Using mohr's circle you got Tau max = 14.9 ksi. Is it possible to calculate factor of safety usig the Tau max? and How to do it? Thanks
@engradnanrasheedmechanical3 күн бұрын
From this when you get maximum shear stress then using failure theories you can calculate the factor of safety and based on that factor of safety you can choose the material which supports the maximum shear stress without causing failure ...
@MrJPDasani2 күн бұрын
@@engradnanrasheedmechanical Thanks. I understand about failure theories but maybe not that well. The issue is when you calculate factor of safety using the failure theories (von mises and/or max shear theory). Assuming any ex.steel material. You get almost the same factor of safety. My question is if i can calculate the factor of safety using max shear value calculated. In other words. For this specific tension load condition. Can i divide Material yield strength/ Tau max shear or not? Or Should i be N= YS/2? Thanks
@engradnanrasheedmechanical2 күн бұрын
@MrJPDasani yes you can divide the materials yield strength by Tau max...
@LactationMan3 күн бұрын
Thanks man
@engradnanrasheedmechanical3 күн бұрын
You are welcome 🌹
@kamosmkey3 күн бұрын
Hello, professor. I wonder in what case sigma y does not equal to zero? It seems that even the loading in the y direction will only cause moment and thus bending in x direction. What element will cause sigma y not to be zero?
@engradnanrasheedmechanical3 күн бұрын
Hello, kindly check problem 9.23 for the details , and also for sigma y is not equal to zero for only this loading is not possible for this loading , for loading in 3 dimension, it may be not equal to zero.
@kamosmkey2 күн бұрын
@@engradnanrasheedmechanical Thanks a lot for your answer!
@engradnanrasheedmechanical2 күн бұрын
@kamosmkey you are always welcome
@BG-uf8kh4 күн бұрын
Loved this one and how you clearly illustrated the stress diagram for multiple points on the beam. 🎉
@engradnanrasheedmechanical4 күн бұрын
Thank you so much 💓 for your valuable feedback 👍
@anmarsaif3814 күн бұрын
Can I use method of equilibrium? I used the method of equilibrium and got 177.45MPa for Normal Stress and −59.15MPa for Shear Stress.
@engradnanrasheedmechanical4 күн бұрын
yes you can and may be you have made a mistake ❤
@e.v.wextermeviolentwrestli57504 күн бұрын
This was actually very helpful something I was stuck on for a while now earned by subscription and like thank you and keep doing what you are doing!
@engradnanrasheedmechanical4 күн бұрын
thank you for your valuable feedback about the videos
@Ritiksoothwal-h7i5 күн бұрын
sir it's -100-(-75)=-100+75=-25
@engradnanrasheedmechanical4 күн бұрын
??
@mevirendersingh5 күн бұрын
y you dont take modulus of elasticity?
@engradnanrasheedmechanical5 күн бұрын
where?
@mevirendersingh4 күн бұрын
@@engradnanrasheedmechanical at last 1 upon 2 AE you don't put the value of E as 200
@engradnanrasheedmechanical4 күн бұрын
May be I shall check but if not then you can plug in the value. Thank you amd sasriakal pa ji
@LOVEAD25 күн бұрын
At 38:51 can we put the bending moment in clockwise direction?
@engradnanrasheedmechanical5 күн бұрын
Yes Of course that will be too good as in this moment equation when you put x=0 you will get -216 which mean our assumed direction is wrong it should be clock wise.
@Parwartist6 күн бұрын
Do you hane pdf of your solutions or telegram chanel?
@engradnanrasheedmechanical6 күн бұрын
No I don't have pdf of my solutions, also what is telegram channel?
@engradnanrasheed12806 күн бұрын
🎉❤❤❤🎉
@xaviergonzalez58286 күн бұрын
Thank you!
@engradnanrasheedmechanical6 күн бұрын
You're welcome!
@engradnanrasheed12806 күн бұрын
❤🎉
@RashidOfficial6216 күн бұрын
Please guide me for uet university mechanical engineering
@engradnanrasheedmechanical6 күн бұрын
What you want to ask? I am here to answer.
@RashidOfficial6216 күн бұрын
mechinacal ke seat mali hai
@engradnanrasheedmechanical6 күн бұрын
Congratulations aor kis University main and campus?
@angelatapay34647 күн бұрын
Just in time for our Finals, thank you so much! But really, why is the y-dash for B not located on 0.02m when at the illustration, point B is seemingly placed at the intersection point of two rectangles?
@engradnanrasheedmechanical6 күн бұрын
Y dash b is the distance from neutral axis to the mid of the area. As b point lies at distance of 20 mm from the base , so area below b point is out main focus so the distance from neutral axis till the mid of that area is y dash b. And this will be used to find Q ( First moment of inertia). Try other problems of this series you will learn it.
