Sir ji hindi me samjhaoge to bacche log jyada intrest lenge jaroori nhi hai ki English bolo aap ka reach bhi jyada nhi aayega is trah se
@anniappanacademy54523 күн бұрын
Iam not good at Hindi. Sorry.
@sbhavanisbhavani81876 күн бұрын
Sir please update the video of mensuration 7.1
@anniappanacademy54526 күн бұрын
State Board or CBSE board
@sdevadevendra81027 күн бұрын
Who are watching this video before one for exam😅😂😂
@sharwanmeena28008 күн бұрын
❤ thanks sir ❤🎉
@srai.854510 күн бұрын
Thankyou sir I am very thankful 😊😊😊😊
@SibaniBehera-iy5uo12 күн бұрын
🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉
@jeganram268814 күн бұрын
please uplpad 12th maths 5.2 all sums sir
@Saraswathi-d3g14 күн бұрын
Simply you expalined that Concept in easy way Sir your way of teaching this topic in English is very wel sir🎉
@gamingwitharnav1914 күн бұрын
Bkl
@manrajmeena993416 күн бұрын
Nice video sir
@ridoyhasan174619 күн бұрын
Thanks bro
@pavangaming345119 күн бұрын
Understood 🎉
@PawanKumar-bu6qk21 күн бұрын
❤❤
@mamtapatil190121 күн бұрын
😊 🙏
@arigelaraja888023 күн бұрын
ఎస్ i understand
@srinivasiti242224 күн бұрын
Super explanation thank you so much sir 🎉❤
@FlockFF29 күн бұрын
😮Suuuuuu
@daretoknowbabaАй бұрын
I want to ask one question. I just read the Taylor's theorem and I watched this video after that. Here, f(z)=1/(z-2) ok. And we to expand it at z=1. As we see, z=1 means, a circle with centre (0,0) and radius 1. So,for this circle the given function f(z)=1/(z-2) is analytical, because it is not analytic only at z=2 which is outside the circle. So, it fulfils the requirement to be expanded in Taylor's series. Now, we are to find f(1) isn't it? But Taylor's series is- f(z) = f(z○)+ f' (z○) ( z - z○ ) + f'' ( z○) / 2 ! ( z - z○ ) ^2+.......... so Here, z○ is the centre of the circle ( z=1) which means it should be 0. I want to understand, why did you take z○ =1 ??? The differentiation is ok. But while putting values why did you put z○=1 instead of 0? Could you please explain? I'm very curious to know this.
@NeelamBisht-qt1wyАй бұрын
Thank you so muchh
@theonewhoasked2Ай бұрын
thanks a lot sir
@HYEDRABADI_GAMERАй бұрын
Thanks 👍
@elamaranupdate8971Ай бұрын
super sir i like it by elamaran❤❤❤❤
@chitrashrimali8947Ай бұрын
oh thank u so much sir
@grade12cs81Ай бұрын
Congratulation Rithesh! Congratulations ma'am!
@theyadavsiblings3698Ай бұрын
Thank you sir Sir aache se samajh AA gaya 🙏🙏🙏
@kavithathandapani8303Ай бұрын
Super
@anniappanacademy5452Ай бұрын
Thanks
@WillShowmakerАй бұрын
No idea what he said😂
@anniappanacademy5452Ай бұрын
The essence of that content is....if God has not given Crystal...we cannot realize the present day Computer's. Because the oscillation stability is very high when we use crystal.
@gargikumari7385Ай бұрын
Yes
@anukritikumari5323Ай бұрын
This is applicable for inelastic collision or elastic collision.......?
@EkmbaramNАй бұрын
Super
@Vandana-b3bАй бұрын
Sir hindi me smejhye to acha hai
@Vandana-b3bАй бұрын
😅😅😅😅😅
@jayashreejayashree5371Ай бұрын
Thankyou sir nalla teach pandringa 🎉🎉
@madanmishra5789Ай бұрын
Sir lateral strain aur longitudinal strain kahan lag rha h?
@madanmishra5789Ай бұрын
Thankyou soo much sir 😊❤🙏
@madanmishra5789Ай бұрын
Ye object mujhe cylindrical shape ka clay ya gutha hua ata kyon lag rha hai 😅its my imagination because spring to turant apna actual form gain kar legi 😊
@HarshaVardhan-h8u2 ай бұрын
Super sir anna...
@jayashreejayashree53712 ай бұрын
Thankyou sir🎉🎉
@Bronxx_02 ай бұрын
❤
@viduranimalarathne87972 ай бұрын
Thanks sir for simplifying 30 mins of lecture 🙏
@NumbaSamuel2 ай бұрын
Thanks
@indusandeep57882 ай бұрын
Thank you so much😮
@SravaniSatti-sz5hx2 ай бұрын
Tanks sir
@Poornima-f6s2 ай бұрын
Very simple and neat way to understand 👍 thank so much!
@dipkanasaha35612 ай бұрын
You are best teacher sir😊😊😊
@zhavlan12583 ай бұрын
Hello. Is it possible at your university to create a working group involving students to work on a ❤new experiment? You understand that one mind and a person are not enough? (for 119 years) By determining the constancy of speed of light, all experiments and Michelson-Morley experiments are indirect and incomplete. If the Michelson-Morley experiment was carried out on a bus or airplane and was used to determine speed. only then will this experience be direct. Therefore, Einstein does not rely on the Michelson-Morley experiment. Question. Do you have an example of such direct experience? New technologies, new research tools Let me suggest for schoolchildren and students on one's own to measure the Universe, dark energy, black holes, etc. To do this, I propose two practical devices. «laser tape measure *+reference distance* 1,000,000 m”» and «Michelson-Morley HYBRID Gyroscope». I am writing to you with a proposal for the joint invention of a HYBRID gyroscope from non-circular, TWO coils with a new type of optical fiber with a “hollow core photonic-substituted vacuum zone or (NANF)” where - the light travels 500000 (In a laser tape measure, the length of the optical fiber is fixed at 1000000 ) meters in each arm, while it does not exceed the parameters 124/124/124 cm, and the weight is 84 kg. Manufacturers of “Fiber Optic Gyroscopes” can produce HYBRID gyroscopes for educational and practical use in schools and higher education institutions. Einstein dreamed of measuring the speed of a train, an airplane - through the Michelson-Morley experiment of 1881/2024, and only then would the experiment be more than 70% complete. This can be done using a fiber optic HYBRID gyroscope. Based on the completion of more than 70% of Michelson's experiment, the following postulates can be proven: Light is an ordered vibration of gravitational quanta, and dominant gravitational fields adjust the speed of light in a vacuum. you can make scientific discoveries; in astronomy, astrophysics, cosmology, higher theoretical physics,... (We are not looking for ether, we will see the work of gravitational quanta) The result is a «theory of everything» in a simple teaching device and a new tape measure for measuring the universe.
@aarushsolanki77303 ай бұрын
icse class 10😊
@SekharNaidu-k4r3 ай бұрын
Clarity not there in the picture but. Explained very well sir 👏👏