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@teneeshunniap1
@teneeshunniap1 2 күн бұрын
Let R1=1,R2=2,R=3. Then dA/dr becomes 2π, 4π, 6π. But putting radii values in the formula A= πr^2; Area A1=π,A2=4π,A3=9π . The changes in Area wrt r ...π ,3π,5π etc. Both results are not maching.why?
@badcontent3347
@badcontent3347 4 күн бұрын
Or mod(x,1)
@Croccifixo
@Croccifixo 4 күн бұрын
That's what I use in Excel
@Telegranger
@Telegranger 11 күн бұрын
BRO SOUMDS LIKE DANTDM
@scottwatson-b6c
@scottwatson-b6c 15 күн бұрын
Hi Tiago, great video very useful. Is there a way, instead of sum to list the values. E.g show how much John paid. so list £500, £400, £250 in a cell?
@Y_T-x1v
@Y_T-x1v 16 күн бұрын
Warning: moving the imaginary point may cause intense lag
@user-whyudodat
@user-whyudodat 17 күн бұрын
nil im yr 6 going into high school next yr and i H the gr A T E
@mechaboy95
@mechaboy95 18 күн бұрын
bro why couldn't you just do it in desmos basically I want to render polygons like cylinders and I want to have multiple points, each as part of an array with coordinates sin(index no x d),cos(index no x d) so that d=360/totally number of points we get a circle of total number of points
@tsvilissack
@tsvilissack 19 күн бұрын
This proof uses the trigonometric identity for sine of sum of two angles. As far as I know the proof of that identity uses the rotation matrix properties, hence this is a circular proof.
@mathematics.proofs
@mathematics.proofs 19 күн бұрын
Maybe it's something I'll look into more deeply. The video was made a long time ago and the way we see things and our understanding changes.
@unique-username
@unique-username 21 күн бұрын
Limited to Newtonian dynamics, can you please rigorously prove Kepler's laws?
@arianit6992
@arianit6992 22 күн бұрын
Why does it takes ages on my remarkable to make the line straight?
@rodrigomarcondes2000
@rodrigomarcondes2000 24 күн бұрын
By hearing the voice I understood why KZbin suggested me this video :P
@hhomeschool
@hhomeschool 27 күн бұрын
Can you make a tutorial about the shuffle function in desmos
@mathematics.proofs
@mathematics.proofs 28 күн бұрын
The latest video related to the Egyptian Tangram and the 345: kzbin.info/www/bejne/m2HXfaOAZpiBgas
@necronposter6832
@necronposter6832 Ай бұрын
for anyone wondering the side length of the square is root 20 units
@ilserojas2259
@ilserojas2259 Ай бұрын
👏👏
@pardus788
@pardus788 Ай бұрын
Thanks 🎉
@EmonEconomist
@EmonEconomist Ай бұрын
2:57 - You never explained why the smallest length has to be 1, the next smallest has to be 2 etc. Your subsequent proofs rely on that being true, but you didn't prove that step.
@mathematics.proofs
@mathematics.proofs Ай бұрын
instagram.com/tiago_hands/reel/DDO4txJugLf/
@mathematics.proofs
@mathematics.proofs Ай бұрын
The latest reel also addresses what you've said: kzbin.infoYCcCGYXcxCs?si=8HLSa56H8cbbzvDf
@mathematics.proofs
@mathematics.proofs Ай бұрын
There's also this drawing: x.com/tiago_hands/status/1865399889527500856
@Vini-if2gb
@Vini-if2gb Ай бұрын
THANK YOU SOOOOOOOOOOOOOOOOOO MUCH FOR THIS. I needed to learn very quickly how to calculate the intersection points without all of that time consuming mathematical logic, these formulas make everything so much easier! YOU SAVED ME!
@mathematics.proofs
@mathematics.proofs Ай бұрын
Glad it helped!
@JohnBerry-q1h
@JohnBerry-q1h Ай бұрын
Dear Host... Can you explain, laboriously, step-by-step, exactly what you are doing when you say... _"Hold down 6"_ ...at time index 1:33 ?
