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@GeraldHardy1729 2 сағат бұрын
Sir, could you please explain the Reynolds number, how it is calculated, and its impact on flow regimes in your next video on fluid mechanics?
@engradnanrasheedmechanical 2 сағат бұрын
Actually I am busy in so many activities that I am unable to make long videos. But I shall try my best
@owaistoru 4 сағат бұрын
are you online? i have one question, which is same like this, if you solve it, . and for your time I will for sure pay,
@owaistoru 4 сағат бұрын
but i need it urgently
@engradnanrasheedmechanical 3 сағат бұрын
Email me on [email protected]
@engradnanrasheedmechanical 3 сағат бұрын
Currently I am in meeting and if get time will look into it.
@owaistoru 3 сағат бұрын
@@engradnanrasheedmechanical I emailed you sir, I hope you have recieve it already
@engradnanrasheedmechanical 3 сағат бұрын
@owaistoru I shall check it when get free but it can not be done in emergency as I have many other things to do....
@BG-uf8kh 7 сағат бұрын
Another great vid professor 🎉
@engradnanrasheedmechanical 7 сағат бұрын
Thank you and these the problems that are not available on youtube nor explained in detail.
@BG-uf8kh 6 сағат бұрын
Literally nothing like it anywhere on KZbin @@engradnanrasheedmechanical
@ragnarlothbrok6324 7 сағат бұрын
Thanks professor. you are the man
@engradnanrasheedmechanical 7 сағат бұрын
You are welcome and kindly share the videos with your friends as well.
@dannypipewrench533 13 сағат бұрын
Thank you.
@engradnanrasheedmechanical 9 сағат бұрын
You are welcome 😊
@cyrusbajwa 17 сағат бұрын
Excellent Video, sir!
@engradnanrasheedmechanical 17 сағат бұрын
Thank you @cyrusbajwa
@harshans7712 Күн бұрын
Thank you sir, this video helped me a lot
@engradnanrasheedmechanical Күн бұрын
you are welcome 🙏
@JoshuaMcHale-oj8xy Күн бұрын
Hello there, When you are calculating for permanent strain you calculate .0078-(30E3/6.50E3) =.00318 When I calculate it I get -4.6075 I have tried to type this into my calculator multiple ways and even switched the denominator and numerator just to experiment with the numbers. How are you getting that value? Thinking about it, even just diving 30/6.50= 4.61, so I am not really following the calculations. Please help! thank you
@engradnanrasheedmechanical Күн бұрын
Ok I have found where the problem is. You can see that stress is 30 ksi which is 30 x 10^3 psi and E= 6.5 x 10 ^3 ksi which is equal to 6.5 x 10 ^ 6 psi so now (30 x 10^3 psi)/(6.5x10^6 psi) = 0.004615and then 0.0078- 0.004615 = 0.003185
@engradnanrasheedmechanical Күн бұрын
I hope it is clear now. Thank you for your interest in the video. Keep watching and learning and don't forget to share it with your friends as well.
@engradnanrasheedmechanical Күн бұрын
Did you get it ? kindly give me your feedback please.
@JoshuaMcHale-oj8xy 16 сағат бұрын
@@engradnanrasheedmechanical Thank you for getting back to me in such a timely manor, I do see that now. I appreciate you and really enjoy your videos. I am an engineering student currently taking mechanics of materials.
@engradnanrasheedmechanical 16 сағат бұрын
@JoshuaMcHale-oj8xy you are always welcome and kindly share my videos with your friends ❤ and if you find any difficulties do let me know. Ask questions and I shall be happy to reply
@kkb2687 Күн бұрын
your videos have been of immense help. please continue to do what you do. thank you
@engradnanrasheedmechanical Күн бұрын
Thank you for your valuable feedback 👍 and kindly share my video in your community and help me in getting maximum audiences of Engineering
@BG-uf8kh Күн бұрын
Another great one 🎉
@engradnanrasheedmechanical Күн бұрын
Thank you 😊 💓
@Asmijitshil24 2 күн бұрын
in shear force calculation sir why you don`t write the y^2?
@engradnanrasheedmechanical Күн бұрын
Where?
@Asmijitshil24 Күн бұрын
@@engradnanrasheedmechanicalat 12:53 during the calculation of Vf
@engradnanrasheedmechanical Күн бұрын
@arikta7818 again you are right I forget to put....
