My videos do not include sound. They are intended to walk through the solution without additional verbal explanations.
@ameliar6374Күн бұрын
why is the man's pushing force drawn as going up the incline? shouldnt it be pointing down??
@MsProblemSolverКүн бұрын
The force of gravity pulls down. With no friction, the only way to achieve constant velocity would be for the force of the man pushing to be in a direction opposing the force of gravity, thus going up the incline.
@plutofifteen2 күн бұрын
isnt the y compontent of a force the force magnitudes times sin theta? why is it cos thete for here
@MsProblemSolverКүн бұрын
It all depends on perspective and what values you are using. When looking at an incline, the calculations can be affected by the angle of the include and what direction you are taking to be x and y. I choose the slope to be x and I try only to use the angles provided in the problem. Take a careful look at which angle theta represents, it is likely the complimentary angle of the one you would usually use for these calculations.
@plutofifteenКүн бұрын
@@MsProblemSolver ohhh i remember now. thanks
@katherinestormcatcher666310 күн бұрын
wtf is Fb can you please just add audio??? oh my god
@MsProblemSolver9 күн бұрын
While I do have plans to add audio, I'm not there yet. I don't have the equipment or experience to add high quality audio just yet. Until then, I will continue to do my best to ensure that my walk thoughts are clear even without verbal explanations.
@katherinestormcatcher66635 күн бұрын
@@MsProblemSolver this ones not tho
@MsProblemSolver5 күн бұрын
@@katherinestormcatcher6663 feel free to let me know what isn't clear. I'd be happy to clarify and it is helpful for me to know if there is a logical breakdown so I can correct it.
@GodfredAsare-p5l12 күн бұрын
Fx was 104N and not 90N
@MsProblemSolver12 күн бұрын
F is 104N, which is the magnitude of the force. Fx is given in the problem as 90 N, which is the x component of the force (the component parallel to the ramp).
@speedyfire404216 күн бұрын
dude your crazy, underrated af!!!
@Music22worldncs21 күн бұрын
this que is from which book sir?
@MsProblemSolver21 күн бұрын
I get questions from a number of different books and sources, and you will find some of the same problems in different places. That being said, I 'think' this one is from Young/Freeman University Physics.
@Music22worldncs20 күн бұрын
@@MsProblemSolver okay thanks 😁
@sunRay0423 күн бұрын
no sound?
@MsProblemSolver23 күн бұрын
I try to make my solutions clear without the need for verbal explanations. While I may add these in the future, I am currently focused on expanding my library of solutions.
@cennerdobber819624 күн бұрын
thank you so much
@MsProblemSolver24 күн бұрын
Glad I could help!
@Pearl_240Ай бұрын
Excuse me part b and c were so comfusing could you please explain more?
@MsProblemSolverАй бұрын
Both part b and part c follow the exact same steps and equations as in part a. First convert the frequency to Hz (1 MHz=10^6 Hz) and then input into the equation.
@Pearl_240Ай бұрын
@@MsProblemSolver thank you!
@joshfriedman97752 ай бұрын
Don't we need to consider gravity in these calculations? wouldn't we need to multiply our masses by G or is their a reason we don't
@joshfriedman97752 ай бұрын
Would it be because since this takes place in the air, the object isn't experiencing a force from the ground opposite of gravity?
@MsProblemSolver2 ай бұрын
You'll notice gravity is considered initially, but it cancels out, leaving the final answer to no longer depend on gravity.
@technodroid94112 ай бұрын
Thank you for this, only question i have is how the box is sliding up if the acceleration is pointing down?
@MsProblemSolver2 ай бұрын
This problem starts with some initial forward velocity when it arrives at the hill (Like someone gave it a good shove forward and let go, so there is no ongoing force in that direction.) . The hill changes the direction of that velocity, but the magnitude remains the same, which starts it up the hill. But now it has the force of gravity in the downward direction and the force of friction in the direction opposite motion. Eventually with no other forces, the block slows down, stops and starts moving in the opposite direction.
