I am teaching a college level PreCalc class, but most of this would be covered in an advanced math class in high school too.
@mamadetaslimtorabally73633 ай бұрын
Very well explained in detail.
@MrsMath-xe7fy2 ай бұрын
Thanks.
@dreamsofendlessguitar16711 ай бұрын
I am taking Mathematics for Elementary Teachers next quarter. Your videos are so helpful, and I will be referring back to them often.
@whoisboppy11 ай бұрын
Life saver <3
@okesamuel4663 Жыл бұрын
I have difficulty in mathematics
@Hcs586 Жыл бұрын
Thank you for your help!
@UnknownPerson-nl7te Жыл бұрын
I mean, I had the exact question in the exam and I had no idea and couldn't figure out how to solve this question, We weren't even given practice questions for exam
@kamranullah27892 жыл бұрын
X
@Goalsofrailways2 жыл бұрын
Nice teaching
@user-jp8mv3jg9b3 жыл бұрын
ia8sn vur.fyi
@nickolaswalczak67723 жыл бұрын
Fix your title
@leslisherye73773 жыл бұрын
ti9un vum.fyi
@cadencedavis75103 жыл бұрын
The writing sounds kept this video really satisfying to listen to
@grandangus52853 жыл бұрын
Thanks for the vid, was struggling with this today and this was really easy to understand!
@fififinance74693 жыл бұрын
Good research for me 😍
@emilyharris27794 жыл бұрын
"Given COS find SINE" Interesting how you're given sine and find cosine..
@hanumkusumahdewi37774 жыл бұрын
I can understand... 🤦♂🤦♂🤦♂
@AdmirableProductions4 жыл бұрын
you're a terrible fucking teacher
@hamishleijer7945 жыл бұрын
why the root(1+cos(pi/4)/2 ??
@anandcherian.5856 жыл бұрын
But won't they intersect at 2π also.....so 5 solutions in [0,2π]
@anandcherian.5856 жыл бұрын
Thank you so much
@rikvandenreijen6 жыл бұрын
Hi Mrs. Math I believe you forgot to write arcsin or sin^-1 when you wrote the inverse function. Thanks for the video. Quick and to the point.
Dividing both sides by sinx instead of subtracting sinx from both sides then factorising means you lose solutions.
@xXxMineMasterxXx4 жыл бұрын
what if x can be equal to 0?
@Bubblesandgoop6 жыл бұрын
I like your videos, it would be nice, however, if you stuck with the same thickness of pen, your writing would be a bit easier to read. Unfortunately, it can be a bit messy to read when that changes. Other than that, this was awesome! Thank you for making these videos!
@ashw7307 жыл бұрын
Why do you take sqrt?
@danielhamam7 жыл бұрын
Thanks :)
@Awh1t3Guy7 жыл бұрын
love your teaching method. Recommend an external microphone, but thank you so much!! College level calculus would be greatly appreciated :)
@MrsMath-xe7fy7 жыл бұрын
Thank you! I will definitely consider getting a microphone.
@sajanphilipjacob19627 жыл бұрын
Amazing.
@MrsMath-xe7fy7 жыл бұрын
Thanks!
@yumilisalgue52398 жыл бұрын
Lol
@rrpeguero8 жыл бұрын
hey thanks for the video, i have a question about the negative sign, im trying to get cos(5pi/8) and it is in the 3rd region (cuadrante) which sign do i have to use? positive or negative outside of the square root sign?
@susanaportilla15 жыл бұрын
Positive , if pi/8 is quad 1 , then 2pi/8 is quad 2, 3pi/8 is quad 3 and 4pi/8 is quad 4 then 5pi/8 is quad1. You have made a complete circle + another pi/8 going back to quad 1 where 5pi/8 is.
@user-ke4hi2el5k8 жыл бұрын
I don't exactly understand why you had add (1) !
@hamishleijer7945 жыл бұрын
same; why the root(1+cos(pi/4)/2 ??
@sunjayk5778 жыл бұрын
Thanks for this video, really helped me out
@LovingLifewithAudrey8 жыл бұрын
Just a little confused at the beginning because isn't half of pi/8 going to be pi/16?
@ReaperGFX8 жыл бұрын
how would you do it if you want to find the exact value of cos(pi/6) with the half angle identity of the exact value sin(pi/12)
@MrsMath-xe7fy8 жыл бұрын
+ReaperGFX Do you still need this? I'm not teaching Trig right now but I can get back to you if you still need help.
@ReaperGFX8 жыл бұрын
nope. all is good. but thanks anyway
@MrsMath-xe7fy9 жыл бұрын
I am glad this helped you. I post these for my students but I'm glad other people can benefit as well.
@Torchlava1009 жыл бұрын
Whoever gave the thumbs down doesn't know how to understand explanations given from extraordinary people.