I'm learning how to do this math and I don't know where to start. I didn't have the best public education and I'm starting from scratch. Do you have any recommendations for books I can order?
@jacobphiri19443 ай бұрын
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@Eiser_grayon3 ай бұрын
thanks for the explanation
@NyamaiLiah6 ай бұрын
Thanks
@Paula-lt3ev6 ай бұрын
Dietetics student here 😊 . Your videos are excellent. Very helpful.
@mamtalall6750 Жыл бұрын
Thank you so much. Excellent simplified explanation.
@rahafrahaf73886 Жыл бұрын
Thank you
@osmirod1 Жыл бұрын
IMPORTANT QUESTION: in what situation if ever are you able to solve for one of the two variables on the right side of the equation, that is, either c2 or v2?
@IWusHErE3032 жыл бұрын
Bro thank you I had to make a dilution lab and I forgot how this works you saved my butt thank you!
@uniteamerica94462 жыл бұрын
Thank you. I'm diluting rooting hormone to soak green giant arborvitae tree cuttings overnight. Now I know how to dilute my stock solution. I will successfully root my tree cuttings and sell them next year. You helped me make money grow on trees. Money really does grow on trees if you propagate and sell the right ones. Propagate and sell screening plants, hedge plants and ground covers. People usually by a lot more than 1 of these type of plants,
@rottenapple22762 жыл бұрын
The mitochondria is the powerhouse of the cell
@kamlablake67532 жыл бұрын
are the parents male or female i am confused as hell
@Alice444V2 жыл бұрын
very helfpul and clear thanks!
@musamohammedmaud24972 жыл бұрын
you’re indeed a man of your words #Dr.Ani John on KZbin, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery
@annusharma40163 жыл бұрын
Thank you 🙏🙏🙏
@musamohammedmaud24972 жыл бұрын
you’re indeed a man of your words #Dr.Ani John on KZbin, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery
@mohfa18063 жыл бұрын
Hello and thank you for your great videos , i have a question please : when diluting a weak acid i noticed in the book that they use the dilution formula :C1V1=C2V2 based on the fact that the number of moles will stay constant , however for weak acid we know that upon adding water the dissociation of the weak acid increases to maintain balance and hence the number of moles of the weak acid decreases , so based on that how the dilution formula still applied?...thank you in advance.
@beautyqueen5002 Жыл бұрын
The number of moles of weak acid does not change upon dilution because the dissociation of the weak acid in water is a reversible process. As the weak acid dissociates in water, it produces hydronium ions and the conjugate base of the acid. The concentration of hydronium ions increases, which increases the acidity of the solution and causes the weak acid to dissociate less. This is known as the common ion effect. When the weak acid is diluted with water, the total number of moles of the acid remains constant, but the volume of the solution increases. This results in a decrease in the concentration of the weak acid, which in turn decreases the concentration of hydronium ions in the solution. As a result, the dissociation of the weak acid increases to maintain the equilibrium concentration of hydronium ions. However, the increase in dissociation upon dilution is small compared to the total amount of weak acid present, and the total number of moles of the weak acid remains essentially constant. The dilution equation, C1V1=C2V2, assumes that the number of moles of solute remains constant upon dilution, which is generally true for weak acids and bases.
@douglasheinl2503 жыл бұрын
Great video, thank you.
@wilmerpadron36223 жыл бұрын
You said early that you can't cancel unit's but later you do
@anamshehzadi56953 жыл бұрын
clearly explained
@devikanair443 жыл бұрын
I don’t imagine you’ll see this comment but I am a bit confused with negative control. You said if you remove the IV then you don’t get the DV. but in the situation with the bugs and meat the cover was the IV so if you removed it you’d get an effect no?
