Thank you sir, this was exactly what I was looking for.

14:56

Hello sir are u a left hander?

The author of cengage mathematics☠️

I wish he would only speak english.

Answer is 53

Itni deeply aaj tak kisi ne nhi samjhaya sir masters kar li thanku soo much sir and aapki book really bhut helpful hai

sir aap time nikalke hmare liye itna krte hain bahut bahut dhanyavaad , i love u , IIT i am coming

OG love ur books sir❤

thank u sir

In the first problem please use if mod Z is equal to 1 then conjugate of Z is 1/Z

From the equation of the graph what we get .?

25,26,27,28,31,32

Sir in word question why don't consider the letter to be repeated

Air 247 ❤❤

Excellent. . pls help like this regular basis

No one can match ur quality ❤

thanks sir

thanks sir

thanks sir

Sir would the lectures in cengage course in hindi or in english

Teacher behind the screen....I didn't like this idea

Great teacher.

Today 2024

Better than BW lectures No time waste

GOD of nishant jindal🙂

Proof for remainder theorem

You are God. Now I am addicted to maths can't live without maths

Sir love your lectures i have one question how to you write is that a glass or something what is it

Sir apne video me apne hi illustration le rhe hai😅

Thank you so much !!

Great Great Explanation 🎉

thank you mr tewani

Is he the only author of cengage maths?

Lajawab explaination sir I want a teacher like u who satisfies jee students

❤Sir how much years u have devoted to complete these books ....really amazing sir ji

29:53 case 5k+2 only 19 aa rahe sir

Main aim to learn the equation of plane in different forms

Cube roots of unity ki rectangular form hoti hy??

Thanks alot for this.

Thank you sir for making this video Because I am troubling with a question based on this

Understood very well i m from kota par thoda aur ache se jaana tha muje

god

i think my approach is right correct if im wrong. eccentricity is constant throughout the ellipse to maintain that particular locus. which is that said ellipse. each angle from the focus to point p must make an angle of theta with the major axis for the point p to be described as (acost, bsint) now we know both angles are the same. thus we can say that 2theta+some angle at p=180 degrees by line properties. now we have a ray from focus1 hitting point p. angle of incidence must be angle of reflection due to constant eccentricity as thus the angle of incidence will also be theta. at the tangent at p, the angle of incidence will be equal to angle of reflection. introducing a normal we notice that we get a 90 degree angle as its orthogonal to tangent and then theta and some angle beta. now theta and beta must be 90 degrees as angles on a line are 180 if summed. hence the normal MUST bisect the angle 2beta into 2 beta angles to maintain the eccentricity of the ellipse and property of reflection. this is a direct consequence of theose two properties. hence any normal to a tangent will bisect the two meeting focal lines at P. Now please it is a long read but do tell if i am correct in my formulation or not. this is merely a consequence of symmetry. its very informal though.

Sir please check in 2nd problem no of terms are 10..not 20 in gp series

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Most accurate teacher

Why the fk this video is not popular ... salute u sir .. u give content better than my coaching .. and i m also solving ur book for my iitjee 2025 journey😊

Legend G.T sir... Author of maths cengage ❤

very nice explanation sir