@Asmijitshil24 2 күн бұрын
sir here how you select the the direction of the moment at 1:48 I don`t understand
@engradnanrasheedmechanical 2 күн бұрын
you mean moment direction at point A ? roughly you can see the net effect of point load is downward so it will produce clockwise moment so in order to balance it the counter clock wise moment will be there at A. Rest you can take any direction of moment and calculate its value if it comes out to be positive value it means that your assumed direction is correct and if the value is negative so it means that your assumed direction is wrong and it should be opposite to what you selected. Thank you
@mjd_official 2 күн бұрын
Appreciated sir❤
@engradnanrasheedmechanical 2 күн бұрын
Thank you but i think you have not studied singularity functions for finding shear force and Bending moment equation and later on this can be used to obtain the deflection and slope of the beam.
@mjd_official 2 күн бұрын
@@engradnanrasheedmechanical sir kuch cheezy humy ne class m seeki hoty h or knowledge mai izafy k lye kuch videos dekty h ...
@engradnanrasheedmechanical 2 күн бұрын
That's good 👍
@Asmijitshil24 2 күн бұрын
sir i don`t understand about the I portion means why 1/3 ?? why not 1/12????
@engradnanrasheedmechanical 2 күн бұрын
Where ? Tell me the time where you have problem
@Asmijitshil24 2 күн бұрын
@@engradnanrasheedmechanical 7:09 during the deribation of Ib
@engradnanrasheedmechanical 2 күн бұрын
@arikta7818 1/ 12 bh^3 is moment of inertia for rectangular shape while moment of intertia for semi circle is pi/8 * r^4
@Asmijitshil24 2 күн бұрын
@@engradnanrasheedmechanical sir why 1/13 you write 1/3 and why not 1/12 ?
@engradnanrasheedmechanical 2 күн бұрын
Yes you are right It's a mistake and sometimes this happen. You can calculate it as well.
@BG-uf8kh 2 күн бұрын
Thank you sir. Great explanation as usual!
@engradnanrasheedmechanical 2 күн бұрын
thank you and i have recorded two more for the next two days.
@fatimazehra3258 2 күн бұрын
please explain example 3.3
@engradnanrasheedmechanical 2 күн бұрын
Ok I shall try my best to explain it...when get free time
@Asmijitshil24 2 күн бұрын
Hello sir, I am Arijit Shil from IIT KHARAGPUR , INDIA, Sir I am also a mechanical engineering. student , thanks a lot sir for your lectures it helps me a lot for my semester exams preparations , we need more , or sir please upload some videos related to fluid mechanics and dynamics then it should be more helpful to us
@engradnanrasheedmechanical 2 күн бұрын
Thank you @arikta7818 . You can check my channel as it has hundred of solved problems as well as theory lectures in detail. I shall try my best to make more and more. Thank you for your valuable feedback 👍
@jeirvinloucatana8615 3 күн бұрын
Why is it divided by 2?
@engradnanrasheedmechanical 3 күн бұрын
Where ?
@GAMUCHIRAIPAULNYAMUTSIKA 4 күн бұрын
you are the best my guy, you have really helped a lot
@engradnanrasheedmechanical 4 күн бұрын
You are welcome and kindly share my videos with your friends and help me in growing my channel further. Thank you 😊 💓
@Enitsuj1010 4 күн бұрын
why cos not sin?
@engradnanrasheedmechanical 4 күн бұрын
For finding theta you can apply sin theta and get theta. But you can see we need vertical component of Fbe which can be taken as cos theta = base /hypotenuse = Fbe y/ Fbe , so Fbey= Fbe cos theta= Fbe * 12/ 15.
@BG-uf8kh 5 күн бұрын
We have all missed you sir!!🎉🎉
@engradnanrasheedmechanical 5 күн бұрын
Thank you 😊 💓 and I shall try to make videos regularly. Kindly share it with news students as well.
@sikandar110 5 күн бұрын
Great Explanation Sir
@engradnanrasheedmechanical 5 күн бұрын
Thank you 😊 💓
@daparts4999 6 күн бұрын
Thank you so much
@engradnanrasheedmechanical 6 күн бұрын
You're most welcome
@korawitchinasri5044 7 күн бұрын
Thank you from Thailand ❤❤
@engradnanrasheedmechanical 7 күн бұрын
You are welcome and keep watching and sharing my videos with your friends ❤
@Brainisthenics-sr2rq 7 күн бұрын
Great vid
@engradnanrasheedmechanical 7 күн бұрын
Thank you 😊
@danielleshaffer620 7 күн бұрын
Hey there! Thank you for posting this! I just realized your problem has 0.15" instead of 0.075" for the downward displacement of C. After watching this and finding the textbook solution for mine, I noticed that my work only had one difference being the length of D in the y direction after displacement. C was displaced downward by 0.075" but since point D is at the midpoint, I think the displacement length for D should be 0.0375 instead of 0.075. I put my previous comment on the wrong video though lol. Copy pasting it here, please let me know if you agree. "I found the textbook solution and they used 0.075" as the displaced length in the y direction for point D but for the given geometry, the length from D-D' should be half that. So LD' should be 0.0375". Using that to solve for LBD', normal strain, and normal stress should result in 60.03", 5x10^-4, and 14.5ksi respectively. Then solving for the moments about point A should result in the 2.5P=FBD and finally P = 284.70 lb."