@zanegporter34067 күн бұрын
Great Work! Thank you,
@engradnanrasheedmechanical6 күн бұрын
Thank you and share it to maximum people so that they may learn it also. 😀
@aadikhan17 күн бұрын
❤🎉
@DepartmentofMechanicalEnggPesh7 күн бұрын
❤
@BG-uf8kh7 күн бұрын
This was amazing Sir. 🎉🎉 great explanation
@engradnanrasheedmechanical7 күн бұрын
Thank you so much 💓 for your valuable feedback 👍
@AdnanRasheedKhan7 күн бұрын
❤🩹❤
@engradnanrasheedmechanical7 күн бұрын
Thanks
@instructormepwr7 күн бұрын
🎉❤🎉❤🎉😍🤩🥰💯👍🤲🙏
@engradnanrasheedmechanical7 күн бұрын
Thank you
@instructormepwr7 күн бұрын
🎉😮❤
@engradnanrasheedmechanical7 күн бұрын
Thank you 🥰😍💝
@instructormepwr7 күн бұрын
❤❤❤🎉🎉🎉
@engradnanrasheedmechanical7 күн бұрын
Thank you 👍
@instructormepwr7 күн бұрын
❤❤❤❤
@engradnanrasheedmechanical7 күн бұрын
thanks a lot
@instructormepwr7 күн бұрын
❤❤❤❤
@engradnanrasheedmechanical7 күн бұрын
thank you 🙏
@instructormepwr7 күн бұрын
🎉🎉🎉❤❤❤
@engradnanrasheedmechanical7 күн бұрын
Thank you 👍
@rayyanrasheedofficial71907 күн бұрын
Amazing ❤🎉. Thank you
@engradnanrasheedmechanical7 күн бұрын
You are welcome 🌹
@AKMALAHMMED7 күн бұрын
can u sir give me the solution manual plz ,,,
@engradnanrasheedmechanical7 күн бұрын
Its available online , you can download it please.
@AKMALAHMMED7 күн бұрын
@@engradnanrasheedmechanical sir i try a lot,,,,,but i can't,,
@engradnanrasheedmechanical7 күн бұрын
@AKMALAHMMED ok email me on [email protected] and mention the solution manual for the book (name and edition)
@htethtethtun16957 күн бұрын
Thank you
@engradnanrasheedmechanical7 күн бұрын
You are welcome 🌹
@BG-uf8kh7 күн бұрын
Loved this one 🎉. I can't wait till next one Sir
@engradnanrasheedmechanical7 күн бұрын
Thank you for your valuable feedback 👍 and you will get more inshallah
@engradnanrasheed12808 күн бұрын
❤
@aadikhan18 күн бұрын
❤
@Atinut128 күн бұрын
Normal if I get (y) from 220+12+12 than divided 2
@engradnanrasheedmechanical8 күн бұрын
220 is the total length so why to add 12 +12 ??
@Atinut128 күн бұрын
@ I assumed x as neutral line
@thecrazyonion47539 күн бұрын
Life saver
@engradnanrasheedmechanical8 күн бұрын
Enjoy the videos and keep sharing them with your friends ❤
@IntrovetMaven9 күн бұрын
Why we solve this question so lengthy if we want to get the weight of steel so we multiply gamma × volume of steel = 1347.5 final answer simple
@engradnanrasheedmechanical9 күн бұрын
This is the procedure and I have to explain for those who don't know about this also we are taking the whole length instead we are taking 2.75 ft length but anyways once you learn , you always think of many way to solve it quicker. ❤
@ShreyasSakthivel-p1d9 күн бұрын
Thank you Mr. Adnan Rasheed. I have an exam today and your videos helped very much
@engradnanrasheedmechanical9 күн бұрын
You are welcome 🌹 and share my videos with your friends ❤
@tempra879079 күн бұрын
How did you choose the sign of moment in the equation of normal stress? I was watching many videos which are related to this chapter but still I couldn't understand how you determined the sign of moment in the normal stress equation. I am confused. Would you like to explain?
@engradnanrasheedmechanical9 күн бұрын
You can see that reaction moment is clock wise so it will produce tension at point B and compression at point A that's why...
@Demetri19210 күн бұрын
So what would be the expression for the maximum strain energy density in terms of the strain energy U and the volume of the beam V?
@engradnanrasheedmechanical9 күн бұрын
Divide this expression by total volume of the beam you will get the strain energy density.
@Demetri1929 күн бұрын
@engradnanrasheedmechanical Thank you!
@engradnanrasheedmechanical9 күн бұрын
@Demetri192 you are welcome
@subhanjaved397110 күн бұрын
At 17:56, the c3 value calculated, is wrong.
@engradnanrasheedmechanical9 күн бұрын
It may be , but the main thing is the concept which i think, you have learnt ❤
@subhanjaved39716 күн бұрын
@ Yes Sir. Thankyou for your videos. They help a lot. Tomorrow’s my strength of materials final. Wish me luck 🙂
@engradnanrasheedmechanical5 күн бұрын
You are welcome 🌹 and best wishes ❤ and good luck for your final exams. Inshallah you will do the best 👌 👍
@sarweshchandramouli7382Күн бұрын
@@subhanjaved3971 hope u did well! mines is in 5 hrs!! And thank you @engradnanrasheedmechanical sir for your help!!