@stem1_lozano3753 ай бұрын
What reference book is this problem from?
@MsProblemSolver3 ай бұрын
I believe this one is from Young&Freeman-University Physics. I have used several sources for problems, and you will often find the same or similar problems in many places.
@stem1_lozano3753 ай бұрын
@@MsProblemSolver thank you!
@MioFuru4 ай бұрын
Sorry how did you get the 9.8?
@MsProblemSolver4 ай бұрын
g=acceleration due to gravity=9.8 m/s^2(approximately)
@wasimvillidad30004 ай бұрын
Last example: Let v = (1 + x²)/2. Too easy!
@goldenheart79334 ай бұрын
Thank you man
@MsProblemSolver4 ай бұрын
Glad I could help!
@goldenheart79334 ай бұрын
helped so much thanks alot
@forhadahmed32244 ай бұрын
Thanks a lot for help.. It was a question in our term final exam..
@gsas30124 ай бұрын
I got -230.4N, why do you show positive 230N as the answer?
@MsProblemSolver4 ай бұрын
You're right! Good catch. Based on the numbers, this should be negative. It is 230 vs 230.4 due to number of significant figures, but I would still expect to see the negative. I'll have to take a look at the original problem to see if there was some additional context I failed to include. Sometimes they are looking for a magnitude, which would be a positive number with a description of direction. It's also certainly possible I made a mistake. I'll review this problem in the next couple days and either make a note to explain the difference or remove it from my channel. Great job catching this one! And thanks for pointing it out; I do my best to correct mistakes when reviewing and editing, but occasionally I miss something.
@gsas30124 ай бұрын
@@MsProblemSolver I think it was asking for a magnitude now that I think about it. Thanks for explaining that magnitude is always positive!
@digguscience4 ай бұрын
Very good explanation
@Rorablink5 ай бұрын
Why no sound?
@MsProblemSolver5 ай бұрын
I do have plans to add voice in the future. In the meantime, I am doing my best to ensure my walk-throughs are clear even without added audio. Thanks for your feedback!
@xylene_ymassan5 ай бұрын
Thanks, Ms Problem Solver! This really helped me out in my physics homework!
5 ай бұрын
real question can i outrun the rocks?
@MsProblemSolver5 ай бұрын
Depends, how fast can you run?
@sanyam15835 ай бұрын
very helpful, keep going - thanks
@BUY_YT_VIEWS_m0606 ай бұрын
where did you buy your camera?
@MsProblemSolver5 ай бұрын
I don't use a camera, just a screen recorder.
6 ай бұрын
FIrst!
@gleanfernandez93006 ай бұрын
Bro on the first problem you calculator shows 0.897 but mine shows 1.115? Your calculator is in degree mode or not or what?
@MsProblemSolver6 ай бұрын
cos(45)tan(30)+sin(45)=0.115; 1/0.115=0.897; w/(cos(45)tan(30)+sin(45))=0.897w; Some of the most common issues are simple calculator issues and I have made TONS of them over the years. Good job double checking. Hope this helped.
@mungadilengi66196 ай бұрын
Please make these videos audible.
@MsProblemSolver6 ай бұрын
I do have plans to do this in the future. In the meantime, I am doing my best to ensure my walkthroughs are clear even without added audio. Thanks for your feedback!
@김오링6 ай бұрын
thanks as always
@MsProblemSolver6 ай бұрын
Happy to help!
@Momo-tr6rc6 ай бұрын
hi yanhee
@Inthe.SHADOWS6 ай бұрын
but sir it is not given as constant acceleration, average acceleration is given. why you are using constant acceleration equations?
@Inthe.SHADOWS6 ай бұрын
from india, grade(class) 10th
@MsProblemSolver6 ай бұрын
Average acceleration is a constant acceleration. If you look at the time from t=10.0s to t=20.0s as a whole, you can use the constant acceleration equations. You can only look at the period as a whole, since the instantaneous acceleration and velocity may deviate from the average. But the constant acceleration equations can apply . There are almost always several ways your can derive a solution; you may have used a different method and came up with the same answer.
