Computer&Electronics

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@emiledvardsson6958 2 күн бұрын

Thank you, this saved me so much time.

@Computer-and-Electronics Күн бұрын

You're welcome!

@edwardteyssier2357 7 күн бұрын

You need to indicate the "Q" output and the "CLR" inputs on your FF boxes.

@Computer-and-Electronics 7 күн бұрын

You're right

@nahuaatr 9 күн бұрын

grazie mille frate buon video

@Computer-and-Electronics 8 күн бұрын

Prego

@Aboflah11930 9 күн бұрын

جيد جداً وشرح ممتاز

@Computer-and-Electronics 9 күн бұрын

Thank you

@protools4fools 13 күн бұрын

Thank you very much! Very helpful videos.

@Computer-and-Electronics 12 күн бұрын

You are welcome!

@Geovani-g4x 13 күн бұрын

You are great and oppressed at once . Where are you from?

@Computer-and-Electronics 13 күн бұрын

Italy

@ooo-pe2gc 13 күн бұрын

I am trying to build this circuit, but I'm having difficulties implementing it with the commercially available components. It seems that I might not be able to achieve the proper biasing conditions. I used BC556B and BC547B transistors. What should I do?

@Computer-and-Electronics 13 күн бұрын

Hi, try to find some clues from the Evil mad scientist kit for the 741. shop.evilmadscientist.com/productsmenu/762. They use 2N3904 and 2N3906 as transistors.

@Dosomeboutit 19 күн бұрын

no one recommended fr was searching for it - wow

@ve2zzz 20 күн бұрын

Excellent explanation !!! ...and I've just learned that unlike most of today's op-amps which use two individual emitter followers feeding a classic differential pair having emitters sharing a common current, 741's input diff uses two CC transistors followed by a common-base amplifier. Thanks for improving my knowledge !

@Computer-and-Electronics 20 күн бұрын

Thank you. I am glad you like it. Yes at the time PNP were poor and opamp needs high beta to lower the base current (input current of op-amp), so Fullagar had to use npn and figure out the right configuration to improve gain and to lower input capacitance

@cryptocsguy9282 23 күн бұрын

1:09 You made a mistake and it's 23-18 = 5 not 2 so bring down the final 0 = 50 then 50/9=5 so the final answer for 2030/9 = 225 not 222 ignoring remainders

@Computer-and-Electronics 23 күн бұрын

You're right. Incredible mistake...

@slnkomada9102 24 күн бұрын

Does anyone have the link of CircuitVerse for the circuits?

@Computer-and-Electronics 23 күн бұрын

Unfortunately the circuit I used for the video is now useless. I changed some blocks for the series about the adders and the division circuit doesn't work anymore. kzbin.info/www/bejne/jZ6sd3mef76thZI

@slnkomada9102 22 күн бұрын

@ Oh, alright, thank you

@cryptocsguy9282 28 күн бұрын

The circuit shown between 11:18-12:33 is wrong it has too many XOR gates while the one you show afterwards is correct. Also if we use 2s complement to figure our minus numbers to add when doing binary subtraction why does the simulation software use regular unsigned numbers to help us get the correct answer ?

@Computer-and-Electronics 28 күн бұрын

Yes you're right. The XOR gate in the Cout Is wrong.

@user-oz5hi1px7e Ай бұрын

my fundamentals for mosfets seems to be lacking, could you please suggest any good resources to learn about the mosfets to know how these different configs of mosfet like 'current mirror' or trans-diode config. i only know the basics (i.e the drain current equation of mosfet, regions of operations). thank you so much

@Computer-and-Electronics Ай бұрын

Hi, I suggest you these books: CMOS Circuit Design, Layout, and Simulation, by Baker, Li, Boyce Design of Analog CMOS Integrated Circuits by Behzad Razavi

@Damnesia2 Ай бұрын

At 12:14, when mentioning the XOR on the carry out, did you intend to put an AND gate to AND the NOT'd SUB line with the carry out so that on subtraction the bit is dropped (so that it does the following: (NOT SUB) AND Cout7)? With the XOR the way it is on Cout, it is transparent for addition as you've stated, but for subtraction, it effectively performs a NOT instead of blocking it fully. Either way, the carry out should not be modified regardless, because if you want to attach 2 adders together to extend the number of bits, dropping that Cout will disable that ability. If you intend on finding whether the addition resulted in an overflow, you should XOR the carry in and carry out of the last FA which will give you an overflow bit that is accurate for both addition and subtraction in signed notation. Cout is only reliable for unsigned addition overflow, not signed.

@Computer-and-Electronics Ай бұрын

You are right the XOR in Cout Is wrong. Cout doesn't need any gate.

@adindajuwita3929 Ай бұрын

Gak jelas, apa nama komponennya!!!????

@Computer-and-Electronics Ай бұрын

Phase and frequency detector.

@maplinxxgd5234 Ай бұрын

great video! I like that you step through the math instead of "it just works lol"

@Computer-and-Electronics Ай бұрын

Thank you

@Thatguyyyouknow Ай бұрын

Great video.is there a software you would recommend for simulating these circuits?

@Computer-and-Electronics Ай бұрын

For digital circuit I usually use Circuitverse. It is free, online, but basic. For analog circuit I use LTspice. This is a mix of both. I didn't simulate It.

