Use the equation 𝑑𝑧/𝑑𝑥=−𝐹_𝑥/𝐹_𝑧 and 𝑑𝑧/𝑑𝑦=−𝐹_𝑦/𝐹_𝑧 to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦.
2:04
Use the equation 𝑑𝑧/𝑑𝑥=−𝐹_𝑥/𝐹_𝑧 and 𝑑𝑧/𝑑𝑦=−𝐹_𝑦/𝐹_𝑧 to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦.
Use the equation 𝑑𝑦/𝑑𝑥=(−𝑑𝐹/𝑑𝑥)/(𝑑𝐹/𝑑𝑦)=−𝐹_𝑥/𝐹_𝑦 to find 𝑑𝑦/𝑑𝑥.7𝑦𝑐𝑜𝑠(𝑥)=𝑥^2+𝑦^2
2:04
Use the equation 𝑑𝑦/𝑑𝑥=(−𝑑𝐹/𝑑𝑥)/(𝑑𝐹/𝑑𝑦)=−𝐹_𝑥/𝐹_𝑦 to find 𝑑𝑦/𝑑𝑥.7𝑦𝑐𝑜𝑠(𝑥)=𝑥^2+𝑦^2
Use the equation 𝑑𝑦/𝑑𝑥=(−𝑑𝐹/𝑑𝑥)/(𝑑𝐹/𝑑𝑦)=−𝐹_𝑥/𝐹_𝑦 to find 𝑑𝑦/𝑑𝑥.5𝑦𝑐𝑜𝑠(𝑥)=𝑥^2+𝑦^2
2:04
Use the equation 𝑑𝑦/𝑑𝑥=(−𝑑𝐹/𝑑𝑥)/(𝑑𝐹/𝑑𝑦)=−𝐹_𝑥/𝐹_𝑦 to find 𝑑𝑦/𝑑𝑥.5𝑦𝑐𝑜𝑠(𝑥)=𝑥^2+𝑦^2
Use the chain rule to find the indicated partial derivatives
5:29
Use the chain rule to find the indicated partial derivatives
Use the chain rule to find the indicated partial derivatives
4:59
Use the chain rule to find the indicated partial derivatives
2 сағат бұрын
Use the chain rule to find the indicated partial derivatives
4:58
Use the chain rule to find the indicated partial derivatives
2 сағат бұрын
Use the chain rule to find the indicated partial derivatives
3:59
Use the chain rule to find the indicated partial derivatives
2 сағат бұрын
Use the chain rule to find the indicated partial derivatives
3:59
Use the chain rule to find the indicated partial derivatives
2 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=tan⁡(𝑢/𝑣) 𝑢=2𝑠+4𝑡, 𝑣=4𝑠−2𝑡
3:30
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=tan⁡(𝑢/𝑣) 𝑢=2𝑠+4𝑡, 𝑣=4𝑠−2𝑡
2 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=tan⁡(𝑢/𝑣) 𝑢=4𝑠+5𝑡, 𝑣=5𝑠−4𝑡
3:29
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=tan⁡(𝑢/𝑣) 𝑢=4𝑠+5𝑡, 𝑣=5𝑠−4𝑡
2 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=𝑒^𝑟 cos⁡(𝜃) 𝑟=𝑠𝑡, 𝜃=√(𝑠^8+𝑡^8 )
3:30
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=𝑒^𝑟 cos⁡(𝜃) 𝑟=𝑠𝑡, 𝜃=√(𝑠^8+𝑡^8 )
7 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=𝑒^𝑟 cos⁡(𝜃) 𝑟=𝑠𝑡, 𝜃=√(𝑠^6+𝑡^6 )
3:29
Use the chain rule to find 𝑑𝑧/𝑑𝑠 and 𝑑𝑧/𝑑𝑡 𝑧=𝑒^𝑟 cos⁡(𝜃) 𝑟=𝑠𝑡, 𝜃=√(𝑠^6+𝑡^6 )
7 сағат бұрын
Use the chain rule to find 𝑑𝑤/𝑑𝑡 𝑤=ln⁡(√(𝑥^2+𝑦^2+𝑧^2 )), 𝑥=9sin⁡(𝑡), 𝑦=6cos⁡(𝑡), 𝑧=4tan⁡(𝑡)
2:59
Use the chain rule to find 𝑑𝑤/𝑑𝑡 𝑤=ln⁡(√(𝑥^2+𝑦^2+𝑧^2 )), 𝑥=9sin⁡(𝑡), 𝑦=6cos⁡(𝑡), 𝑧=4tan⁡(𝑡)
7 сағат бұрын
Use the chain rule to find 𝑑𝑤/𝑑𝑡 𝑤=ln⁡(√(𝑥^2+𝑦^2+𝑧^2 )), 𝑥=6sin⁡(𝑡), 𝑦=2cos⁡(𝑡), 𝑧=3tan⁡(𝑡)
2:59
Use the chain rule to find 𝑑𝑤/𝑑𝑡 𝑤=ln⁡(√(𝑥^2+𝑦^2+𝑧^2 )), 𝑥=6sin⁡(𝑡), 𝑦=2cos⁡(𝑡), 𝑧=3tan⁡(𝑡)
7 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=sin⁡(𝑥)cos⁡(𝑦), 𝑥=√𝑡, 𝑦=7/𝑡
1:33
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=sin⁡(𝑥)cos⁡(𝑦), 𝑥=√𝑡, 𝑦=7/𝑡
