Have you seen the full lesson yet?

@@TheScienceCube sir are all the chapters of 11 and 12 covered??

@@Medha-h6j No Medha! ABout 70% is covered. I am making videos very slow to keep the quality high :)

@@sumaiyakhalid831 so glad to know you liked it! 👍

Hi! Here is the full question with the answer kzbin.info/www/bejne/bJvMd2mJlthllZIsi=uOk5ETbc8PP-yr0z

@@itzmeabid did you like :)

@@TheScienceCube No, I don't like indians🤣🤣

Thank you for your thoughtful analysis! You're absolutely right that mathematics is flexible in this case, and both approaches lead to the correct direction for the cross product, provided the correct method is applied. When we use the smaller angle ∅ between vectors A and B, the right-hand rule directly gives us the direction of the resultant vector C as C = A × B = AB sin(∅) n, where n is the unit vector perpendicular to the plane containing A and B. As you pointed out, if you instead consider the larger angle, 360° - ∅, the sine function gives the same magnitude but with an opposite sign, resulting in AB sin(360° - ∅) (-n). The crucial part here, as you've astutely noted, is that when you use the right-hand rule for this larger angle, the direction is still consistent when you account for the sign change. But why would you want to complicate things by introducing a negative unit vector when the right-hand rule is designed to simplify the process? The whole point is to make it easier for students to consistently find the correct direction without getting bogged down by unnecessary complexity. Let's keep it simple and effective!

@@TheScienceCube I too wanna keep it simple but it doesn't mean to give wrong information ( that you can only use smaller angle ) , you should introduce it this way and then say , we take smaller angle to simplify it . 👍

In a series circuit, the wire between capacitors remains electrically neutral, so any charge +Q on one plate induces an equal and opposite charge -Q on the adjacent plate. This ensures that all capacitors in series have the same charge, even if their capacitances differ.

So glad you liked it :) I'm always interested in knowing what specific things students like so that I can do more of it in my next video. Can you tell me one or two things that you really liked.

@@sujitshah.05 are you preparing for an exam?

So glad you liked it! Consider joining our Telegram Channel: ▶t.me/TheScienceCube_Community

@mndtr0 well that's math for you in physics

Can you elaborate on your question please?

That is correct but for the purpose of these lessons, we should simply consider it as a vector that does not necessarily point in the direction of motion.

Thanks Kash! What specifically did you like? I'll do more of it :)

@@TheScienceCube sir me apky playlist k sary videos diky ha moje bahut Acha Lagta ha

@@TheScienceCube sir diagrammatically ap achy explain karty ha.sir ak arz ha ha sir pory HRK book k lecture shoro kardy bahut informative lecturer hota ha apka.me Roz apky lecture Ka intezar krta hu dikny kliye.shukriya

@@kashifsattar9942 Thanks Kashif! So delighted to read your note :)

So happy to know you liked it :). Are you preparing for an exam?

So glad you like dit Sohan! What class are you studying in?

@@TheScienceCube Completed my 10 in CBSE and pursuing my 11( inter first year) in state syllabus

@@SohanMeka Excellent! Are you from India?

@@TheScienceCube Yes

Nicely put! Are you a Physics teacher?

Good question! What you have to remember here is that unlike in linear motion, angular displacement is NOT a vector quantity. It may surprise you but I'm going to show it in one of the videos which is coming in next 15 to 20 days. Therefore when dealing with rotation, we just use a term angular displacement and as such angular distance has no significance. Now, to answer your question, if a body turns 30π radians we simply say the angular displacement is 30 π. When it moves 20 π radians let us say anti-clockwise and then 10 π radians clockwise, We simply say the angular displacement is 10 π radians anti clockwise. Does that make things clear for you?

@@TheScienceCube What boggles my mind is that angular displacement is defined an angle between initial and final position vector. Fine. How can it then be more than 2pi, actually 2pi should mean angular displacement of zero (if observed point was at 0th coordinate), yet we don’t treat it that way but the one I insisted initially (I just didn’t clarify what’s clockwise and what’s anti-clockwise). Thinking of translational-rotational analogy it does make sense, but geometrically it doesn’t to me?

@Timetraveler0161 you are right, but that is the way it is...again it is because it is not a vector

@@TheScienceCube Hm, but where does the vector of angular velocity come from then?

@Timetraveler0161 Again, we are used to the idea that the velocity vector should point in the direction of motion... but not in rotation

Hello Kashif! Not sure what is HRK?

@@TheScienceCube sir fundamental of physics hallidys resnik wala

@@kashifsattar9942 Oh I get it! I use a couple of books for my study and lesson prep - R&H, Sears & Zemansky's University Physics and Giancoli. Also - Shankar Ramamurthy's lectures

Aapki hosla afzai kay liye bohat shukriya :)

Thanks DGamer! Are you preparing for some exam?

Thanks Paru! Are you preparing for NEET?

🙂 Niharika, consider joining my telegram channel t.me/TheScienceCube_Community

Not sure what your questions is? Please elaborate

Yes Aswin, you can take. The final result will tell you if the presumed direction was correct or incorrect

While sloshing causes instantaneous pressure variations, the average pressure on the aquarium walls, when averaged over time, does not change significantly from the static case.