@bagaspramanaputrafadhila5921 2 ай бұрын

ＩＬＩＫＥ　ＩＴ

@Computer-and-Electronics 2 ай бұрын

Thank you

@nihatakdamar7711 2 ай бұрын

Can't the AND gate be made with 4 transistors? If you change the places of the high and low voltage sources in the NAMD gate. Or if you connect serial n transistors to the high voltage source and the parallel p transistors to the low voltage source.

@Computer-and-Electronics 2 ай бұрын

No, the n-MOS transitors are on with a logic one and must be below near the zero voltage. The p-MOS transistors must be above near the High voltage because they need a Logic zero to switch-on. You need a voltage difference between source and gate of the transistors and the positions matter in order to create such difference

@changed55555 2 ай бұрын

Nice explanation sir ,but informative channel alway have less views..

@Computer-and-Electronics 2 ай бұрын

Thank you. Please share the videos you like most.

@changed55555 2 ай бұрын

@@Computer-and-Electronics ok

@davidesaccon 2 ай бұрын

Best OP-Amp video ever! Way better than any book or uni lesson I ever came across. Thank you so much for making me understand all this!

@Computer-and-Electronics 2 ай бұрын

You are welcome. I am glad you like it. Please share this video with people you know may like it.

@jorgesantos6023 2 ай бұрын

Most definitely

@Computer-and-Electronics 2 ай бұрын

Thank you

@jason3307 2 ай бұрын

awesome explanation! thanks

@Computer-and-Electronics 2 ай бұрын

You're welcome

@AcidDotCom 2 ай бұрын

Best explanation of the circuit and how to build it. Saved me days of work. Thank you :)

@Computer-and-Electronics 2 ай бұрын

I am glad you like it

@S-a-m-m 3 ай бұрын

Is there any difference into using a multiplexor instead of a decoder?

@Computer-and-Electronics 3 ай бұрын

Yes there is, a mux is a device that selects one of several input signals and transmits it to a single output line. A decoder select Just One of the many outputs through a few control lines. In this case we want a decoder to select the right Memory cell

@SAhellenLily 3 ай бұрын

👍

@SAhellenLily 3 ай бұрын

Nice explanation!Sir👍

@Computer-and-Electronics 3 ай бұрын

Thank you

@Accanfo 3 ай бұрын

Super good

@Computer-and-Electronics 3 ай бұрын

Thanks

@franconichtgesagt3094 4 ай бұрын

From minute 6:25 all the equations vu=expression have the term R_C missing and aren't dimensionally correct.

@Computer-and-Electronics 4 ай бұрын

Right, thanks.

@Cesar_III 4 ай бұрын

Good explanation.

@Computer-and-Electronics 4 ай бұрын

Thank you

@dhavies 4 ай бұрын

you can master truth tables like this: AND gate is just a multiplication of the 2 inputs, NAND is an opposite of AND gate’s output, OR gate is the addition of the inputs (adding 1 +1 equals 1 since its in binary) and NOR is also an opposite of OR gates’s output

@dhavies 4 ай бұрын

who else is in ai and just wants to write efficient codes😂

@isaakmwangi4618 4 ай бұрын

who else is here because of Andrej Karapathy 👀

@fiseticamente 4 ай бұрын

awesome explanation, gave me an eureka moment. grazie mille!

@Computer-and-Electronics 4 ай бұрын

Prego. You're welcome.

@seankhatiri3393 4 ай бұрын

Couldn't imagine someone explaining how a simple 4-byte RAM works better than this!

@Computer-and-Electronics 4 ай бұрын

Wow, thank you. I am flattered.

@Aditya-wc9sw 4 ай бұрын

is this the end of the Scott's CPU series?

@Computer-and-Electronics 4 ай бұрын

Yes that is the end of videos based on Scott's CPU. Other videos in the playlist are about CPU but not based on Scott's book .

@Aditya-wc9sw 4 ай бұрын

@@Computer-and-Electronics Thanks for making this course, its very Informative and Helpful!

@mohitjani2390 4 ай бұрын

andrej got me here, definitely not disappointed

@Computer-and-Electronics 4 ай бұрын

Thank you

@M4th3www 4 ай бұрын

Amazing video

@Computer-and-Electronics 4 ай бұрын

Thank you

@hareeshrajendran 4 ай бұрын

Man oh Man!! Watched only one and this is a banger

@Computer-and-Electronics 4 ай бұрын

Thanks

@MadhavanSureshRobos 4 ай бұрын

Why does a NOT gate require two transistors exactly? Why not just use a p-type transistor? It works exactly as a NOT gate even without a n-type

@Computer-and-Electronics 4 ай бұрын

Yes you are right, but you should use a resistor instead of the nMos (otherwise the output Is always connected to ground or zero logic). But in Integrated circuit a transistor Is always better than a resistor because It takes less room. Moreover, there are other considerations related to speed, simmetry, power consumption and IC process which make you prefer the two transistors solutions.

@MadhavanSureshRobos 4 ай бұрын

@@Computer-and-Electronics ohh got it. Very interesting!!

@antonsidorov7531 4 ай бұрын

As many others, I came here from twitter. I would like to ask a question about a NOT gate. I don't understand why you need two transistors if having a single P-Type transistor, supposedly, already achieves the same effect (outputs 1 when input is 0)?

@Computer-and-Electronics 4 ай бұрын