7 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=sin⁡(𝑥)cos⁡(𝑦), 𝑥=√𝑡, 𝑦=6/𝑡
1:33
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=sin⁡(𝑥)cos⁡(𝑦), 𝑥=√𝑡, 𝑦=6/𝑡
7 сағат бұрын
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=𝑥𝑦^9−𝑥^2 𝑦, 𝑥=𝑡^2+1, 𝑦=𝑡^2−1
1:33
Use the chain rule to find 𝑑𝑧/𝑑𝑡 z=𝑥𝑦^9−𝑥^2 𝑦, 𝑥=𝑡^2+1, 𝑦=𝑡^2−1
7 сағат бұрын
Find all the second partial derivatives.𝑇=𝑒^(−3𝑟) cos⁡(𝜃)
2:59
Find all the second partial derivatives.𝑇=𝑒^(−3𝑟) cos⁡(𝜃)
9 сағат бұрын
Use polar coordinates to find the limit.
2:27
Use polar coordinates to find the limit.
9 сағат бұрын
Find the indicated partial derivatives𝑓(𝑥, 𝑦, 𝑧)=𝑒^(𝑥𝑦𝑧^7 ); 𝑓_𝑥𝑦𝑧
2:59
Find the indicated partial derivatives𝑓(𝑥, 𝑦, 𝑧)=𝑒^(𝑥𝑦𝑧^7 ); 𝑓_𝑥𝑦𝑧
9 сағат бұрын
Find the indicated partial derivatives𝑓(𝑥, 𝑦)=𝑥^6 𝑦^7−𝑥^5 𝑦^6; 𝑓_𝑥𝑥𝑥; 𝑓_𝑥𝑦𝑥
2:59
Find the indicated partial derivatives𝑓(𝑥, 𝑦)=𝑥^6 𝑦^7−𝑥^5 𝑦^6; 𝑓_𝑥𝑥𝑥; 𝑓_𝑥𝑦𝑥
9 сағат бұрын
Find the indicated partial derivatives𝑓(𝑥, 𝑦)=𝑥^6 𝑦^5−𝑥^5 𝑦^4; 𝑓_𝑥𝑥𝑥; 𝑓_𝑥𝑦𝑥
2:59
Find the indicated partial derivatives𝑓(𝑥, 𝑦)=𝑥^6 𝑦^5−𝑥^5 𝑦^4; 𝑓_𝑥𝑥𝑥; 𝑓_𝑥𝑦𝑥
9 сағат бұрын
Find all the second partial derivatives.𝑇=𝑒^(−4𝑟) cos⁡(𝜃)
2:59
Find all the second partial derivatives.𝑇=𝑒^(−4𝑟) cos⁡(𝜃)
9 сағат бұрын
Find all the second partial derivatives.𝑓(𝑥, 𝑦)=𝑥^4 𝑦−4𝑥^3 𝑦^2
2:28
Find all the second partial derivatives.𝑓(𝑥, 𝑦)=𝑥^4 𝑦−4𝑥^3 𝑦^2
9 сағат бұрын
Find all the second partial derivatives.𝑓(𝑥, 𝑦)=𝑥^6 𝑦−4𝑥^3 𝑦^2
2:29
Find all the second partial derivatives.𝑓(𝑥, 𝑦)=𝑥^6 𝑦−4𝑥^3 𝑦^2
9 сағат бұрын
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑒^2𝑧=𝑥𝑦𝑧
4:35
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑒^2𝑧=𝑥𝑦𝑧
9 сағат бұрын
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑒^4𝑧=𝑥𝑦𝑧
4:35
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑒^4𝑧=𝑥𝑦𝑧
9 сағат бұрын
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑥^2+8𝑦^2+3𝑧^2=5
4:35
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑥^2+8𝑦^2+3𝑧^2=5
9 сағат бұрын
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑥^2+2𝑦^2+5𝑧^2=8
4:35
Use implicit differentiation to find 𝑑𝑧/𝑑𝑥 and 𝑑𝑧/𝑑𝑦𝑥^2+2𝑦^2+5𝑧^2=8
9 сағат бұрын
Пікірлер
@MathTrick-t7v
@MathTrick-t7v 2 күн бұрын
I like it
@favoritemath
@favoritemath 2 күн бұрын
Thank you for your comment
@tommysalami420
@tommysalami420 3 күн бұрын
7/10 not doing your homework again XD
@favoritemath
@favoritemath 3 күн бұрын
Answer 7/10 is correct. You may need to write your answer in a different form. Because, when x→1 answer is 7/10, and also when y→1 answer is 7/10. ​ .