@ParsaAmini-xp6up
@ParsaAmini-xp6up Ай бұрын
Very well Thanks
@brainboy6655
@brainboy6655 Ай бұрын
what does this even mean😢
@RedBloxStudios
@RedBloxStudios Ай бұрын
The radius of this circle squared is equivalent to the cosine of twice it's angle, multiplied by a scaling factor
@brainboy6655
@brainboy6655 Ай бұрын
Fun little proof I never knew I needed! Just discovered your channel not long ago but I'm hooked! (Very much not a math person)
@mathematics.proofs
@mathematics.proofs Ай бұрын
Thanks for stopping by. Yes, even for those in mathematics, very simple equations, but which are very useful come up all the time. The other day I came across (x/a)+(y/b)=1 for a straight line, which surprised me!
@brainboy6655
@brainboy6655 Ай бұрын
Love this video! Teachers told me to just remember the equation when i asked, now I'm definitely going to remember it.
@danksourav
@danksourav Ай бұрын
ain't no way
@deckearns
@deckearns Ай бұрын
This is excellent. Thank you for posting. ❤
@thunderclaper
@thunderclaper Ай бұрын
do i need to be a math person to understand how use this compass
@VashlyBabez
@VashlyBabez Ай бұрын
Another method please
@username-ur6dq
@username-ur6dq Ай бұрын
Fyi you can do recursion in desmos so this writing of f(f(... Is a tad unnecessary.
@username-ur6dq
@username-ur6dq Ай бұрын
You can also get rid of the vars a,b cause you don't need them to make for a dragable complex number. But I suppose you may want them to be able to change real and imaginary separately more easily, I guess...
@HJ28_398
@HJ28_398 Ай бұрын
How to do recursion?!! I've tried this for so long! Is it new?
@username-ur6dq
@username-ur6dq Ай бұрын
Just look up in google "desmos recursion" and you will find information on it online​@@HJ28_398
@qwertyman506
@qwertyman506 Ай бұрын
Please explain how
@username-ur6dq
@username-ur6dq Ай бұрын
I commented earlier but for some reason it doesn't show up... Anyways just google up "desmos recursion" and you will find desmos documentation on recursion. Also it was added 4 months ago.
@eliemassouh6842
@eliemassouh6842 Ай бұрын
Is there any graphing for Sierpinski Triangle?
@eliemassouh6842
@eliemassouh6842 Ай бұрын
Nice✨
@eliemassouh6842
@eliemassouh6842 Ай бұрын
Amazing 😍🤩 But desmos is lagging now 😂
@mathematics.proofs
@mathematics.proofs Ай бұрын
Yes, that's typically the case and it gets worse if you try to colour it all in. :-(
@mathematics.proofs
@mathematics.proofs Ай бұрын
TUTORIAL FOR THE JULIA SET FRACTAL NOW ONLINE: kzbin.info/www/bejne/eqval5yrgMuKi80si=Hv73YJvxU8uaggWV
@Suraborisut-o8g
@Suraborisut-o8g Ай бұрын
🌺🫶🌺👍🇹🇭
@FNShadow008
@FNShadow008 Ай бұрын
Very nice proof!
@Sior-person
@Sior-person Ай бұрын
Ok what the dot doing though???
@mathematics.proofs
@mathematics.proofs Ай бұрын
The .x and .y represent the real x and y coordinates of a point. For instance, if P=(3, 4), P.x=3 and P.y=4. Hope that helps!
@AllYourMemeAreBelongToUs
@AllYourMemeAreBelongToUs Ай бұрын
Why’d you do this on mobile?
@mathematics.proofs
@mathematics.proofs Ай бұрын
It can be done on a PC but I did it so viewers can do something entertaining on their phone whenever they're bored. Makes for conversation with friends.
@mathematics.proofs
@mathematics.proofs Ай бұрын
Be very particular about the approach. Make sure you haven't missed anything or overlooked anything.
@theceus
@theceus Ай бұрын
This helped. Thanks so much!
