So easy

Very nice problem with very nice solution! ❤❤

The square of (-1) is (1), because ((-1) \times (-1) = 1). However, when we talk about (i), the imaginary unit, the situation is different. By definition, (i) is such that (i^2 = -1). By definition i^2 = −1

I also solve this question

in boolean algebra that would work just fine if x=y=1

Stupid solution for stupid question

I guess it's x=7.5 To solve the equation , you can combine like terms: 1. Combine and : 4x = 30 2. Divide both sides by 4 to isolate : x = \frac{30}{4} = 7.5 So, the solution is . X=7.5

Идиотизм! Зачем все это было нужно, если в конце все равно вычислили с помощью калькулятора первоначальное выражение!??

Is the D=(b^2)-4ac thing just to find out if the answer is a complex answer? Cause I was just taught to use the Quadratic Formula, which is what the x=[-b±SQRT(D)]/2a is.

Very nice problem! ❤❤

7 & 5, by inspection.

in wolframalpha, the result of 1^x=3 is "False", 1 power to anything except infinity is 1.

bc/ab = c/a = 2; c = 2a, ca = 300, =>a = sqrt(150), c = s* sqrt(150), b = 2/3 * sqrt(150), a+b+c = 11*sqrt(150) = 55*sqrt(6)

The handwriting is sending me 😤

Not a math olympiad problem.

B = 0 A = 100 c = 200

The method is hard and time consuming.

The method is hard and time consuming.

х=1,1508

what a click bait omg

1 to the fifth power equals 1 1-1 equals zero. also zero to the fifth power equals zero zero minus one is still zero so either will work. So much more simple than half an hour of inconclusive math.

(0.5)+(0.5)=1 (y ➖ 0.5x+0.5). (xy ➖ 1xy+1). .

Semua test itu tidak penting, hanya berhubungan masalah nama, dan wawasan, ilmunya sama saja

Well, let's see... x! / 6! = 7! x! = 6! * 7! x! = 2*3*4*5*6 * 2*3*4*5*6*7 x! = 2*2*3*3*4*4*5*5*6*6*7 We have duplicates for 2, 3, 4, 5, and 6. So let's take 2 and 4 and make 8: x! = 2*3*3*4*5*5*6*6*7*8 Now let's take 3 and 3 and make 9: x! = 2*4*5*5*6*6*7*8*9 Now let's decompose a 6 into 2 and 3: x! = 2*2*3*4*5*5*6*7*8*9 Now let's take 2 and 5 and make 10: x! = 2*3*4*5*6*7*8*9*10 And there we have it: x = 10. 10! / 6! = 7!. So let's see, it took maybe 2 minutes to type all that? I don't see how I could possibly stretch it out to 11 minutes.

Did not even take 2 minutes

Easy

2^x + x = 20 /2 "1^x = 1" 1 + x/2 = 10 x = 9*2 x = 18 ?

Very good!

Without W function you could have immediately have mentioned that this is an increasing and continuous function - estimate te value through Newton-Raphson. Don’t see the point of ‘solving’ when you need approximation anyways.

So easy, the answer is - 4. Took me 3 seconds.

Phi^12 😂😂😂

You dont know how to write )( 😂

Easier method: Step 1:3^x=30-x Step 2:log 3^x=log(30-x) Step 3:xlog3=log30/logx Step 4:xlogx=log(30-3) Step 5:xlogx=log27 Step 6:xlogx=log 3³ Step 7:xlogx=3log3 By comparison X=3 I am in grade 12 cbse

1 - 1 = 0 to easy

Yeh I had solve it correctly

It was way too easier by hit and trial 😕 As 30 is a small no. we can easily calculate value by putting random value to this x=3

4.0392

a times e**a does NOT equal a.

The simple approach. Substitute x=1/2+z and y=1/2-z into the second equation: (1/2+z)(1/2-z)=1 or z^2=-3/4. Thus, z=±i√3/2, x=(1±i√3)/2, and y=(1∓i√3)/2

You can using complex analysis method sir.

2а=с, 2b=3a, b=3a/2, ab=a*3a/2=100, a=√(200/3)

4

y = 1-x; insert in 2nd equation; x(1-x)=1 => x² - x + 1 = 0 ; standard formula yields x1,2 = 0.5 +/- 0.5 * SQRT(-3) = 0.5 +/- 0.5*i*SQRT(3) => y1,2 = 0,5 -/+ 0,5*I*SQRT(3)

This is why our University's have gone to s*** and they graduate not knowing the difference between s*** and shinola.

4080 = 4096-16 4096 = 2^12 16 = 2^4 n = 12; m = 4

Stupid solution

Да, пиндоская математика, это просто дно

Wtf is lambert w function? I've done bachelors in mathematics and never heard about it. You shouldve given at least some info regarding it or at least a short definition.

He manages to write L so that it is identical to e. That's very artistic! So L=e thus Ln e = e*n*e = n*e^2 = 1 and from there on...

Wow. Do we not all recognize that (1+ √5)/2 = φ? And do we not all know that φ^2 = 1+φ?