@abhisheksoni9774
@abhisheksoni9774 5 күн бұрын
Keep doing 🎉❤
@favoritemath
@favoritemath 5 күн бұрын
Thank you for your comment
@caldersheagren
@caldersheagren 5 күн бұрын
I don’t think this is sufficient to show that the limit exists. You need polar coordinates since the limit needs to agree for any arbitrary path
@nicholasjensendemattos150
@nicholasjensendemattos150 6 күн бұрын
Polar coordinates work nicely here
@favoritemath
@favoritemath 6 күн бұрын
Thanks for your comment
@rodabaixo13
@rodabaixo13 6 күн бұрын
Yeah. A lot more intuitive
@favoritemath
@favoritemath 6 күн бұрын
@rodabaixo13 Thanks for your comment
@jshack_2334
@jshack_2334 11 күн бұрын
Thank you!
@favoritemath
@favoritemath 11 күн бұрын
You're welcome!
@MathTrick-t7v
@MathTrick-t7v 11 күн бұрын
I like it ❤
@favoritemath
@favoritemath 11 күн бұрын
Thanks for your comment
@matthewwinski3650
@matthewwinski3650 15 күн бұрын
So, why is it negative t? I can't find an answer for why t/theta would be negative
@favoritemath
@favoritemath 11 күн бұрын
We use negative t to ensure the boundary curve is traversed counterclockwise when viewed from the positive y-axis.
@beetogarcia9983
@beetogarcia9983 Ай бұрын
What did you do for r(t)?
@favoritemath
@favoritemath Ай бұрын
x^2+z^2=16. This equation describes a circle in the xz-plane, with a radius 4 and centered at the origin (0, 0, 0). To describe the circle mathematically, we use a standard method to parameterize circles where x = r*cos(t) and z = r*sin(t) (r=4, t is the parameter (angle) that varies from 0 to 2𝜋). So, 𝑟(𝑡)=4cos⁡(𝑡)𝑖−4sin⁡(𝑡)𝑘, 0≤𝑡≤2𝜋
@ZDTF
@ZDTF Ай бұрын
Wut
@reindeer4274
@reindeer4274 Ай бұрын
This is something you'll need to know how to do if you end up taking Calc 3
@ZDTF
@ZDTF Ай бұрын
@reindeer4274 bro I'm not even in high school yet
@ZDTF
@ZDTF Ай бұрын
I'm high in school
@reindeer4274
@reindeer4274 Ай бұрын
@@ZDTF Yes, so dont worry too much if its not clicking yet
@favoritemath
@favoritemath Ай бұрын
Thanks for your comments
@ep_ha
@ep_ha 2 ай бұрын
Thanks 😊
@favoritemath
@favoritemath 2 ай бұрын
I'm glad I could help
@jnstud3nt
@jnstud3nt 2 ай бұрын
So helpful and concise!
@favoritemath
@favoritemath 2 ай бұрын
Glad it was helpful!
@dodrickquintero7702
@dodrickquintero7702 2 ай бұрын
Thanks for the video, was stuck on a similar problem 👌🏽
@favoritemath
@favoritemath 2 ай бұрын
Glad it helped
@swanda_art
@swanda_art 3 ай бұрын
Thanks!
@favoritemath
@favoritemath 3 ай бұрын
Welcome!
