At 15:12 you show the right side network, indicating Ri is 50 ohms. That baffles me. Shouldn't Ri on the right network be the same as Ri on the left network, ergo 15.2 ohms? Otherwise the method makes sense to me. I'm looking to match a 100-ohm antenna to a 50-ohm IC input at the L1 GPS frequency. Favoring a high-pass configuration.
@wallingphd16 күн бұрын
Ri = 15.2, but when we perform series (L1' is in series with Ri) to parallel, the network must have 50Ohm parallel impedance if it will match to 50Ohms at the target frequency. Hence, the modified network is Rip' || L1p', where Rip' is 50 ohms after the transform. This step is shown in going from the top network to the bottom network. If you want to use a high-pass network, you would have to pick a Q and then swap the Ls for Cs and vice-versa.
@its_aleix18 күн бұрын
Thanks for your explanation,but I have a question about the sp simulation vs dc simulation when I used mos as a constant cap(connect body、drain and source,just measure gate to ground cap),I found the dc simulation absolutely different from sp simulation。 The curve tends to go in the opposite direction。 had no clue,In the end, which way can accurately measure the mos capacitor I use in the loop_filter circuit situation???
@wallingphd22 сағат бұрын
The SP simulation should be more accurate, provided the models of the transistors are good, because it takes into account all parasitics. That said, for a loop filter, you may want to consider running PSS + PSP since the DC bias of the filter can impact the total capacitance from the transistor.
@egbertgroot273721 күн бұрын
Finding a low capacitor is easy .. but how do i wind 20 microH? ;-)
@survivalextraordinaire3572Ай бұрын
One thing I'd like to ask, if you ever see this comment, is how would you match the diodes to the feedlines on either side? Say for instance you have diodes that arent already matched to 50 ohms as in your video, I understand how to match the input lines to the diodes ZL, but how would I match the output lines characteristic impedance to the diode? Otherwise great video and I found this very helpful overall.
@francescofilice7210Ай бұрын
Great lesson prof: a highway towards BJT knowledge, merci beaucoup :)
@popavsya_vladickАй бұрын
Пасиб тебе, мужик
@emanatef7749Ай бұрын
ERROR (EXPLORER-5052): Monte Carlo run stopped because no statistical data generated for the test: SAR:mismatch_CM:1
@emanatef7749Ай бұрын
anyone can help me to solve this isssue?
@wallingphd22 сағат бұрын
For error handling, you need to check support.cadence.com or use google: community.cadence.com/cadence_technology_forums/f/custom-ic-design/45443/error-when-doing-monte-carlo-simulation
@garvitjain85232 ай бұрын
at 1:59 it should be N+1 as we go from Ibo to Ibn cause that is N+1 terms
@sanaraji87512 ай бұрын
Hi Jeffrey, Where can I find the full video?
@OmidSalangi-bt2ez2 ай бұрын
thank you
@vicever084 ай бұрын
should condition for S11 equals gamma_in be Gamma_out, S12 or S21, any of them be zero?
@saadqayyum21484 ай бұрын
The derivations of Gm and RT are very confusing, especially the KCL at the output node. As stated by @theslippymaster, the source node is virtual ground due to differential symmetry. Hence, Gm and RT should be same as a Common source transistor and not that of a degenerated one. Furthermore, later in the frequency response (lecture 12 part 1), the values of Gm and RT are not as you derived here but instead what I have stated above.
@BalrajPillai-b7r4 ай бұрын
Where do you find the .dds sample that looks like that? Is there any reference in the examples?
@pablomarco51185 ай бұрын
Many thanks prof!
@pablomarco51185 ай бұрын
Thanks prof
@dongfanghan5 ай бұрын
👍
@VK2LNA6 ай бұрын
Just want to say your videos are fantastic and have really cleared up a lot. Thank you so much for the effort you've put into this.
@kashmirparadise86256 ай бұрын
I'm having systemverilog code and inside it I have instantiated sub blocks which are also written in system verilog but when I try to use config view, it shows view to use only (which i would keep as external HDL view) for top level and not for the sublocks which are instantiated in the blocks of top level. What should I do so that I can get sub blocks there as well so that I can keep it's view to use as external HDL view
@nagarajudeevi7 ай бұрын
Thank you
@SAhellenLily7 ай бұрын
Thank you Sir😊 vy=Gm1*vx*(1/sc)=Gm1*(vx/sc)...(1) Therefoe ix=-io=Gm2*(-vy),ix=Gm2vy..(2) Substituting equation (1) into (2) ix=Gm2*Gm1*(vx/sc),vx/ix=sc/Gm1Gm2 So sc/Gm1Gm2=sL L=c/Gm1*Gm2....answer
@AGuyWhoWantAUsername7 ай бұрын
Anyone here encountering issues where when you save the waveform as image, Cadence will crash?
