WynEducation

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@TheRealLil_Curry Ай бұрын

Q13 is D, since it is the area below the x axis the integral can be just multiplied by -1. Your working out for f(2) - f(-1) is wrong because you have given the 2 an extra negative sign. You will get -1 -2, which is is -3, multiplied by -1 gives us 3 square units.

@tz392 Ай бұрын

I don’t think we can use Desmos for the exam bro

@wasimvillidad3000 2 ай бұрын

Random thoughts for part e, three points of intersection. Consider f(x) = e^(ax) Let f(p) = q and f(q) = p, 0 < p < q < 1 Solving for a in terms of p and q. a = (lnq - lnp)/(p - q) which is clearly negative but showing it is less than -e is beyond my Sunday night brain. Food for thought!

@wasimvillidad3000 2 ай бұрын

5:33 This is true for increasing functions but not necessarily for decreasing functions. For example: f(x) = (7 - x²)/3, x ≥ 0 intersects its inverse at three points, two of which do not lie on y = x. [(1, 2) and (2, 1)].

@wyneducation6446 2 ай бұрын

That's interesting! Never thought about that...very cool.

@wasimvillidad3000 2 ай бұрын

Without fractions. ax² + bx + c = 0, a ≠ 0 4a²x² + 4abx + 4ac = 0 (2ax + b)² = b² - 4ac 2ax + b = ±√(b² - 4ac) 2ax = -b ±√(b² - 4ac) x = -b ±√(b² - 4ac)/2a

@wyneducation6446 2 ай бұрын

Ohhh so cool! Never thought of that!

@suravinayan2753 2 ай бұрын

for question cii it's actually e*ln(x) not (1/e)*ln(x) *note:ln is Log base of e

@hamishbrown5446 2 ай бұрын

Cheers Mr McDermott 🙏

@wyneducation6446 2 ай бұрын

@hamishbrown5446 haha, good luck Hamish!

@nicholaswhiteoak4501 2 ай бұрын

Mr McDermott you are my goat! Year 10 was peak!!

@aryanmittal9197 2 ай бұрын

For b don’t we include 0.64 and -0.64 since at -0.64 it is still less than 1.1?

@wyneducation6446 2 ай бұрын

Hey, nah, at first look of this, when it says "less than" it means "strictly less than" which means it can't equal 1.1 so theta can't equal -0.64 or -0.64...so it has to be strictly between -0.64 and 0.64. AKA -0.64<x<0.64.

@krishsachdeva3086 2 ай бұрын

Can you please do a video on combinatorics and the hypergeometric formula at a yr12 level?

@boscomach8289 2 ай бұрын

Yes pls

@wyneducation6446 2 ай бұрын

kzbin.info/www/bejne/b3q7eph8eseVi6ssi=-RB3DuAqc6x6cfbJ Happy Studies...

@brendanward2991 2 ай бұрын

Nicely explained.

@SteveGouldinSpain 2 ай бұрын

I'm none the wiser.

@kuro6331 3 ай бұрын

Should Q3 d i be $10? The y axis is probability and the x is cost isnt it? So the max cost (x-axis) is 10. idk if i interpreted it wrong

@wyneducation6446 3 ай бұрын

@kuro6331 yep, totally agree, I fell into their trap there. $10 sounds better 👍

@kuro6331 3 ай бұрын

Q2 f) should be pi/3. You took the string length as 1.5 but its 0.5

@kuro6331 3 ай бұрын

For Q1 d) iii) k should be +-1, since the modulus of the integral is equal to p^4/4

@wyneducation6446 3 ай бұрын

Hey! Yes, totally agree. Haven't has a chance to go back and fix a few of these things. Thanks 😊

@Felix-sb5wp 3 ай бұрын

for q2e, I think its 21 no? 30/4pi/9 = 21.485 so test 21 and 22 21x 4pi/9 is 29.3 "" is 30.7 which is outside of the domain. so the 22nd time is not included.

@kuro6331 3 ай бұрын

i dont think thats right, the 21.485 should mean that it goes back to point A 21 times. when you include the fact that it started at point A, that makes 22

@Felix-sb5wp 3 ай бұрын

@@kuro6331 oh true

@Felix-sb5wp 3 ай бұрын

@@kuro6331 good point

@Moomorker 4 ай бұрын

how can the maximum for question 1a be 2 when the domain is -pi/3 to pi/3

@wyneducation6446 4 ай бұрын

Hey! You're right, I made a mistake there. I didn't check the domain properly. I think the correct answer is...minimum=1 and maximum=(5/4).

@RanveerSingh-l4q 5 ай бұрын

Hey, thank you so much for making the video, just a quick question, how hard u reckon this exam is?

@wyneducation6446 5 ай бұрын

Hey! I thought it was challenging. Like all Methods exams, the concepts are very similar but being able to do it effectively under timed conditions is another question. Also, so much depends of effective use of the CAS. There are a few questions I think I got wrong so I'll make some updates soon 😊

@RanveerSingh-l4q 5 ай бұрын

thank you so much!

@akaimo348 6 ай бұрын

For Q2 (b), it should be a is not equal to either -2 or 1 because as long as the slope of line 1 and line 2 are different, they will intersect at a certain point.

@wyneducation6446 6 ай бұрын

Yes, of course! Thanks for that pickup! 'a' is an element of real numbers not including {-2,1} 11:04

@vethumgunathilaka7674 6 ай бұрын

desmos>geogebra

@danngo2758 6 ай бұрын

sigma opinion

@rezamohamadakhavan_abdolla8627 6 ай бұрын

Lacking sound

@wyneducation6446 7 ай бұрын

The y and x-axis should just be depth against time. Not 'change in depth' against 'change in time' as shown on the graph

@wyneducation6446 7 ай бұрын

The y and x-axis should just be depth against time. Not 'change in depth' against 'change in time' as shown on the graph

@MarkMcDermott-qt5jw 8 ай бұрын

I said the the range of sin inverse is [-1,1] when I should have said that the domain is between [-1,1], the range of sin inverse is clearly [-pi/2,pi/2]

@wyneducation6446 10 ай бұрын

Anywhere where I have said 'x' I should have said 'theta'. Woops...happy studies!

@wyneducation6446 10 ай бұрын

At 1:47 I said that the smallest possible output is 1. I meant to say "0".

@jampastie5497 2 жыл бұрын

great video!

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