@mathematics.proofs
@mathematics.proofs Ай бұрын
You're welcome!
@okkoheinio5139
@okkoheinio5139 Ай бұрын
Complex numbers were added to Desmos like a month ago, btw. Just turn on Complex Mode in the settings. Recursion also exists now. All in all, this video is outdated at the time of upload.
@Sior-person
@Sior-person Ай бұрын
Oh sweet I Didn’t know that 🗿 (Does look prt limiting 😔)
@HalfBreadOrder
@HalfBreadOrder Ай бұрын
how are you not getting the error
@namonef
@namonef Ай бұрын
Cant wait for Julia set
@mathematics.proofs
@mathematics.proofs Ай бұрын
Here's the tutorial for the Julia Set Fractal: kzbin.info/www/bejne/eqval5yrgMuKi80si=Hv73YJvxU8uaggWV
@mr.pumpkinn
@mr.pumpkinn Ай бұрын
-This is so dumb.- Complex numbers are already here, so you can just do: f(x,n)={n=0:x,f(x,n-1)²+x} |f(x+iy,50)|≤2 (Don't forget to turn on complex mode in the settings)
@minamagdy4126
@minamagdy4126 Ай бұрын
Don't forget also the +x in the recursive case
@mr.pumpkinn
@mr.pumpkinn Ай бұрын
@@minamagdy4126 I edited it
@silloo2072
@silloo2072 Ай бұрын
It works!
@spiderham6353
@spiderham6353 Ай бұрын
Its not working. It says "Cannot access coordinate '.x' of a number."
@xnaaloh4437
@xnaaloh4437 Ай бұрын
You need to pass in a co-ordinate like he did with f((x,y))
@spiderham6353
@spiderham6353 Ай бұрын
@@xnaaloh4437 I got it working, it was a setting I didn't have on. Thanks anyway
@reddelcorazon8118
@reddelcorazon8118 Ай бұрын
What is going on: The 1st line takes point and somehow iterates it like the mandelbrot fractal (Z^2 + C) The 2nd line takes in a point and gets the distance to the origin The third line then gets all possible points on the plane and then after iterating them alot with the first function it tests if the final points are close to the origin to see if they converge or diverge after being iterated, then it shades all starting points that end up converging.
@Kishblockpro
@Kishblockpro Ай бұрын
Thank you very much!
@Katie.smith704
@Katie.smith704 Ай бұрын
Thank you so much for sharing, this is incredible!
@sanahaskuranage8071
@sanahaskuranage8071 Ай бұрын
how do you know that OR=OS-TQ
@carminefiore8627
@carminefiore8627 Ай бұрын
could you explain how does (x+iy)²=x²+y²? i tried to get it, but since i'm not deep into this kind of math, thought there could be some kinda rule that i'm not aware of
@mathematics.proofs
@mathematics.proofs Ай бұрын
It's |x+iy|^2=x^2+y^2. It's because |x+iy|=sqrt(x^2+y^2). |x+iy| means the magnitude of the vector x real units across and y units upwards. Vectors have both a magnitude and direction.
@carminefiore8627
@carminefiore8627 Ай бұрын
maybe I wasn't clear enough. if you calculate |x+iy|², you get x²-y²+2ixy. my question was, how do you get x²+y² from x²-y²+2ixy? is there some rule in the study of the complex numbers, or is it simply manipulation on the expression?
@mathematics.proofs
@mathematics.proofs Ай бұрын
@@carminefiore8627 (x+iy)^2 is completely different to |x+iy|^2. I think you're getting the two confused.
@carminefiore8627
@carminefiore8627 Ай бұрын
@@mathematics.proofs now I get it. thanks for the clarification!
@madihazeeshan2148
@madihazeeshan2148 Ай бұрын
Assalam O
@哲子仮免
@哲子仮免 Ай бұрын
Your derivation was different from what I have watched from other sources. Haven't obtained that information that sinθ can be also converted into tanθ×cosθ. Dang!
@mathematics.proofs
@mathematics.proofs Ай бұрын
Awesome