Bahut badhiya sir ji

Sir aur questions ispr karvaiye

Sir kabhi bhi sabse zyada value ho to kaise apply or same sabse kam ho to iske liye?

Most beneficial 😃

Konsa semester h bro

Great explanation sir 👍 👏

Thank you sir 🙏 explained very nicely

Sir pls tell me kya ignou ke reimann integral syllabus ke according yeh playlist enough hai , kyunki hmaari book mai tagged partition or pta nhi kai chize di hui hai jiski wajah se mujhe padhne mai problem aa rhi hai sir pls reply

Great 👍🏻

Sir ji apki explanation ki tarif k liye mere pass word nhi hai Thank you so much sir ❤❤❤❤❤❤❤❤❤

Thank you sir

nice explanation

🙏🏼🙏🏼👍

Please complete Statics book 📖

So much easy explanation..tnq

Very nice explanation sir ji

Awesome explanation sir

Prove that the ideal pZ in the ring of integers Z is maximal if and only if p is a prime ? Ye question ke liye aapne jo karwaya woh likh sakte hai ?

🎉

sir i have a doubt you have used symbol this ⊆ for s contained in s(dash) contained in z . but in the book at some places they have used ⊂ this symbol . can we use both of them?

Sir agar exam main bole ki state and prove Lagrange theorem toh then konsa form karna hoga. ... please reply!! Subscribed:)

Awesome

Sachmeee swadddd aaaa gyaaaaa sir ji ....🔥🔥🔥♥️

🌟

Please complete the other chapters of real analysis

Awesome explanation

nicely explained in every brief :)

❤

Amazing explanation...it's so easy to understand thankyou very much sir...✨PDE or Advance calculus pr bhi bna do video

Very fantastic explanation... thankyou thankyou so much sir...I request sir aap real analysis bhi kra do complete

Clear sir❤❤

Super sir keep rocking 🎉

Please try explaining in English

Awesome explanation different from other ❤❤❤

In book there is too difficult to understand but on seeing your videos there is is simple to understand ❤❤❤❤❤thanks sir

Thank you vector.

Thank u sir mujhe ye test mujhe kisi se smjh nhi aaya apne smjha diya😊

great explanation

Thank you sir

Thankyou sir 🙏

Not defined

Smjhane ka tareeka kaafi accha hai sir , dhanywaad guruji

Last step is not clear sir ...

Very fine explanation

To solve the equation \( a^b - b^a = 1 \), where \( a \) and \( b \) are positive integers, we can approach this problem by checking possible values for \( a \) and \( b \) manually. Here's the step-by-step reasoning: ### Step 1: Check Small Values of \( a \) and \( b \) Since \( a \) and \( b \) are positive integers, we start by testing small values. #### Case 1: \( a = 2 \) and \( b = 1 \) \[ 2^1 - 1^2 = 2 - 1 = 1 \] This satisfies the equation \( 2^1 - 1^2 = 1 \), so \( a = 2 \) and \( b = 1 \) is a solution. #### Case 2: \( a = 3 \) and \( b = 2 \) \[ 3^2 - 2^3 = 9 - 8 = 1 \] This also satisfies the equation \( 3^2 - 2^3 = 1 \), so \( a = 3 \) and \( b = 2 \) is another solution. ### Step 2: Consider General Cases Next, let's consider whether any larger values of \( a \) and \( b \) could satisfy the equation. However, as \( a \) and \( b \) increase, the difference between \( a^b \) and \( b^a \) tends to grow larger than 1. For example: - \( a = 4 \), \( b = 3 \): \[ 4^3 - 3^4 = 64 - 81 = -17 \] (not equal to 1) - \( a = 5 \), \( b = 4 \): \[ 5^4 - 4^5 = 625 - 1024 = -399 \] (not equal to 1) Thus, no larger pairs of positive integers \( a \) and \( b \) satisfy the equation. ### Conclusion The only solutions are: - \( (a, b) = (2, 1) \) - \( (a, b) = (3, 2) \) These are the values of \( a \) and \( b \) that satisfy the equation \( a^b - b^a = 1 \).

Wrong concept There are lots of eg like DOB 05/08/2021 acq to ur theory marriage will be in 2024, that's possible? You say 90% true but this is 90% false

Nice explained

Sir ,I want to online tuition from u ,is it possible,sir? I am in bsc 3rd year

Aap acha padhte hai sir . video lecture banate rahiye