Thank you 👏

Wonderful and clear explanation! Thank you so much!

till today this is the best

How do you do this? I try and try but i cannot....

A high class teacher

Best proof I've seen of why academics are cowards. Yeah, I want to be just like you: unhealthy, weak, and creepy, impressing children, not able to earn a living on your own.

@11:50 For all x in the domain of f(x).

An easier way to calculate x^4-y^4 would be to factorise it to (x^2+y^2)(x^2-y^2).

Would be great if they brought together a good oceanographer like him with a atmospheric physicist to get the whole picture

Thanks for adding the subtitles!

these videos come in handy because i am learning CIF and residual theorem right now

Thank you for the lesson very instructive

58:10 goldbach requires proving the existence of 2 primes that add to 2z, not finding them. The professor has only proven that you cannot find them, not that they don’t exist.

1:45 how do you know that the last eigenvalue is 3?

Is the converse true?

Any Malawians??

Thank you for opening my brain 🧠🙏

this is well explained thanks for clearing this topic

Hi, very nice video as always from the UNSW maths department!!!!!!11

EXCELLENT LECTURE -WHICH COUNTRY ? -AMARJIT -INDIA

it is not complete play list is it? unless 2069 also has a calculus component like 1141 and 1241?

Has video contents please put it up

Has video contents please put it up

z_n should be z_i in the formula right? The integral symbol would also more correctly be a contour I think. Either way thanks for all these lectures it is highly appreciated!

Is it wrong to take Z=x + yi and simplify it?

9years later and i still found this very helpful. thank you sir

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Thankyou so much❤🎉well explained and clear understandable

Why isn't z bar analytic here?

Much Appreciated

interesting, never thought of the vertical lines along the surface of hyperboloid has the parametric function x=t, z=t y=1/-1, when you draw the hyperboloid on maple or matlab, it never grid that way.

I am sorry but i didnt get where did the 1728 constant emerge? I know where did the 1729 get from (its just 1728 + 1) but where do the 1728 come from? Please dont post replies about "integer complexity" of (1+1+1) * (1+1) and so on :D i know that its1728 == (3^3) * (2^6) but i just didnt hear the origin in the Gaussian resampling and multi dimensional rudimentation.

20:40 (1/2) i got a little different output in my classical sigma-delta calculator for these 2 random numbers ... 8.5397342226735670654635508695466 [ omitted digits my calculator didnt show] - maybe i should change the range of integration in the exponent part... I have heard about the limit O(NlogN) a long time ago, showed in signal processing classess with DFT and Parseval (Parceval?) power preservation theorem - thanks that in practical you made it twice as fast :). Usually when people face that big integers they are looking for some other thing than a multiplication or they can suffice with some fast HW (fpga?) high order (2kbit 4kbit 256kbit) implementation for security reasons :) Regarding Kolmogorov - at that time in the soviet (USSR/CCCP) there were many scientist showing work proving the state of the party either in agriculture or in biology that nobody could deny - i am sure that Kolmogorov could have also stated that O(n^2) is the slowest of multiplication algorithms as children can do it that way and nobody would bother to object :)

try to improve on your steps to make it more simplifying

Find the fifth roots of z=-1+i

go find another job

thanks very much you are getting better

Even though your leading entry is not equal to 1 you still get same answer. No one will doing that like you

you don't really to simplify that much it make student confused. you still can get the same answer in the end. Make sure don't do that next time.

Suppose a group of 20 students are enrolled in one or more of the following courses: 8 in Algebra, 12 in Biology, and 11 in Chemistry. If 5 students are enrolled in all three courses, how many students are enrolled in at least one of these courses? help me with this please

Thank you sir really help a lot

what about c.) bruh

Thanks fo' the help son!!

so smartly solved