Wait according to this you could divide by e^x at the start and get that integral of one equals one
@nebularwinter8 сағат бұрын
Say you remove 5 dollars from both envelopes. Then your odds get better: one envelope has 0 dollars and the other one 5 dollars, and by the same computation with "expected returns", the expected return of switching is INFINITY.
@EdKolis7 сағат бұрын
What if you took $8 out of each, leaving negative money inside the one that had $5? Then there would be negative incentive to switch no matter which you pick!
@driksarkar66754 сағат бұрын
@@EdKolisThat is, you would be incentivized to keep your current envelope.
@shayomarcopion9 сағат бұрын
This is like that one meme where you get to choose if you want to swallow the red pill or blue pill but both choices are balanced. It's a 50/50, what do you expect? Even if you think about changing or staying in the answer, we wouldn't know which is which. 50/50 will always be like that, and will *BE* like that. The law of 50/50 can't be broken.
@asemalawiHb9 сағат бұрын
I love it
@GeoffryGifari16 сағат бұрын
wonder if ramanujan found the solution or the original nested radical first
@nokhinsiu721018 сағат бұрын
Bro proved intergral = 1 and 1/0= 1+1+1²...
@alexanderlevakin900118 сағат бұрын
I like the part where you substitute f(x) for x+2n+a despite f(x) is x+n+a by definition.
@CleverMathematics12 сағат бұрын
Do you mean the part where he substituted f(x+n) for x+2n+a?
@nebularwinter18 сағат бұрын
I liked the part where you introduce "a" and then 4 steps later, you just put "a=0"
@stone73272 күн бұрын
This is so funny. I busted out laughing more than once lol
@platinum_cadence3 күн бұрын
I studied mathematics in college and graduate school and my god my analysis professors, especially functional analysis, would have lost their fucking minds lmao
@MagicGonads4 күн бұрын
There's probably a trivial amount of filtering on the resulting IDs too so they don't contain some specific substrings
@ron-math3 күн бұрын
That's for sure haha.
@isaac102314 күн бұрын
Was this made with Manim?
@ron-math3 күн бұрын
Yes.
@ron-math4 күн бұрын
I love @KZbin.
@Razorcarl6 күн бұрын
This is so cursed
@excelmaster24967 күн бұрын
Let's integrate the closed parenthesis
@chobswey7 күн бұрын
This channel should be called Rum & Math because there’s no way a sober person could come up with this
What exactly do you mean by “operator” when referring to the integral sign? I know that you said to think in reverse, but what does an integral mean without a dx, if it means anything at all?
@hannahnelson45698 күн бұрын
This was simultaneously an incredibly useful and informative lesson and incredibly confusing difficult to understand. Thank you for educating us!
@yewdimer14659 күн бұрын
For anyone confused about the plot at 12:20, it displays the component number on the x-axis and the corresponding value on the y-axis. For example, one of the eigenvalues for the Laplacian matrix is 2, which corresponds to the eigenvector (0.5, -0.5, -0.5, 0.5). With this in mind, the meaning of the plot should become self-explanatory.
@jaf797910 күн бұрын
You have a great teaching style.
@shannonbarber616110 күн бұрын
New subscriber. Hate the video. Show me more physics pleb moves.
@wtfzalgo11 күн бұрын
wat
@redroach40111 күн бұрын
You are probably correct in your analysis but this was a pretty bad explanation so if someone cam please hwlp me thar would be nice
@sinom11 күн бұрын
What do you nean "you don't need that dx"... There are only very, very few cases where you can use the Integration sign without the dx and this isn't one of those cases (at least without furst defining what you mean)
@ron-math11 күн бұрын
I was cheating: changing the context of conventional integral to operator.
@jakubk.41711 күн бұрын
This is my new favorite video on YT not gonna lie. I was laughing the whole way through out-loud. Yes, I am weird
@CliffSedge-nu5fv12 күн бұрын
Everything is an operator if you're lazy enough.
@55hzdxlh7312 күн бұрын
what did i just see???
@edmundkemper162512 күн бұрын
Subbed for the title. :))
@MDNQ-ud1ty12 күн бұрын
(1 - I)^(-1) = 1/(1 - I) = 1/(1 - 1/D) = D/(D - 1) f = D/(D-1)g ==> (D-1)f = Dg ==> f' - f = g' if g is a constant then f' - f = 0 ==> f' = f which one can define e^x to be the solution.