What about f(x)= x^2, if x < 0 0, if x ≥ 0? It has an inflection point at x = 0 according to your definition. Did you intend this? You didn't show functions like this in your video.
@sankalps.97756 ай бұрын
Thanks so much!
@sumittete28047 ай бұрын
Hello Chris...at 18:08 , is it sufficient to conclude that if f is defined on an interval then accumulation function of f is an anti-derivative of f ? But for instance, if signum function is defined on an interval [-1, 1] then accumulation function is not an anti-derivative of signum function as accumulation function here is not differentiable on (-1, 1).
@Carol-vj2dw7 ай бұрын
Bravo!
@rkumaresh7 ай бұрын
Polar coordinates are hard to understand and this video was simple to learn the basics. @8:37 when the arctan(2/5) is 0.381 which lies in the range of inverse tan i.e -pi/2 to pi/2 why would we have to go back and add pi to that.
@carrollmartin14658 ай бұрын
Probably it's a good explanation
@nas-cf1wy9 ай бұрын
3:00 This formulation method is a genius. I salute you, brother.
@mikeups9 ай бұрын
ok so just do it with a given area A, or I suppose conversely a volume V
@onlinecalctutor196810 ай бұрын
Thanks so much for this video! Do you happen to know which definition for inflection point is used by the College Board for the questions on the AP Calculus exams? I looked in the AP Calculus Course and Exam Description and it didn't seem to say explicitly.
@enrobotics11 ай бұрын
This is the simplest to understand. I love this🎉❤
@juromebey192211 ай бұрын
255 degrees should be 4pi/3 radians on your unit circle 1:13
@abdulhamedeid93511 ай бұрын
how do you make your presentations
@kevinscheengsbier6130 Жыл бұрын
Awesome
@jasonbraverman8974 Жыл бұрын
The aluminum on the tops and bottoms of soda cans are twice as thick as the sides. If you change your equation so that the surface area =(4*Pi*R^2)+(2*R*H) to represent using twice the aluminum on the tops and bottoms, then you'll get the right answer. The radius (cube root of 355/4pi) is 3.046 cm, making the height 12.18. Much closer to the 2.7cm - 3.3cm range for the radius and 12.3cm height.
@graviton2222 Жыл бұрын
Thanks ..the best and the more explicit video on how Euler did resolve this problem...you are awesome Odden
@heathrobertson2405 Жыл бұрын
Very helpful thank you sir
@YourNameHere1000 Жыл бұрын
Very helpful, thank you.
@TheCheech0203 Жыл бұрын
Absolute chad video I will get an A in physics 2 literally because I can do this stuff in excel now thank you king
@spdas5942 Жыл бұрын
Best approach ever seen ! Nice job.
@pauselab5569 Жыл бұрын
this is a great explanation. super simple, useful and not too technical
@holyshit922 Жыл бұрын
And we can generalize it for all positive and even arguments of zeta
@garymartin9777 Жыл бұрын
Now an introduction to polar bear coordinates. Wherever there's a polar bear, my butt is vectoring with great magnitude pi radians relative to it.
@sumitsana6170 Жыл бұрын
If we take open interval (a,b) what will be the problem
@iCrAzYghost Жыл бұрын
I don’t understand why you didn’t just take the integral?
@AR-sy2rk Жыл бұрын
Straight up😂😂
@mattkriese7170 Жыл бұрын
Excellent explanation and visuals. I find myself lost in the text definitions constantly. Supplementing and having a way to visualize what is being stated is integral to my understanding. I appreciate your work 🙏🏻
@michaelvance2293 Жыл бұрын
A little late to the party but consider making a cost function using the surface area (i.e. the aluminum costs some value per square cm). If every part of the can costs the same amount nothing changes (besides maybe a scalar). However, it seems reasonable that the top and bottom material would want to be thicker and say, twice as expensive. This new cost function actually does optimize to something very close to a standard soda can (and of course companies want to optimize cost!).
@andrewphilip3308 Жыл бұрын
Thank you very much. Just what I needed to know. These proofs evoke a peculiar and wholesome inner ecstasy. (enstasy ?)
why is double derivative positive for concave upwards?
@ranjan5865 Жыл бұрын
Very helpful 👍🏼 and we'll explained
@theri1473 Жыл бұрын
why did you particularly use the cubic function and not choose the quadratic function that forms the area that is rotated?
@cosquncafar Жыл бұрын
Awesome explanation, thanksss for sharing. Could you tell the tool which u use to prepare the graphical representations?
@angelaniu5908 Жыл бұрын
Thank you so much sir! This helped a lot :)
@DrMcCrady Жыл бұрын
Great videos, they will be handy next time I teach calc 1 or 2. Thank you for making them! Also, do you mind sharing what you used to make your slides and animations?
@jimcar53 Жыл бұрын
you're an amazing teacher. I learnt a heap from this video.
@elfaidii2 жыл бұрын
Amazing video!
@tasninnewaz67902 жыл бұрын
ok, subscribed.
@ltcdrake19852 жыл бұрын
Umm.... your endpoint conjecture is absolutely wrong. If end-points are included in the domain of the function and they have a defined value, then they should absolutely be considered for possible global extrema. If an endpoint value is higher (or lower) than all other values, why wouldn't it be a global extrema? Endpoints cannot be relative extrema (by definition), but global extrema may occur at relative extrema and defined end-points. If you do not check defined endpoints for global extrema on any AP Calculus exam or any Calculus entrance exam for any college/university, you will get the problem wrong.
@nightowl42942 жыл бұрын
@WindTechInsights2 жыл бұрын
introducing the r/h ration would lead to the same result much easier... in regards of why manufacturer do not follow this rule, it is not only it looks "bigger", but it also the dimater an avarage hand can hold... it would take just some educative facebook campaig to explain that actually the best shape is when the 2r/h ratio is equal to 1...it could save million tons of wasted material
@navjotsingh22512 жыл бұрын
This is awesome, you are the calculus god. I will worship you and start a new calculus religion 😅
@camerongrenier54052 жыл бұрын
Best video ive seen on this topic!! could you make one on interpolation??
@ptyptypty32 жыл бұрын
Hi Chris... I have seen about 10 videos on this Law of Cooling... and there were some very good ones.. BUT... Your Video here is the BEST by far!! Thank you for your complete Presentation of all aspects of this Topic.. Amazing!! I am a Subscriber!!