ı had not understood kernel until this video. thank you so much. you are great teacher. You helped me so much. Greetings from Turkey.
@HenryAdamsMath17 күн бұрын
Glad you found it helpful!
@BigKokRomi69Ай бұрын
hi, ive been stuck at this problem since forever, How do i show that Q* and R* are not isomorphic? The operation is multiplication for both of them
@HenryAdamsMath17 күн бұрын
The underlying sets are of different cardinalities (Q* is countable and R* is not), so there can be no bijection between them.
@lvlansonАй бұрын
Just found your video, I like that you have these topics in short video form. I am enjoying it. Thank you very much, will probably also check out the others :)
@HenryAdamsMath17 күн бұрын
Wonderful!
@besusbbАй бұрын
Thanks for the explanation
@HenryAdamsMath17 күн бұрын
You are welcome!
@RaeTheActuaryАй бұрын
awesome, appreciate it, your abstract algebra list is fire
@HenryAdamsMath17 күн бұрын
Glad you're enjoying the series!
@valeriereid23372 ай бұрын
I do not follow the mapping. Why does -4 maps to 2 for example.
@HenryAdamsMath17 күн бұрын
Ah! We have that -4 maps to 2 since we have the equality -4 = 2 mod 3. Indeed, since -4+6=2, and since 6 is a multiple of 3, that is why -4 = 2 mod 3.
@valeriereid23372 ай бұрын
I didn't fully understand why 1 maps to 1 in the last example.
@HenryAdamsMath17 күн бұрын
Are you referring to the example where Z/4Z maps to Z/2Z by sending j to j mod 2? If so, then 1 maps to 1 since 1 = 1 mod 2.
@valeriereid23372 ай бұрын
This is very helpful.
@HenryAdamsMath17 күн бұрын
Glad you found it helpful!
@DingZiyang-d8g2 ай бұрын
The graphs in the talk are vivid, I like them.
@HenryAdamsMath2 ай бұрын
Thanks!
@valeriereid23372 ай бұрын
Wonderful! Thank you Professor Adams. Your lectures make the concepts of abstract algebra easy to understand.
@HenryAdamsMath2 ай бұрын
Thanks!
@valeriereid23372 ай бұрын
Thanks for making your lectures available. I am also happy you go for simple notations and not the extra complicated notations.
@HenryAdamsMath2 ай бұрын
Glad you like them!
@valeriereid23372 ай бұрын
This certainly helps!
@HenryAdamsMath2 ай бұрын
Wonderful!
@valeriereid23372 ай бұрын
This lecture helped me understand the proof of Lagrange's theorem. Thank you.
@HenryAdamsMath2 ай бұрын
Glad to hear it!
@valeriereid23372 ай бұрын
Come on, I was just enjoying the visit from Grandpa. Thanks Professor Adams. Your lectures certainly helps.
@HenryAdamsMath2 ай бұрын
Thanks! I'm glad you're finding the lectures helpful.
@valeriereid23372 ай бұрын
Thanks Professor Adams. This helps.
@HenryAdamsMath2 ай бұрын
Great!
@valeriereid23372 ай бұрын
Thank you Professor Adams, this most certainly helps.
@HenryAdamsMath2 ай бұрын
Glad it was helpful!
@RiteshArora-s9x2 ай бұрын
How many questions one needs to do from Judson's book ? Thanks. Is this course a first course on algebra ?
@HenryAdamsMath2 ай бұрын
Yes, it is!
@valeriereid23373 ай бұрын
Professor do you have anymore lectures from the book you are using here> I would appreciate your lectures.
@valeriereid23373 ай бұрын
Thank you so very much. This certainly helps.
@HenryAdamsMath2 ай бұрын
You're very welcome!
@isthisbadbnumber3 ай бұрын
thank you so much 🫶🏻
@HenryAdamsMath2 ай бұрын
You are welcome!
@ghadeeryousif26023 ай бұрын
Thank you dr Henry
@HenryAdamsMath2 ай бұрын
You are welcome!
@ritwikpriyadarshi9613 ай бұрын
Thank you! Could not multiply properly before this in cycle form and always had to turn into mappings, this is gonna save a lot of time :)
@HenryAdamsMath2 ай бұрын
Yes, you can multiply in cycle form (to save space).
@anuradhaupadhyay32583 ай бұрын
Well explained ❤❤ thank you sir
@HenryAdamsMath2 ай бұрын
Thanks!
@tekisasu75503 ай бұрын
Thank you for the video! I stumbled upon it and am leaving more satisfied than I was prior.
@HenryAdamsMath2 ай бұрын
Great to hear!
@fatimaginebra88233 ай бұрын
Thaankk youuu!! This made me understand so much, I'm doing my bachelor's thesis using this and this helped so muchhh!
@HenryAdamsMath2 ай бұрын
Wonderful!
@Rajkumar-uu7te3 ай бұрын
Sir can you give 2×2 Matrices which form group but not abelian?
@HenryAdamsMath2 ай бұрын
Correct, the set of invertible 2x2 matrices under matrix multiplication is a group that is not abelian.
@wenzhang3653 ай бұрын
This video is very helpful. Thank you.
@HenryAdamsMath2 ай бұрын
You're very welcome!
@mohammadshirzadi92213 ай бұрын
Thanks!
@HenryAdamsMath2 ай бұрын
No problem!
