Firstly, thank you for providing such high quality material for free. Lastly, I think at 6:30 you meant to say that there sat vaps that have higher enthalpy than the critical point (not sat liqs), right?
@KgothatsoMoabelo17 күн бұрын
How did methane get into the room, Professor?😅
@rdrageteaeugic24 күн бұрын
helped a lot, internet opensource is the best thing, thank you for your work!
@ngaithang9924 күн бұрын
This is very confusing. I tried to find By using CEB, but that doesn't give you the correct By. Is there a specific order you have to work this problem out in? And if so, why is that?
@yosoyanita100628 күн бұрын
how can we get entropy on state 4?
@still-learning-the-basicsАй бұрын
What am I missing if I'm doing the Moment between A & B? The equation would be A*24in = B*24 in +200 lb *18 in . So that would make A - B = invalid which does not make sense to me.
@itsyogurt92472 ай бұрын
Hello, Ive been confused sometimes about the feedwater exits. Is its enthalpy always equal to the sat. Liq of the extracted steam? When using the pump method, i noticed it is not, assuming the given state when both extracted and feedwater mixed
@TheCheech02032 ай бұрын
Great video Dr. Mantufel! Thank you!
@Vyantri2 ай бұрын
I have written out the solution myself, but when I tried to post the Drive link here KZbin keeps shadowbanning this comment. For now I will just leave my explanation of how I got equation of the line and how to express r as a function of Z. The part about getting r(z) might confuse some people. It certainly confused me at first. I did not use the method explained in this video. My approach was slightly different. What I had done as seen on my solution, is that I drew a 2D projection view of the Y and Z axes as shown in the question's diagram. The outer edge of the cone (highlighted in green on my solution) was considered to be a line within the set coordinate system and the equation for this line was determined. We can see that the green line is going down (as you go from left to right) therefore its gradient is negative. We can also see that the line intercepts the vertical axis (in this case the Z axis) at h, therefore the y-intercept is h. It intercepts the horizontal axis at "a" and therefore the gradient of the line can be determined. It is rise over run and since we know that the lengths of "h" and "a" are the "rise" and the "run" respectively, the gradient of the line is -h/a. The full equation of the line is Z=-h/a*y+h The trick now is understanding that Z is our variable that we need to integrate with respect to, as our infinitesimal element has a dZ in it. That immediately gives us a clue that we have to somehow somewhere integrate with respect to Z. We also need to be cognizant of the fact that the quantity "r" which is the radius of the infinitesimal element, is a CHANGING quantity. It's not a constant as the infinitesimal element (the small quarter cone slice indicated on the diagram) can be placed anywhere in the whole quarter cone so the r value can be higher or lower. This tells us that "r" is a VARIABLE and therefore we cannot treat it as a constant (generally you can pull constants outside the integral when solving but you can never do that with variables). We will have to integrate with respect to "r" either directly or indirectly. As previously mentioned, we have a dZ as our infinitesimal element's height, so immediately this tells us that we have to find some way to represent the quantity r as a function of Z. Once we do that, the hardest part of the problem is solved. If you look at the 2D sketch I drew, "r" in that 2D sketch would essentially be horizontal lines that start from the Z axis and end at the actual line (determined by the equation above). The LENGTH of those horizontal lines (r) is given by the y value of the green line. This would essentially mean that the "r" quantity can be expressed as equivalent to y in the function of the straight line. Essentially all that means is that you take the equation above, and you make y the subject of the formula and then you can simply call "y" r(z) because that function now describes the length of r as it changes with respect to Z or the Z axis (so as the infinitesimal element moves up and down). Finally that would leave us with r(z) = a[1-(z/h)] And this equation does satisfy the common sense checks outlined in this video. When Z=h then r must be 0. When Z=0 then r must be a. From there the question is pretty easy but expressing r as a function of Z allows us to integrate r (which is a CHANGING quantity) indirectly with respect to Z. Generally that's how you're supposed broadly think when doing applied maths problems like this.
@Sadlyn3 ай бұрын
This make this realistic than i was thought in class. Thanks man
@afshinghiasvand4 ай бұрын
Thank you very much.
@AdolfKambinda-f8p4 ай бұрын
Can this equation work for the center of mass
@matthewperez8304 ай бұрын
Thank you so much Manteufel! You were my thermodynamics professor in college and your lectures are great. Had to brush up on this chart and this really helped.
@Chignlak4 ай бұрын
I seriously cannot commend you enough. Clear and concise. I wish I had found you at the start of the semester. Thank you.