@engradnanrasheedmechanical 7 күн бұрын
You are right and again you can verify it through video where you can just put your own values of the problem and solve accordingly. Thank you
@danishkham1827 7 күн бұрын
Sir g ye paper mien na dena
@engradnanrasheedmechanical 7 күн бұрын
@@danishkham1827 kha nur sanga ye
@BG-uf8kh 7 күн бұрын
Great 🎉🎉
@engradnanrasheedmechanical 7 күн бұрын
Thanks 😄
@BG-uf8kh 8 күн бұрын
Welcome back sir
@engradnanrasheedmechanical 8 күн бұрын
Thank you brother after 3 months. I just started 🙏
@danielleshaffer620 9 күн бұрын
Do you know if there's a video for the 2nd part of this problem? (3-15). It's the same thing except it wants you to solve for P if C is displaced 0.075 in. downward. I've found multiple step-by-step solutions but none of them show any details for how angles & lengths were obtained. Thank you!
@engradnanrasheedmechanical 9 күн бұрын
Currently I haven't solved it and I shall check and when get time will try to solve for you. ❤
@engradnanrasheedmechanical 8 күн бұрын
@danielleshaffer620 for you i have specially recorded that video and soon after one hour you can watch it and learn it. Stay tune and keep watching. Thank you
@danielleshaffer620 8 күн бұрын
@engradnanrasheedmechanical Thank you!!! I keep getting 284.7 lb but the text solution says its 570lb while the quizlet/chegg solutions say it's 570 or 980lb. I asked my professor and he said the length I got for BD' was correct (60.03") and you can't take moments about point C to get P so all you're left with is moments about point A. So if that 60.03" is correct, I'm not sure how my answer is wrong unless my moment equation is wrong.
@engradnanrasheedmechanical 8 күн бұрын
kzbin.info/www/bejne/ZpzHcmttgNyZpNk Check out this please and give me your feedback
@engradnanrasheedmechanical 8 күн бұрын
@danielleshaffer620 did you check what you did wrong? After 3 month I have started first video and it's because of you and thanks to you for encouraging me to start it again.
@krmesad5608 9 күн бұрын
you are a true legend, quick explanationer, intelligence, super engineer. big love from Saudi Arabia
@engradnanrasheedmechanical 9 күн бұрын
Thank you so much for your valuable feedback, love and support ❤
@ragnarlothbrok6324 10 күн бұрын
Wow sir, you have solved so many. I love you!
@engradnanrasheedmechanical 10 күн бұрын
@@ragnarlothbrok6324 thank you and kindly forward it to your friends as well.
@ragnarlothbrok6324 10 күн бұрын
@@engradnanrasheedmechanical will do sir
@CheckMateMate10 11 күн бұрын
Please more fluid mechanics
@engradnanrasheedmechanical 11 күн бұрын
Thank you. When get I free time I shall try .
@neofortunate4521 12 күн бұрын
Sir, can you please help me in identifying the sections that i need to use to solve for Q.
@engradnanrasheedmechanical 12 күн бұрын
You want to say that I should identify the other section for calculating Q. I got that you want another question with different section.
@neofortunate4521 12 күн бұрын
@@engradnanrasheedmechanical Yes, sir the selection part confuse me a lot, cause other beams we section differently...Otherwise you're theeeeeeee bestttttttttt.🥳🥳🥳
@engradnanrasheedmechanical 12 күн бұрын
Here is the complete playlist for this chapter. It contain easy to complex problems
@Kohlmam 12 күн бұрын
Thanks
@engradnanrasheedmechanical 12 күн бұрын
you are welcome 🙏
@bimplay6903 13 күн бұрын
Amazing video, by any chance could you tell us what edition number book we can find this exercise? I have the old Hibbeler and couldnt find it :(
@engradnanrasheedmechanical 13 күн бұрын
Thank you and its 9th Edition
@engradnanrasheedmechanical 13 күн бұрын
@@bimplay6903 also if you look at the thumbnail , all the information of book and its edition is given. Thank you
@jardelaguiar1940 14 күн бұрын
Muito obrigado, Brazilian here !!!
@engradnanrasheedmechanical 14 күн бұрын
You are welcome bro...
@Ijee12 17 күн бұрын
8:29 please can you also explain why you multiplied by 2/2?
