Basically, if any number of vowels are present, Alex is bound to win. Chris wins only if there are no vowels at all.

this is totally wrong. there aren't even any g or u irreps in the D3h character table.

If you know oxidation and reduction 50% chemistry is done. Whether organic or life or metals. Just something to do with oxygen.

Can you provide code for this?

Anyone got a better soluion for this?

bruhh c'mon

Wait, which textbook is this referencing? Also, great explanation!

Your code is wrong. Used Java passed all the test cases: public static int countTeams(int teamSize_1, int teamSize_2, int p) { // Write your code here int maxTeams = Math.min(p / teamSize_1, p / teamSize_2); int maxTeamSize = Math.max(teamSize_1,teamSize_2); int minTeamSize = Math.min(teamSize_1,teamSize_2); for (int i = maxTeams; i >= 0; i --) { if ( (p - i * maxTeamSize) % minTeamSize == 0) { return i + (p - i * maxTeamSize) / minTeamSize; } } return -1; }

This is the peak of human achievement.

Are you an AI?

bho here?

The link in the telegram plz

Where is the code

I mean the overlap isn't an issue necessarily if I'm first going through each column from 1 to 2024 and coloring the topmost 1000 squares in each column then the area I have left to work with is 1024 completely uncolored rows, from which I can effectively paint 1000 squares in any way I want since it won't matter. ultimately end up with 2024*1000 + 1024*1000 = 3,048,000 no?

Plz find minimum work done in shaking

from which book is this question from?

TY

hello sir, how do we solve for a p+ polysilicon device? expected to find Vtp and Φms flat band voltage is also not given. Determine the metal - semiconductor work function difference and the threshold voltage for a silicon MOS device at 𝑇 = 3 0 0 𝐾 for the following parameters: 𝑝 + polysilicon gate, 𝑁 𝑎 = 2 × 1 0 1 6 𝑐 𝑚 - 3 , 𝑡 𝑜 𝑥 = 8 𝑛 𝑚 = 8 0 Å , and 𝑄 𝑠 𝑠 ' = 2 × 1 0 1 0 𝑐 𝑚 - 2 .

what is the coincidence me working on this question today. great work!!!!

What's the answers

Thanks you saved me.

GG lifesaver!

It's wrong For parallel flow ○T1 = 220-10 = 210⁰c ○T2 = 115-75 = 40⁰c Now LMTD ....

can you give the c++ code for this problem?

fuck numerade for their paywall, thanks

Give the code file please.

Wrong answer

Please also provide the code

Bro can u send the code

Thanks for the explanation I Appreciate it

Thanks.

wheres the final code?

Someone was able to solve this in HackerRank?

This is completely wrong, DSQI values from 0 to 1

Utter bullshit

It's o(n*q) can't we reduce complexity

Thank you

Where is the code

Were you able to find the answer ?

Here's my attempt at solving this: (Python) ``` def get_freq(word): return {c: word.count(c) for c in set(word)} def get_minimal_moves(word): freq = get_freq(word) moves = 0 new_word = word while any(freq[c] > 1 for c in freq): sorted_freq = sorted(freq.items(), key=lambda x:x[1], reverse=True) c = sorted_freq[0][0] indices = [i for i, x in enumerate(new_word) if x == c] i = freq[c] // 2 index = indices[i] left, right = new_word[:index], new_word[index+1:] if c in left or c in right: new_l = left new_r = right if c in left: j = indices[i-1] new_l = left[:j] + left[j+1:] if c in right: j = indices[i+1] - index - 1 new_r = right[:j] + right[j+1:] new_word = new_l + c + new_r moves += 1 freq = get_freq(new_word) return moves ```

Thanks

Also provide the java code for this problem

Bhai shi se solve kro kya h questions kya h answer kya h explaination kuchh pta hi nhi chl rha hai

