Vishwanath Nagaraj

Пікірлер

@MartandPuri 16 күн бұрын

Sir I first time viewer I confused with terms 'medial '

@vishwanathnagaraj1592 16 күн бұрын

It would be better if you start from the 1st proposition of book 10. Most of these terms have been covered in previous propositions.

@punditgi 2 ай бұрын

Vishwanath Nagaraj, can you add the link to the download site for your notes in the Description of this video? I am not able to see the link in the video. Thank you! 😃

@vishwanathnagaraj1592 2 ай бұрын

Done Sir. Sorry about that.

@punditgi 2 ай бұрын

@@vishwanathnagaraj1592 Perfect! Thanks again. 😇

@punditgi 2 ай бұрын

Many thanks for your notes! 🎉😊

@JamesRoolvink 3 ай бұрын

Why not draw a line between B and D? Is that production of a proof less efficient? How to define less efficiency? Using less steps and/or less propositions? P.S. Where is the proof of prop. 42? P.P.S. Great video's!!!

@vishwanathnagaraj1592 3 ай бұрын

Hi James, We could have joined B and D rather than A and C. The steps in the proof would have been the same. In that case, the triangle BDC would have been equal to the triangle BEC since these triangles are also on the same base and between same parallel lines. The proof would not have been any more or less efficient. I believe that it not the number of propositions or steps that define efficiency but the ease of understanding. In any case, since we are looking at Euclid's Elements, I am being as faithful to his choices in developing the proof. Thank you for pointing out the missing Proposition 42. Can't figure out how I missed it. By the way, have you had a look at the Book. Any comments on that would be much appreciated. Thanks for the appreciation and feedback.

@vishwanathnagaraj1592 3 ай бұрын

Hi again, Just browsed through the playlist of Book 1. Euclid's Book 1 - Proposition 42 is there.

@fernandodaneri2611 6 ай бұрын

Thanks!

@timhochstetler 7 ай бұрын

if fb and fc are on the same point where b=c then fb=fc

@vishwanathnagaraj1592 7 ай бұрын

True, but the definition of a circle says that on a circle all the points are equidistant from the center. So we are choosing two points - point of contact and an arbitrary point somewhere else for comparison. In any case, remember the center is the assumed center. If we take the actual center, FE and FB will not be equal at any point since the centers of the two circles are not the same.

@aa-gc3fg 7 ай бұрын

Sir how it becomes (1+y)^n= n instead of (1+y)^n =x

@vishwanathnagaraj1592 7 ай бұрын

Yes Sir, you are absolutely right. Follow the steps by incorporating the change and you should be able to arrive at the limit as n goes to infinity. Thank you for identifying the error. You should end up with p < sqrt(2x / (n(n-1)) which will tend to 0 as n goes to infinity.

@punditgi 7 ай бұрын

Many thanks for your book! 😊

@punditgi 8 ай бұрын

Excellent videos! 😊

@vishwanathnagaraj1592 8 ай бұрын

Long time!

@jyothis8630 8 ай бұрын

Interesting

@jyothis8630 8 ай бұрын

Good

@jyothis8630 8 ай бұрын

Good

@jyothis8630 8 ай бұрын

Super

@bushrathabassumshaik0616 8 ай бұрын

thanks alot sir understood it better now

@echooscar5241 8 ай бұрын

Very nice video! Which program did you use to make the diagrams?

@vishwanathnagaraj1592 8 ай бұрын

GeoGebra.org

@TheThinkingMathematician 9 ай бұрын

great video

@singingkakida4945 9 ай бұрын

Sir I have searched many video but after scrolling many video I got yours ..no one explain so clearly like you..thnku sir .I will play this vdo to my class room

@vishwanathnagaraj1592 9 ай бұрын

You are most Welcome. 🙏

@sharmaproductions9459 9 ай бұрын

Namaste sir! Could you please update the link of the excel sheet. Currently there is an error when i try to download the excel sheet.

@vishwanathnagaraj1592 9 ай бұрын

Kindly goto About page in which the working link is there.

@detectiveandspynovels7140 9 ай бұрын

One of the best video.♥️♥️♥️♥️♥️♥️♥️

@avarts4432 10 ай бұрын

Well explained:),thanks

@maleksalih5237 11 ай бұрын

Wonderful

@punditgi 11 ай бұрын

Many thanks for this book! 😊

@punditgi 11 ай бұрын

Namaste-ji! Donnyavad. 😊