@SussySusan-lf6fk
@SussySusan-lf6fk 3 ай бұрын
Plz share the music
@favoritemath
@favoritemath 3 ай бұрын
kzbin.info/www/bejne/roKzZnlsaKuBorcsi=Z8hXL73MwbSHLxYM
@SussySusan-lf6fk
@SussySusan-lf6fk 3 ай бұрын
@@favoritemath thank you. Your math + your music = excellent
@JoaoVictor-mn6cr
@JoaoVictor-mn6cr 3 ай бұрын
@favoritemath
@favoritemath 3 ай бұрын
Thanks for your comment. :)
@porridge762
@porridge762 3 ай бұрын
Why is a a plane
@favoritemath
@favoritemath Ай бұрын
Thanks for your comment
@shomst7904
@shomst7904 3 ай бұрын
Thank you. Stupid textbook doesn't include answers.
@favoritemath
@favoritemath 3 ай бұрын
You are welcome
@HeroesAlan
@HeroesAlan 3 ай бұрын
r(x) = <x, x^2>, r'(x) = <1, 2x> r'(2) = <1,4>, normalize we get <1,4>/sqrt(17)
@favoritemath
@favoritemath 3 ай бұрын
Thank you for your comment.
@646Aoo
@646Aoo 3 ай бұрын
😢?4+5+8+9+3+9+2+9+9😮?
@karinadelossantos3429
@karinadelossantos3429 3 ай бұрын
So glad I came across your channel, I love how short and straight to the point it is. It is very helpful to someone who needs a little reassurance on problems. Your work is not in vain.
@favoritemath
@favoritemath 3 ай бұрын
Thank you.
@yourmom696
@yourmom696 4 ай бұрын
this helped me so much thank you
@jt1380
@jt1380 4 ай бұрын
thanks
@favoritemath
@favoritemath 4 ай бұрын
You're welcome!
@Cberdz
@Cberdz 4 ай бұрын
Webassign says it's wrong
@favoritemath
@favoritemath 4 ай бұрын
Hi. Try writing the answer as 1/9 (4i - j + 8k). If the answer is wrong, ask your teacher why?
@Nodiddy-ir3lj
@Nodiddy-ir3lj 6 ай бұрын
great video! on my hw need to fix title so people can find easier! or make a section playlist
@favoritemath
@favoritemath 5 ай бұрын
Ok thanks!
@archangecamilien1879
@archangecamilien1879 7 ай бұрын
It was something like |a|x|b|x cos(angle), lol...
@favoritemath
@favoritemath 5 ай бұрын
Thanks for your comment
@mekaindo
@mekaindo 7 ай бұрын
"Find a•b" "Ok." "|a|=8, |b|=6" "Then uhh a•b=+-48" "The angle between a and b is 30°." "Wait wha-"
@chickenwing3946
@chickenwing3946 7 ай бұрын
My reaction exactly
@favoritemath
@favoritemath Ай бұрын
This is because |a| and |b| are lengths. Length is always positive.
@favoritemath
@favoritemath Ай бұрын
Thanks for your comment
@Mashupbeats1729
@Mashupbeats1729 7 ай бұрын
bro if u give grade 12 maths calculus i can solve . these are too high for me
@favoritemath
@favoritemath 7 ай бұрын
I know this is too high for 12th grade because these problems are for Calculus III. I later will be publish tasks for Calculus I and Calculus II. Good luck.
@SussySusan-lf6fk
@SussySusan-lf6fk 7 ай бұрын
I like your channel Sir. I'm a teen who wants to learn more math. Your channel is a gem for me and my friends. Thank you 😊
@favoritemath
@favoritemath 7 ай бұрын
Glad to hear that.
@Mashupbeats1729
@Mashupbeats1729 7 ай бұрын
bro if u upload class12 mathematics problems i will definetly try
@favoritemath
@favoritemath 5 ай бұрын
Thanks for your comment
@Mashupbeats1729
@Mashupbeats1729 7 ай бұрын
i only know stokes law in physics . wtf is this ?/
@favoritemath
@favoritemath 7 ай бұрын
Stokes' theorem is part of the Surface Integrals subtopic in Calculus III
@Mashupbeats1729
@Mashupbeats1729 7 ай бұрын
@@favoritemath god dam will learn later btw i am only in 12th grade
@favoritemath
@favoritemath 7 ай бұрын
You still have everything ahead of you. Good luck.