@ashrafshahrour66983 жыл бұрын
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@SachinSingh-xg8gg4 жыл бұрын
Thanks
@anitatiwari86884 жыл бұрын
Ty so much ....it helped me allot sir....keep it up ...make more helpful videos for us ...❤❤☺
@Cosmuex4 жыл бұрын
"Scientist who guess are unemployed" lmaoo
@Dr-Garry4 жыл бұрын
In our institute we take AP chemistry and I am just in grade 9-ASP( Advanced Science program)
@leslieenriquez40854 жыл бұрын
I just have trouble knowing what’s the c1 v1 and c2 v2 word problems confuse me 😥
@slaygoddesscarol5733 Жыл бұрын
Same problem
@axtonjay31625 жыл бұрын
why is this so confusing????
@dejaharris735 Жыл бұрын
literally didnt even write out the problem worked. Wish these tutors would go more in depth! Lazy
@mangsialthang5855 жыл бұрын
So useful 🙂
@toneshav3405 жыл бұрын
I thought Ketone has an attached Hydrogen not carbon ...
@tinnesarmin32585 жыл бұрын
U r superb
@arpanalimbu91455 жыл бұрын
Thanksss
@tezadoctorat73575 жыл бұрын
Hey. Unfortunately the dilution equation can be applied only on molar concentrations. See Skoog : Fundamentals of analytical chemistry, 9th edition. page 75. " This equation is based on the fact that the number of moles of solute in the diluted solution must be equal the number of moles in the concentrated reagent.' For example: Let's say that you want to prepare 1 L of 15% H2SO4 solution (density: 1.095 g/mL) from 60 % H2SO4 (density 1.498 g/mL). We have to find out the volume needed. If we use the dilution equation we get that we need 250 mL of 60% H2SO4, but if we calculate correctly we obtain that we actually need only 182.7 mL. Here is the correct calculation: 15% means that 15 g H2SO4 is in 100 g solution. Using its density we calculate the solution's volume, that is V=m/d=100/1.095=91.32 mL. Next we calculate the amount of pure H2SO4 that is in 1L=1000 mL solution, which is going to equal 164.25 g pure H2SO4. Than we say that 60 g H2SO4 is in .......100 g solution 164.25 g H2SO4.........x = 273.76 g solution. And finally we transform the obtained mass into volume using it's density and the formula given earlier, so we get 182.7 mL, instead of 250 mL that we would get using the dilution equation.
@ravikumarvitthala29505 жыл бұрын
very true!
@wat84376 жыл бұрын
Is this principle used in the manufacture of IV pharmaceutical solutions? They probably are since there's not much room for error
@penderchovwe3516 жыл бұрын
Thanks a lot
@nadifomuse5126 жыл бұрын
Thanks a lot
@mestudy60496 жыл бұрын
amazing! cleared out my doubt! thank u!
@sydneea97716 жыл бұрын
Why didn't you finish the serious of 4 😞 your videos really helped me! I need one on proteins at this moment in time.
@makuchii16 жыл бұрын
thank you this video helped me a a lot !
@vandam76566 жыл бұрын
very good explanation
@whelanylime7 жыл бұрын
I HAVE BEEN TRYING TO FIGURE OUT MY THREE POINT TEST CROSS PROBLEM FOR 3 HOURS AND YOU HAVE SAVED ME
@tanisha26597 жыл бұрын
how to find c2/vs
@yonasiloma27717 жыл бұрын
Language use English
@mailewilkey94917 жыл бұрын
In my school we take biology freshman year and chemistry sophomore lol
@sierraslyh67437 жыл бұрын
Actually I dont think the mistake at 12:56 was that you forgot to cross v and v+. I think you had them switched before they crossed because the results, CV-CT-V and +-+-+ matches the result from the table of values for 89 and 94. Great video, though! Thsnks!
@lynnecota91038 жыл бұрын
So helpful!
@GameCritics78 жыл бұрын
you need better audio, just a recommendation
@salmael_badry29268 жыл бұрын
but ,sodium and potassium are positive charged ions How can the equilibrium potential of sodium positive charged and that of potassium is negative? explain ,please.