@suheladesilva29335 ай бұрын
Great video, thanks very much. Seriously, this video should appear higher on the recommended list.
@darrellnathan48125 ай бұрын
Where can i get the excel sheets for the calculation? Thank you
@adityakapilesh90915 ай бұрын
You're a legend man
@silentt15435 ай бұрын
Thank you very much sir
@pierreolivierlevesque12795 ай бұрын
i have a problem right after adding the add-ins thermodynamic where it brings me to the VBA windows and the ThisWorkbook.VBProject.HelpFile = ThisWorkbook.Path & "\ThermoTablesHelp.chm" is in yellow. what can i do ?
@JamesVestal-dz5qm5 ай бұрын
I got full credit for this in transport phenomena 2. It still makes me angry that peter is a tubby boy whose wife is angry at him and hes teaching our class. Peter should stop lecturing about what we know from undergraduate and start teaching the students he has today. If peter were smart with words he would stop calling the equations animals. When peter talks about the power of words, i think about calculating the power in kcals stored in his body fat. Peter sweats when he takes a lot of steps. Maybe peter should build an excel spreadsheet to track his daily caloric intake.
@NexiOHome5 ай бұрын
you lack an explanation: "because we have more nitrogen" why? you dont explain why we have "more" nitrogen. "then we need to fix the nitrogen" I wonder what your class avg is? probably one of those teachers that have to use a bell curve to prevent the class from failing. P.S. if you are one of those teachers who implements a curve in the class because class performance is poor, newsflash is not because your students are dumb. Its because you teach poorly.
@aymanshabaka34026 ай бұрын
hi, thanks for the nice video. can you send me the add in?
@rishibhawsar6856 ай бұрын
Thanks 😊, Really helped
@rasraster6 ай бұрын
Why would air heat up in uniform fashion when the delta T with the refrigerant varies so much? Doesn't make sense.
@randallmanteufel64116 ай бұрын
x-axis is fraction of heat transfer. Specific heat of air is constant over temp range from T_in to T_out. If cp was highly dependent on T, then would not be straight line.
@gustavomarcelo72506 ай бұрын
How can 2 to 3 is constant pressure when we add the heat? Shouldnt it be the reverse where pressure increae with the increae of heat?
@ashtonbyrd41906 ай бұрын
love you
@wh00lio6 ай бұрын
gay
@ildarakhmadullin99736 ай бұрын
Thank you, Dr.Manteufel. First I was your student back in UTSA and learned Heat Transfer. Now, I am teaching Heat transfer at North Park University Chicago, IL.
@randallmanteufel64116 ай бұрын
Ildar, glad you are doing well and teaching heat transfer!
@dimbanimvula36726 ай бұрын
Thank you so much professor
@Karl.Kreuzberg7 ай бұрын
THANK YOUUUUU !!!! Litteraly discovering the software the evening before my exam Your saving my ass (maybe)
@RyanThomson-c7c7 ай бұрын
Well illustrated and to the point. It was difficult to find a good review of both y and x bar. Going in to take my FE next week and needed this refresher. Thank you
@Thezubtech7 ай бұрын
Many thanks! Good info.
@AndreaAlmaraz-v8k7 ай бұрын
Thank you (^^)/
@mehekghosh31107 ай бұрын
You explained it so well!! Thank you!!!
@harshmangukiya918 ай бұрын
super useful
@briandmontejovalencia59158 ай бұрын
33:01 Re= G(D)/miu
@Tullex28 ай бұрын
Do PVT have to equal zxy respectively? Or they can be anyone? I tried PVT as xyz, and I ended up getting R/V x R/P after partial differentiating
@ShadowSaga9 ай бұрын
why - i mean wh y the 3 is negative
@roosroos44799 ай бұрын
thank you sir
@jakovbilic45569 ай бұрын
Why is air temperature increasing lineary? This is not what I learnt about T-A (temperature-area) diagram
@hadeelali46409 ай бұрын
How we calculate x4 ?
@iyusless9 ай бұрын
goat
@abdelkader92eng7310 ай бұрын
هل من مصل على النبي محمد صل الله عليه وسلم وبارك الصلاة الإبراهيمية
@loganscott263610 ай бұрын
When i did this question i had to multiply the given mass by 9.81 to get the weight and that was how i got correct answers but your process was right otherwise but could be a different question type so idk
@ahmednaji906510 ай бұрын
friction for turbulent is not 0.316Re^0.25 BUT 0.316/Re^0.25, correct it???????