@Inthe.SHADOWS6 ай бұрын
@@MsProblemSolverThanks
@اقرء6 ай бұрын
Gak ada suara dong
@MsProblemSolver6 ай бұрын
That's correct. I try to make my walk-through videos understandable without verbal and minimal written explanations. The math should speak for itself. I am looking into adding sound at some point in the future.
@KrischeaPellas7 ай бұрын
Hello! Your videos are really helpful to me. I'm glad you decided to make this channel for those students who are studying/practicing physics. But I hope you can use your voice and explain so we can understand better. Anyway, thank you!
@MsProblemSolver7 ай бұрын
I'm glad my videos are helpful. I do intend to add voice explanations at some point, but high quality sound requires some equipment and software that I am still researching. Right now, I am focusing on creating clear walkthroughs that can be understood without the added voice explanations. I'm also always willing to answer questions. Good luck with your studies!
@juanmanuelcoronadosarta83857 ай бұрын
no sound??
@MsProblemSolver7 ай бұрын
That's correct. I create my videos to be easy to follow without added voice explanations.
@SparkyAndres7 ай бұрын
what application do you use? Onenote?
@MsProblemSolver7 ай бұрын
Great guess. Most of my videos use OneNote but some of my older videos used Whiteboard.
@sharonrussell46327 ай бұрын
My brain hurts - a 4th grader
@as2ria8 ай бұрын
Why did u use this kinematic equation?
@MsProblemSolver8 ай бұрын
The selection of which equation to use is based on which variables are available and what you are looking for. This could have been solved in a few different ways. This is just the path I chose. As long as you apply the equations correctly, any path should take you to the same result.
@samuelvieira97489 ай бұрын
Simple and to the point!
@Shalini-j7n9 ай бұрын
Keep growing 😅 Happy new year 🎉
@MsProblemSolver9 ай бұрын
Thank you for your support and Happy New Year!
@bussinessmindset24509 ай бұрын
Can't we use d=vt formula for finding distance?
@MsProblemSolver9 ай бұрын
For this problem, vertical displacement d=vt+at^2/2. Since a=-g, and initial velocity is zero, we use d=at^2/2. For horizonal displacement where a=0, we would use d=vt.
@onethegogd578310 ай бұрын
Haven't watched yhe video yet Anyway 3,6/2=1,8 h=gt²/2 h=(10*1,8²)/2 h=16m This is really basic
@MsProblemSolver10 ай бұрын
The fantastic part about physics is that even if you take another path, as long as all of your assumption are correct, you will come to the same answer. I took a different path in my video and came to the same answer as you. Great job!
@perrytopness590311 ай бұрын
is there no sound?
@MsProblemSolver11 ай бұрын
That's correct. My videos do not currently include voice explanations. I do my best to ensure my walkthroughs are clear without additional verbal explanation as I do not currently have the software, equipment or experience to provide high quality audio.
@ivebeencultured11 ай бұрын
Don't know why this keeps getting recommended but ok
@ivebeencultured11 ай бұрын
Nice
@panmadechen296911 ай бұрын
👍👍👍
Жыл бұрын
THanks but do you know why the = is so humble?
Жыл бұрын
It knows that isn't less or greater than anyone else in the equation.
@55animesh Жыл бұрын
My brain can't handle this lol😅 I'm 10 why did KZbin recommend me this
@MsProblemSolver Жыл бұрын
I couldn't say. Maybe KZbin thinks you should be a Physicist!
@hashbrown8314 Жыл бұрын
Great content! Try adding audio explanation also.
@MsProblemSolver Жыл бұрын
I appreciate the support. I do plan on eventually adding audio, however I am still working on figuring out the appropriate software and hardware necessary to provide high quality audio. In the meantime, I am focusing on providing clear walk-throughs that can be understood without any audio.
@hashbrown8314 Жыл бұрын
I understand that. You are solving physics, the others will be pretty easy eventually. Keep up the great work. @@MsProblemSolver