@Ijee12 17 күн бұрын
8:07 why did you write out the formulas as N/A’? Normally it’s N/A but you wrote N/A’ please can you explain that part?
@engradnanrasheedmechanical 17 күн бұрын
Ok A' is oblique plane and in question it has been asked to find the normal and shear stress at oblique plane or plane at given angle. So stress on plane A' will be N/A'. I hope it is clear now
@Ijee12 17 күн бұрын
@@engradnanrasheedmechanical thank you
@engradnanrasheedmechanical 17 күн бұрын
You are welcome 😊
@Ijee12 17 күн бұрын
6:13 can you please explain how you came about A’ = A/sin o?
@engradnanrasheedmechanical 17 күн бұрын
I shall suggest you that again watch this portion. I shall again explain , as sin theta = A/ A' so A'= A/ sin theta
@Ijee12 17 күн бұрын
@@engradnanrasheedmechanical okay. Thank you 🤲🏽
@Ijee12 17 күн бұрын
@@engradnanrasheedmechanicalfrom what i just did now using geometry, the A is the opposite and the A’ is the hypotenuse so that’s why you used sine? Am i correct?
@engradnanrasheedmechanical 17 күн бұрын
Yes
@kieranaxisa8138 17 күн бұрын
for section AB should torque B not be considered and why? As I have seen examples where it is included.
@kieranaxisa8138 17 күн бұрын
Also the reaction torque at support D is also not considered?
@engradnanrasheedmechanical 17 күн бұрын
For section AB the torque is considered from left side. You can also come from right side subject to condition that first you have to find the reaction torque at D. You you can apply both and check it , it will give Same torque in each section. Try it and get back to me for your feedback. I gave this question in mid term paper of this summer. Its the easiest one.
@jaysan3004 17 күн бұрын
Hello sir, can you explain why dA = bdx? what side of the small element are we looking at? I am having a hard time visualizing it
@engradnanrasheedmechanical 17 күн бұрын
From bottom or top view dx is the small length of element and b is width.
@engradnanrasheedmechanical 17 күн бұрын
It's like book lying on table and it's thickness in in your frontal view while width can be seen in the top view.
@Ijee12 18 күн бұрын
Would you say the shear force is perpendicular to the surface or parallel to the surface ? I’m still trying to get a hold of when to determine shear force.
@engradnanrasheedmechanical 18 күн бұрын
Shear force is always parallel to the surface to which it it is applied.
@Ijee12 18 күн бұрын
@@engradnanrasheedmechanical okay. Thank you.
@engradnanrasheedmechanical 18 күн бұрын
@Ijee12 you are welcome
@sikandar110 18 күн бұрын
Sir you are clearing my concepts. Thank you.
@engradnanrasheedmechanical 18 күн бұрын
Keep watching 👀 🙂 😎
@SomcaiTodtda 19 күн бұрын
Why 60÷8
@engradnanrasheedmechanical 19 күн бұрын
Where?
@SomcaiTodtda 19 күн бұрын
@@engradnanrasheedmechanical Sir -20(3)+Rcy(8)=0
@engradnanrasheedmechanical 19 күн бұрын
@SomcaiTodtda it's very simple move -60 to right hand side it will be 8 Rcy = 60 Now divide 8 on both side you will get Rcy = 60/8 = 7.5
@SomcaiTodtda 19 күн бұрын
@@engradnanrasheedmechanical Thanks you sir
@engradnanrasheedmechanical 19 күн бұрын
@SomcaiTodtda you are welcome 😊
@shreeswar7940 19 күн бұрын
Sir i have a question, if 60kN is applied at F, won't the spring counteract the force i.e. how will it be 30kN for both the bars. Where is the counteractive force that the spring exhibits. Like if we write the force equilibrium equation won't it be Fab + Fcd + kx (spring's resistance force) = 60kN. I am little bit confused about it
@engradnanrasheedmechanical 19 күн бұрын
In fig (a) we have taken section of EF to find force in Ef while in B we have taken spring and beam BD as single body and find the force in BE and CD and in third we took the spring forces .
@engradnanrasheedmechanical 19 күн бұрын
Actually you can see due to tension in 3 rods point F will move downward and due to compressive force pf spring it's also move down ward so total displacement is sum of the deflections.
@engradnanrasheedmechanical 19 күн бұрын
Also you can see the P load cases compression in spring and this load will be equal to P as this rod and spring is single assembly so the net force on Beam AB will act causing the force in other rods to be 30 in each.
@shreeswar7940 18 күн бұрын
Thank you very much sir, finally i got the concept😊@@engradnanrasheedmechanical
@engradnanrasheedmechanical 18 күн бұрын
@shreeswar7940 you are welcome 😊