Now, I am able to jot exponential equations in under 30 seconds. Thanks to your daily uploads.

After getting the 'feel' and pondering, I am sure 𝑑𝑥 is an infinitesimally small change in 𝑥. Thank you for the wonderful explanation, albeit a repetitive one.

thank u sir but can u make it more engaging by hiring an editor

Thank you for another repetition session. I am catching up with your fast-track methods.

Whew! Played-paused the 1-hour session, making it into a really long one. The end result, I am now able to write linear/quadratic equations in under 25 seconds by applying your shortcut trade, instead of the method(s) I am accustomed to. But I have to work with the exponential ones. Gradually, I am honing my skills due to repeatedly doing the problems. Thank you.

You explain mathematics topics very well. I would be happy if you send me your e-mail or other contact information. I wish you a healthy and successful life. Best regards.🙏

You explain mathematics topics very well. I would be happy if you send me your e-mail or other contact information. I wish you a healthy and successful life. Best regards.🙏

You explain mathematics topics very well. I would be happy if you send me your e-mail or other contact information. I wish you a healthy and successful life. Best regards.👏

The method you have shown is the most practical method for finding the distance between two parallel lines, the radial values ​​between the intersection points of the horizontal x and vertical y axes, and the function equation.

The method you have shown is the most practical method for finding the distance between two parallel lines, the radial values ​​between the intersection points of the horizontal x and vertical y axes, and the function equation.

The method you have shown is the most practical method for finding the distance between two parallel lines, the radial values ​​between the intersection points of the horizontal x and vertical y axes, and the function equation.👏

You are a true genius in functions and mathematics. Thank you.🙏

You are a true genius in functions and mathematics. Thank you.

You are a true genius in functions and mathematics. Thank you.🙏

You are a true genius in functions and mathematics. Thank you.🙏

You solve logarithms, analytical equations and second order unknown equations very well. I really congratulate you. Do you have a private contact information for me to ask you questions? Best regards..

In analytical equations; the distance between two points, the slope and the measurement of the equations are very important! It is very difficult and very important to solve according to the transition points of the paravolute arms.🙏

You really explain it wonderfully. I see your special question solving ability as a new theory. I hope everyone should benefit from you. I wish I had your private contact information. I would like to get information from you. Best regards.🙏

Interesting relationship between the volume of a cuboid and a perfect cube.

Phew! I like the way you mix up really basic stuff with heady problems. By the way, the solution to problem 37 (if factorization/simplification is intended) is 2ax⁵ (7a² - 5x²).

wow I love this, you're hell of a teacher man like KUDOS. I've never seen an explanation like that!

Mr. Vollinger: You explain logarithms in very nice and special ways. Don't you have an e-mail? I wish you success. Best regards.🙏

To the point.

I have arithmetic level knowledge in math. Can I really walk my way up to calculus in 3 months?

... So, the answer to two-lines-multiplied is a parabola of a quadratic equation. Thank you for the impromptu presentation.

The way you teach math is great. Thank you.

I paused the video, and solved the practice problems.

Followed your instruction; watched the first part then this one.

Part 2: kzbin.info/www/bejne/foWThqaBfNB2q8Usi=QVWGuRXzIXF5v4TO

Part 1: kzbin.info/www/bejne/boaqaH2plpmDaNE

THIS is coincidence in math: kzbin.info/www/bejne/pX-VkIGXp8iAbsU

Indeed, short and sweet. Thanks for graphically depicting the 'a'.

Thank you for highlighting rough-estimation of radian measurements.

kzbin.info/www/bejne/n3SUaqhmfN-bqZI I liked your application of the "short cut" of multiplication instead of the traditional division.

You are amazing. You explain things with special methods like scientists. Is it possible to reach you?

Once again thank you for refreshing my memory. And, I did pause, got hold of pen and paper, and managed to work out the last problem.

I want to talk to you about Limit, Derivative and Integral. I cannot see your contact information. I wish you good work. Best regards.

Genial esa forma de sintetizar todo y que quede incrustado de manera no memorizada

Please post all your videos organized in playlists in the correct order we need to follow them so everything makes sense as a learner.

Yes for -3, and no for old, for you "traced it pretty darn well."

You are amazing Sir

... Pondering. 🤔

kzbin.info/www/bejne/fn6VaaFngJ57lZY In my humble opinion, 6 x 1.0001 = 6.0006

Thank you for the background.

To the point.

I watched it twice, but, the second time with a pencil and paper. Thank you for jogging my memory after a hiatus of 53 years.

Thanks teacher ✨

👍🏻👍🏻👍🏻

Thank you for your explanation

Very good maths for experimental Physics