Dr. McCord

Пікірлер

@zahrabatool4280 8 күн бұрын

Thank you❤

@obama2523 11 күн бұрын

But where is this teacher currently?? I expected a million subscribers

@rahulsk-x9c4f 13 күн бұрын

tq for video

@Sarah-q7s2f 20 күн бұрын

What if the elements are not balanced like there more mn in one side one with oxygen

@Yourdetailcollector7799 Ай бұрын

🔥💪

@AbdulHakimAbidCCREATIONS Ай бұрын

WIll water always form in all the equations? If I am balancing other chemical equations?

@JohnLivanos-y7l 2 ай бұрын

hey sir I'm no mathematician but i believe you accidentally did ln(initial/final) and not final/initial for part c

@Robby74u 2 ай бұрын

This too simplified a student new to this won't get anything

@Orlu2k Ай бұрын

That why people should coke to this video after learning it a bit in class so they have a basis 👌🏾👌🏾👌🏾

@tej8358 2 ай бұрын

Thank you sir!!

@Supreeth9889 2 ай бұрын

Sir you explained very well sir I understood very easily

@gyanaranjansahoo8440 2 ай бұрын

very nice explaination

@OdoguPhilip 2 ай бұрын

I don't understand

@sanemi74 2 ай бұрын

Use this 🧠

@OdoguPhilip 2 ай бұрын

How is manganese +7

@BrainBustr Ай бұрын

Was wondering too buh Mn often uses +2 or +7. It all depends on the compound it's part of

@yashashbodalkar580 2 ай бұрын

Just straightforward, no time stalling and yapping, thanks a lot

@kleopaskornelius 3 ай бұрын

You saved my day Thank you so much

@sun7989 3 ай бұрын

You just did this better than my teacher tysm

@EdnaAchieng-e5r 2 ай бұрын

😂😂😂

@Mahesh_2800 4 ай бұрын

thank you sir

@Julux_28 4 ай бұрын

Wow, thank you so much!! I understand it so well now :)

@stacksborrow1510 5 ай бұрын

Dr McCord you just balanced my grade! Thank you sir!

@محمدبنوالي-ظ2ح 6 ай бұрын

Was pretty helpful

@BenedictaElgba 6 ай бұрын

You don't know how to teach 👎

@Jaqueveonthesecond 6 ай бұрын

thank you so much saved me for finals

@theyouproject 6 ай бұрын

where did u get the oxidation number of Mn

@Mohamed___Adhil___ 6 ай бұрын

The oxidation no. for one oxygen is -2 ..for 4 oxygen is -8 and a negative ion above the oxygen should be added so that -8+1=-7 .....therefore mn 7+

@theyouproject 6 ай бұрын

@@Mohamed___Adhil___ oww get it, tnx

@Mohamed___Adhil___ 6 ай бұрын

@@theyouproject welcome

@abel_kidus 7 ай бұрын

This method looks very similar to the ion electron method

@yesyes-vt9eg 7 ай бұрын

that was clear and extremely helpful with the steps. thank u

@orangecaprinun 7 ай бұрын

SOMEBODY HELP! @ 0:55 If there isn't the same number of atoms of species that are not O or H like in: N2O4 + Br^- > NO2^- + BrO3^- What do i do??? i tried just multiplying NO2^- times 2 without changing anything else including the difference in oxidation numbers (+4 - +3 = -1), and the other difference of Br being -1 - +5 = -6, i ended up having to multiply the reduction half reaction by 6, so 6N2O4 and 6(2NO2^-) = 12NO^-, but eventually the charges on the two sides did not match taking into account the protons and all

@Mohamed___Adhil___ 6 ай бұрын

Bro/sis ....it can be easily done by the ion electron method....try it

@christiansinamano4827 8 ай бұрын

thank you bro. you just saved my average

@vanitasz 8 ай бұрын

Thank you🙏🏿🙏🏿

@swagcookie_xo6243 8 ай бұрын

How do you know which oxidation to use?

@indranilsingh2682 6 ай бұрын

If you mean the oxidation number then you'll have to find the oxidation number of each molecule. First you'll have to learn how to find out oxidation number then you can balance chemical equations using his method .