Honestly, it would guarantee that you've landed on the middle value, so it's a smart move! But most (non-evil) instructors will have enough wiggle room that simply looking for 50%*n or 25%*n will land you in the correct interval for the median or Q1.

Dude help me I am taking stats ap in high school and this is bad

Ah, I just pressed the little wheel thing to use the right arrow. Once I did the square, my cursor was still in the exponent. But pressing 'right' I moved out of the exponent and down into where I wanted to do +3x. Otherwise, I just used the +/- operations on the right in silver to add the 3x and subtract the 7

@@KellySpoon Oh okay, thank you for the quick response. I am completely unfamiliar with this graphing calculator and thought you had done something different.

Good luck!

You can find derivatives at a point in the 36X Pro with the button right below 2nd: "d/dx [ ]". I haven't tried to put them into the table function to see if it will give me the derivative at multiple points.

Looks like you understood this, Tyrin! But for anyone who stumbles onto this comment later - the way I figure out "not all" questions is to consider what "all" is and then realize not all is everything else!

This is why finding median on a histogram is a bit silly. We can't write the actual value. Most professors would want you to write that the median falls in the interval [6, 8) as we have no idea where in that interval the median lies.

@@KellySpoon oh thank you for the response. I get it now.

Ah! Because there are two ways that can happen: damaged first, then not damaged OR not damaged first, then damaged - the probabilities will always be the same for either situation, so we can either add them together (since option 1 OR option 2 would result in 1 damaged tire and OR problems are addition problems in probability)... or we can shortcut that, only calculate one of them and multiply by 2 for the two ways the event can happen.

Mathematically, "or" is additive! I would give you most of the points for a problem like that on an exam - probably 3 out of 4 possible. Though with the online exam, you'd only have one blank, so that might push you towards combining the number in either category. :)

@@KellySpoon Understood! Thanks :)

For the example of 46 students, would it be easier if you just have all the students to respond and take the first 10 students who responded from the respond list?

What do you mean? All the notes are on Canvas in the lecture note button?

Exactly. You will end your whisker at that first data value inside the fence and mark that min or max (and any other values outside the fences) as outliers using open circles or asterisks.