@MobiusHorizons8 ай бұрын
Thanks for making this! Very clear, understandable and concise. I have been struggling to learn these concepts and this really made it click.
@HarryWoo8 ай бұрын
When tuner provides the various impedance to PA output, Pout is measured at 50ohm ( for example, Spectrum analyzer). How we know insertion loss from tuner input to 50ohm Pout measurement point under a specific tuner input impedance in order to calibrate out that insertion loss ?
@ParminderKaur-zm4kw8 ай бұрын
Hey Mr jeffrey ,Can you please tell which software did you use to record the content ?? The video is very nicely made
@troomshroom76828 ай бұрын
First
@draelos8570Ай бұрын
Second
@conglevan639 ай бұрын
great
@BetterCallHardik9 ай бұрын
angle H starts at -180
@wallingphd9 ай бұрын
That would imply that the transfer function were inverting (e.g., multiplied by -1). It is not, so the angle does not start at -180.
@BetterCallHardik9 ай бұрын
As mentioned in the video H jw is taken as jw-wz when omega tends to zero ; the phasor approaches -wz so the phase is -180 isn't it?
@wallingphd9 ай бұрын
@@BetterCallHardik The angle is equal to atan (-w/wz). atan of 0 is 0.
@BetterCallHardik9 ай бұрын
@@wallingphd it approaches from the negative side of 0 arc tan(0-)=180
@wallingphd9 ай бұрын
@@BetterCallHardik atan(1) = 45, atan(0.5) = 26, atan(0) = 0, atan(-0.5) = -26, atan(-1) = -45). atan is bound between -90 deg and 90 deg for input from -inf to inf.
@yabiliao87799 ай бұрын
thanks!
@KristinaEliot10 ай бұрын
could specify which cells are calculated or and which are given values. i'm also trying to make a link budget for a terrestrial link.
@todayiwill136111 ай бұрын
Thanks a lot ! I’m a master thesis student and you help me a lot
@becermis11 ай бұрын
Great content. Thanks!
@BetterCallHardik11 ай бұрын
if current matching is a concern then Q6 Q8 both must have Vce=Veb
@BetterCallHardik11 ай бұрын
IB0 should also be added giving N+1 term
@BetterCallHardik Жыл бұрын
Ok so the SCTC is for big capacitances llike coupling or bypass and OCTC is for device capacitances.
@BetterCallHardik Жыл бұрын
Bode plots nice
@BetterCallHardik Жыл бұрын
Including ro for last one would have Rc||Rl parallel with r0
@GiorgiAptsiauriX Жыл бұрын
Hi, could you please upload or share privately EMX simulation of the transformer? or anything that details out EMX simulation? I am also using 22FDX-PLUS.
@balrampillai5314 Жыл бұрын
Incredibly useful and informative; thank you so much for putting out this tutorial!
@jimmysun2968 Жыл бұрын
Is Rz Cc-CL/Cc*1/GMII actually?
@digambarbhole9467 Жыл бұрын
sir, I have a module that I have created with the help of Mosfet but now I want to plot the resistance of my entire module from the input port but here I am using the sp parameter method to get this plot while using the sp parameter i am applying pulse input as my module resistance changes with the number of pulses applied to it so I want to plot the real-time resistance of my module as it changes with time as it is a function of the number of pulses applied so with sp parameter I am unable to get this plot can you suggest any method where I could plot this
@ismailassou6942 Жыл бұрын
Sir, do you have license manager for ADS 2024?
@wii_ Жыл бұрын
ty
@farshadsedarati6759 Жыл бұрын
Could you please explain why u use Ps for both loss in inductor and input power?
@刘正-h8k Жыл бұрын
Hi Professor, many thanks for your video! I am wondering do we need to change the differential port impedance to 100ohm and common mode port impedance to 25ohm for this evaluation? In this way, we can get correlated results as the 4 port evaluation using the conventional equation such as SDD11=0.5*(S11+S33-S13-S31). Thanks!
@abheetl9743 Жыл бұрын
Excellent video, very precise and concise. Thanks!
@CircuitShepherd Жыл бұрын
Nice 👍😉
@emiliomartineziii2980 Жыл бұрын
It's always a relief when someone who can speak english makes a video 🙏