In 2 hrs

Actually, they're right. I almost made that same mistake lol You're absolutely right with your logic however, the PC is incremented right before so you take your -256 through +255 and add you're +1 from the PC and you get -255 through +256.

the result: for exampe for AND, whether the two Inputs (from the source Registers) are equal and for ADD the sum of the two inputs. For instructions like LD, the value that you want to get from memory is stored in the destination register. The values either come from a computation by the ALU (add, and, or, Sub, etc etc) or come from memory (ld, ldr, ldi, lea etc)

how

@@rampage14x13 how

Compare what?

yes he would

LC-3 use Not instead of shifting !!

hahaha it's pretty late but you can use DeMorgan's theorem which says: A OR B = A' AND B'

its A OR B = NOT( NOT(A) AND NOT(B) ) actually

cuz it is. The memory of the LC-3 has 2^16 bit address space and 16 bit addressability (so we have a 65536 identifiable unique locations and 16 bit in each one) In a short we can spell 65536(2^16) like a 64k

That's what LDI is supposed to do, which is fetching the content of another location in the memory, read that content as another address, and store the content of that newly found address. Think of it as a treasure map, you were told to go to a location, you get there, you find a new hint that tells you where the treasure actually is, and you go to where the hint tells you to, and finally found the treasure.