Good work.❤

Routine for searching 8x16 character font in bios memory and display 16 lines with "segment address + offset address", the byte of the memory location and the bits of the byte and then waiting for key press. Space bar = next 16 bytes, ESC = exit. Start batch file with segment + offset attached. Example: C:\MEMSPY.BAT C000 1A00 @echo off REM MEMSPY.BAT REM Display 16 bytes REM Need two parameter attached REM for segment and offset: like C000 1700 REM Space = next 16 bytes REM ESC = Exit echo a>tmp.deb echo mov ax,b800>>tmp.deb echo mov es,ax>>tmp.deb echo mov bx,%1>>tmp.deb echo mov si,%2>>tmp.deb echo cld>>tmp.deb echo mov ds,bx>>tmp.deb echo xor di,di>>tmp.deb echo mov ch,10>>tmp.deb REM --- Output segment address --- echo mov dx,bx>>tmp.deb echo call 0170>>tmp.deb echo mov al,3A>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb REM --- Output offset address --- echo mov dx,si>>tmp.deb echo call 0170>>tmp.deb echo add di,2>>tmp.deb REM --- Get byte from ds:si --- echo lodsb>>tmp.deb REM --- Output byte --- echo xor dx,dx>>tmp.deb echo mov ah,al>>tmp.deb echo mov dh,al>>tmp.deb echo mov cl,2>>tmp.deb echo call 0172>>tmp.deb echo add di,2>>tmp.deb REM --- Output bits --- echo mov dl,ah>>tmp.deb echo mov cl,8>>tmp.deb echo mov al,31>>tmp.deb echo rol dl,1>>tmp.deb echo test dl,1>>tmp.deb echo jnz 0141>>tmp.deb echo mov al,30>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb echo dec cl>>tmp.deb echo jnz 0136>>tmp.deb REM --- next row --- echo add di,76>>tmp.deb echo dec ch>>tmp.deb echo jnz 0112>>tmp.deb REM --- increase seg address + 64 kb --- echo cmp si,0>>tmp.deb echo jnz 0157>>tmp.deb echo add bx,1000>>tmp.deb REM --- get key from keyboard --- echo mov ah,0>>tmp.deb echo int 16>>tmp.deb echo cmp al, 1b>>tmp.deb echo jz 0187>>tmp.deb echo cmp al,20>>tmp.deb echo jz 010C>>tmp.deb echo jmp 0157>>tmp.deb REM -- Subroutine -- REM --- Output 4 hex ASCII --- echo org 0170>>tmp.deb echo mov cl,4>>tmp.deb echo rol dx,4>>tmp.deb echo mov al,dl>>tmp.deb echo and al,F>>tmp.deb echo cmp al,A>>tmp.deb echo jb 017F>>tmp.deb echo add al,7>>tmp.deb echo add al,30>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb echo dec cl>>tmp.deb echo jnz 0172>>tmp.deb echo ret>>tmp.deb REM echo.>>tmp.deb echo n MEMSPY.COM>>tmp.deb echo rcx>>tmp.deb echo 88>>tmp.deb echo wcs:100>>tmp.deb echo q>>tmp.deb debug<tmp.deb>DEB.INF del tmp.deb cls MEMSPY.COM del MEMSPY.COM

Step 5: decimal 16 is hexadecimal 10.....hexadecimal 16 is decimal 22

How to make a screenshot of the text screen and to reload the screen using two batch files and some internal Debug commands: n, r w, q and n, r, l, q and segment address, file name and file size. Test in 4 steps from DosBox command prompt: dir ScreS.bat Screen1.SAV cls ScreL.bat Screen1.SAV @echo off REM ScreS.bat filename REM Save text screen to file. echo n %1>tmp.deb echo rcx>>tmp.deb echo FA0>>tmp.deb echo rds>>tmp.deb echo B800>>tmp.deb echo wds:0>>tmp.deb echo q>>tmp.deb debug<tmp.deb>nul del tmp.deb @echo off REM ScreL.bat filename REM Load text screen from file. echo n %1>tmp.deb echo rcx>>tmp.deb echo FA0>>tmp.deb echo rds>>tmp.deb echo B800>>tmp.deb echo lds:0>>tmp.deb echo q>>tmp.deb debug<tmp.deb>nul del tmp.deb

These are internal Debug commands. All values are hexadecimal. I like to use a Debug version in DosBox that provide 16 bit and 32 bit instructions. DosBox emulates a PC with intel CPU 80386/80387.

we need answers not quwstions

*Promo sm* ✌️