numerator and denominator of these fractions. It doesn't really matter which base you use. The reason for using lg or ln is that many older or weaker calculators offer only one type of logarithm to a fixed base, namely 10 or e. But as I said, better calculators usually offer a general "log" key, which allows to set an arbitrary (positive) base, like 4 in this case, so you don't need the base converting rule anymore.

x=log48/log4=(log6+log8)/log4≈(0,78+0,9)/0,6≈1,68/0,6≈14/5. Absulute error is about 0,0075.

x^2/36=36/x^2 => x^2/36 = 1/ x^2/36 /*(x^2/36) => x^4/36^2 = 1 => x^4=36^2 => x^2=36 => x=6

Oh😢

As x^2/36=x^2/36 X^2/x^2= 36/36 X^4 = 1296 (36x36) X = 4√1296 = 144

X is 144

This in an exercise on how to make a simple sum complicated! Consider 8^8=(((8^2)^2)^2=(64^2)^2=4,096^2=16,777,216. So 8^8-88=16,777,128. The multiplication involved is trivial.

Hello? I have used your thumbnail a little bit. Would you mind if I ask could you see my solution way please? :)

16^5 - 16^4 = 16^4 ( 16 - 1 ) 16 ^4 (15)

Japanese Math Olympiad Question: √(x + 2) + √(x - 4) = 6; x =? 6 > √(x + 2) > √(x - 4) > 0; Let: y = x - 1, x + 2 = y + 3, x - 4 = y - 3 √(x + 2) + √(x - 4) = √(y + 3) + √(y - 3) = 6, [√(y + 3) + √(y - 3)]² = 6² (y + 3) + 2√[(y + 3)(y - 3)] + (y - 3) = 36, √(y² - 9) = 18 - y, y² - 9 = (18 - y)² y² - 9 = y² - 36y + 18², 36y = 18² + 9, y = [9(36 + 1)]/36 = 37/4 = x - 1, x = 41/4 Answer check: √(x + 2) + √(x - 4) = 6 x = 41/4: √(41/4 + 2) + √(41/4 - 4) = √(49/4) + √(25/4) = 7/2 + 5/2 = 6; Confirmed Final answer: x = 41/4 = 10.25

What was the shortcut promise in description of video?

(15)16^4 = (15) 2^16 = (15)(1024)(64) = (30)(512)(64) = (15360)(60+4) = 921600+61440 = 983040

much easier way is not this way.

❤

If everyone at the Olympics were as fast as you, the world record for 100 meters would be at 3 h 15 min and 29 sec.

x^4 = 4^4 x^2 = +/- 16 x = +/- 4, +/- 4i

Man, you just do complex 4th root from 4^4 ... that is a one-liner...

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5^(х-2)=5^2 X-2=2 X=4

Cut the BS. Factor 4^x out without using the fancy 2-1

1) Factor out √5 top and bottom and cancel leaving (√6+1)/(√6-1) 2) Rationalize the denominator

Since the cube of m is bigger than its square when |m| > 1, a real root will be where |m|^3 is a bit less than 150. That suggests |m| = 5. Then m^2 - m^3 = 25 - (-125) = 150, making m = -5. We can now factorise m^3 - m^2 + 150 = 0 because (m + 5) is a factor. So let (m + 5)(m^2 + Am + 30) be the factorisation, then we can see that A = -6 makes the coefficient of m equal to 0. Solve m^2 - 6m + 30 with the quadratic formula x = -(b/2) ± √( (b/2)^2 - ac) = 3 ± √(9 - 30) = 3 ± i√21

brilliant video g

Answering without watching the video Quite a simple question with a little trick to it. Took less tha a min to solve with pure metal calculation Ans: -5