Da diferença de temperatura de 5%. eu utilizei um calibrador no código, usando #25 no monitor serial (25= valor da temperatura real que tu está, utilize um termostato genérico) #include <Wire.h> #include <math.h> const int thermistorPin = 34; // Pino analógico do ESP32 const float termNom = 100000; // Resistência nominal do termistor a 25°C (100k ohms) const float refTemp = 25; // Temperatura de referência para a resistência nominal (25°C) const float beta = 3950; // Fator Beta do termistor const float seriesResistor = 10000; // Valor do resistor em série no circuito (10k ohms) float calibrationOffset = 0; // Offset de calibração void setup() { Serial.begin(115200); Serial.println("Iniciando medição de temperatura..."); Serial.println("Para calibrar, envie # seguido da temperatura real (ex: #26 para calibrar para 26°C)."); } void loop() { // Medir a tensão no termistor int adcValue = analogRead(thermistorPin); // Converter o valor medido para a resistência do termistor float voltage = adcValue * (3.3 / 4095.0); // Conversão para tensão (ESP32 é 12 bits ADC) float resistance = seriesResistor * (3.3 / voltage - 1); // Calcular resistência do termistor // Calcular a temperatura usando a relação para o fator Beta float temperature; temperature = resistance / termNom; // (R/Ro) temperature = log(temperature); // ln(R/Ro) temperature /= beta; // 1/B * ln(R/Ro) temperature += 1.0 / (refTemp + 273.15); // + (1/To) temperature = 1.0 / temperature; // Valor invertido temperature -= 273.15; // Converter de Kelvin para graus Celsius // Aplicar o offset de calibração temperature += calibrationOffset; // Imprimir valores para debug no Serial Monitor Serial.print("ADC Value: "); Serial.print(adcValue); Serial.print(" | Voltage: "); Serial.print(voltage, 3); Serial.print(" V | Resistance: "); Serial.print(resistance, 2); Serial.print(" ohms | Temperature: "); Serial.print(temperature, 2); Serial.println(" °C"); // Verificar se há entrada de calibração no Monitor Serial if (Serial.available() > 0) { String input = Serial.readString(); if (input.startsWith("#")) { input.remove(0, 1); float realTemp = input.toFloat(); calibrationOffset = realTemp - temperature; Serial.print("Calibração ajustada. Novo offset: "); Serial.println(calibrationOffset); } } delay(1000); // Delay para a próxima leitura }

Hello Taiwan, I'd look at the code, I have a feeling it's not built for negative numbers. I haven't tried and I don't know if I will find time to try now. If you understand it a bit, this part will probably need to be changed. //measuring the voltage on the thermistor current = analogRead(termPin); // Convert the measured value to the thermistor resistance current = 1023 / current - 1; --- (maybe there will be a problem here, because I no longer know what the thermistor sends as data.) current = resistance / current; //Calculation of temperature according to the relation for the beta factor float temperature; temperature = current / termNom; // (Y/Y) temperature = log(temperature); // ln(R/Ro) temperature /= beta; // 1/B * ln(R/Ro) temperature += 1.0 / (refTemp + 273.15); // + (1/This) temperature = 1.0 / temperature; // The inverted value temperature -= 273.15; // Convert from Kelvin to degrees Celsius Look at what is going on with the data and where the error occurs. It's been a while since I've done this, I'd have to find more time to test where the error occurs.Let me know. Thanks

Absolutely Same thought

I used PETG and so far it's holding up well :-)

@@inventions654 thank you

Thank you for the info :-)

i was just going to say, it is very annoying. but a cool build.

+1 use mellow music that isn’t shouting and swearing at me

apparently the resistor temperature information is not getting into the code. check if it is well connected.

everything is mentioned in the video. Please watch it again, at the beginning I show and describe exactly what components are used.

Hello, I think this is the mentioned problem. In other words, the bottom of the bottle is not straight and is very crooked, or the tape guidance is generally bad.

Great, thank you and good luck!

I am very grateful that my videos help. All the best!

Im in the same boat right now