@SrEstroncio4 ай бұрын
What is the book being used for this? Thanks
@HenryAdamsMath2 ай бұрын
We are following the book "Understanding and Using Linear Programming" by Jiří Matoušek and Bernd Gärtner link.springer.com/book/10.1007/978-3-540-30717-4
@samyud18194 ай бұрын
I just wanted to find a way to optimize my diet “database” but now I’ve been introduced to linear programming :)
@HenryAdamsMath2 ай бұрын
Haha, great!
@vector83105 ай бұрын
Why has this video only drawn under 700 views? It is the only video I've found that actually illustrates the kernel operation with concrete examples. Unlike most videos on the topic, it doesn't just regurgitate definitions that can be found in you average textbook or monograph. This is the sort of content that viewers should demand.
@HenryAdamsMath5 ай бұрын
Glad you liked the video, Vector, much appreciated!
@Gordy-io8sb5 ай бұрын
For the longest time, I pronounced it "a-bell-i-an"...holy.
@Anony11765 ай бұрын
Outstanding video. One of the best video in the KZbin. I am from India sir. Sir can I do a small project in online if possible? It will be really helpful for me. I have completed undergraduate in physics
@HenryAdamsMath5 ай бұрын
Glad you enjoyed the video!
@atulkumaraa2676 ай бұрын
Thanks
@HenryAdamsMath5 ай бұрын
You are most welcome!
@pfever6 ай бұрын
You seems like a really cool professor and teach really well! :D
@HenryAdamsMath5 ай бұрын
Thanks so much!
@sadiashahzadi68416 ай бұрын
Sir! You are performing good job
@HenryAdamsMath6 ай бұрын
Thanks a lot!
@Lem42126 ай бұрын
great video
@HenryAdamsMath6 ай бұрын
Thanks!
@siddharthb59776 ай бұрын
No other choice but subscribe. Why were you not my teacher when I was in college?
@HenryAdamsMath6 ай бұрын
Thanks for subscribing!
@siddharthb59776 ай бұрын
Wow! Simple and effective, I really like the way you teach.
@HenryAdamsMath6 ай бұрын
Thank you!
@riyakeerthana31366 ай бұрын
Thank u for ur crystal clear explanation
@HenryAdamsMath6 ай бұрын
You're most welcome!
@kressmax8 ай бұрын
Very well done!
@HenryAdamsMath7 ай бұрын
Thank you very much!
@mahmoodalmohri48058 ай бұрын
Thank you for your demonstration. My question is that how do we assign the arbitrary value between 0 and 1 to each vertex? Earlier it was easier to do that, since I knew that if I chose the vertex to be in the vertex cover, then its value is one, and zero otherwise. But now how does each vertex get assigned their value?
@HenryAdamsMath7 ай бұрын
You assign the value between 0 and 1 by solving the relaxed linear programming problem, for example using the simplex algorithm, which is computationally very efficient!
@user-gf4jz7li8s8 ай бұрын
Hi Henry! Is the distributivity proved by the other basic axioms or on its own?
@HenryAdamsMath7 ай бұрын
My understanding is that the distributivity axiom does not follow from the other axioms, and that it is therefore necessary to include as an axiom of its own!
@RamatuYahaya-gq7hz8 ай бұрын
Find the rule of the mapping
@shayquaza32078 ай бұрын
you're the goat bro <3
@HenryAdamsMath7 ай бұрын
Appreciate it!
@aminmdal70438 ай бұрын
i have some problems with integer linear programming. i want to discuss with you. how can contract with?
@021scorpion8 ай бұрын
Thank you so much for all your hard work, you videos have been tremendously helpful! I just have a quick question, this sounds counterintuitive but I think what I just learned from this video is that any finite abelian group of let's say size 72 is isomorphic to products of cyclic groups (all 6 of them) but those 6 groups are not isomorphic to each other. intuitively it would make sense if the abelian group of size 72 would only be isomorphic to Z/8Z x Z/9Z because 8 and 9 are relatively prime. Also did we not learn if A is isomorphic to B and B is isomorphic to C then A is also isomorphic to C? in here we have an abelian group of size 72 being isomorphic to Z/8Z x Z/9Z and also the same abelian group is isomorphic to Z/2Z x Z/4Z x Z/9Z for example, but Z/8Z x Z/9Z is not isomorphic to Z/2Z x Z/4Z x Z/9Z because the orders are different so how is this possible that the abelian group would be isomorphic to them both? Won't the abelian group of size 72 must have elements of certain orders in which it would be different than some of these products? I am a little confused on this part and apologize for writing so much lol. Thanks in advance.
@HenryAdamsMath7 ай бұрын
It is not true that any abelian group of size 72 is isomorphic to Z/8Z x Z/9Z --- that is only one of six possibilities that an abelian group of size 72 could be isomorphic to. Yes, it is true that if A is isomorphic to B and B is isomorphic to C, then A is isomorphic to C. No, it is not the case that Z/8Z x Z/9Z is isomorphic to Z/2Z x Z/4Z x Z/9Z --- these are two different abelian groups of size 72 that are not isomorphic to each other. You seem to be assuming that there is a single abelian group of size 72 --- but this is not correct ---- up to isomorphism there are six different groups of size 72 !
@jack-sk5st8 ай бұрын
Can you give me the source code of the ellipsoid algorithm?
@hoganchou19698 ай бұрын
what an informative lecture
@HenryAdamsMath7 ай бұрын
Thank you!
@fatalfoot75798 ай бұрын
Amazing video, thank you very much, helped me a lot !!!