what is the question fpr this problem? i mean in words of paragraph?
@SaeedAmiri702 күн бұрын
What's the reason for changing curve concavity by changing fluid? Does it depend on varying K or Cp values by temperature along the heat exchanger?
@kylecatman77384 күн бұрын
I DO NOT agree that there is no work in this problem, the volume is increasing 4 fold for christ sakes!! Plus, the piston is being moved for crying out loud!! Total Bull on this one Falconer!!!
@rckygrhm15 күн бұрын
Awesome! a very clear explination.
@muhammadshehreyarkhan18516 күн бұрын
I guess this formula is for UA clean & in case of UA dirty we have to add the fouling factor contributions on the inner & outer of the surface as well. What is the equation for that? Will the fouling factors be assumed from literature or calculated?
@muhammadshehreyarkhan18516 күн бұрын
Indeed a picture is worth thousand words.
@muhammadshehreyarkhan18516 күн бұрын
Thanks for the explanation in detail. In case of the reboiler using heat transfer fluid other steam which does not change phase i.e. hot oil, will the heat transfer coefficient of the reboiler be the same as that of the condenser?
@miguelangelcandeno49967 күн бұрын
Using userform with checkbox in WORD?
@mirzasalkic525210 күн бұрын
Could you explain why in the eq 7 there is + in front of the x1*W, when I found its originally - there
@RD-ud3eh10 күн бұрын
1:02 I have been unable to put/spin the turbun onto my head using this system, any ideas?
@omarhafiz599610 күн бұрын
So helpful, thanks
@jonathanstraiton460111 күн бұрын
Why is there a coefficient of "2" in the mass balance for A? I thought that was already accounted for with the Ca^2
@tanyilun299013 күн бұрын
May I know which simulator are you using?
@marysherry762513 күн бұрын
What is x? And what is the purpose of solving x=0.91?
@CalebDietrich13 күн бұрын
You multiply the H values (BTU per lb) by the total pounds of each stream in your energy balance. Are the units of H in "BTU per lb of total mixture" or "BTU per lb of H2SO4"? If you think about it, the enthalpy of mixing arises from mixing the H2SO4, not the other stuff in solution (which should be arbitrary to the total heat). So accounting for only the masses of H2SO4 from in and out of the mixer in the energy balance makes most sense to me. Is this logic flawed?
@DheepakKumar-dq9nx13 күн бұрын
We are taking the differential element, then why rdθ why not ∆rdθ?
@user-dy6vq7vd7k15 күн бұрын
Great Video. Just to mention, your link doesnt work for the calculator.
@LearnChemE13 күн бұрын
Thanks for the note. KZbin stopped allowing annotations, but the link is in the description and now on a card (the information button on the top right).
@CalebDietrich16 күн бұрын
Also, keep in mind that this video uses the Darcy friction factor (64/Re = f for laminar flow) as opposed to the Fanning friction factor (16/Re = f for laminar flow). Therefore, (7:32) h_L = f(L/D)*v^2/(2*g) is correct for Darcy friction factors, but h_L = 2f(L/D)*v^2/g for fanning friction factors. The friction factors are essentially different by a factor of 4 (therefore f_f * 4 = f_d).
@CalebDietrich16 күн бұрын
(4:46) The exact numbers are debated, but generally Re<2100 is laminar, 2100<Re<4000 is transitional, and 4000<Re is turbulent. In engineering practice, 10,000 < Re is fully turbulent (this is for internal flow through pipe).
@CalebDietrich16 күн бұрын
For anyone who was wondering, I think the friction factor used in this video is the Darcy friction factor (64/Re = f) as opposed to the typical Fanning friction factor used by Chemical Engineers (16/Re = f). Both are equally valid, but it should always be specified which is being used. To get from Fanning to Darcy friction factors multiply the fanning friction factor by 4 (f_F * 4 = f_D)
@shanoraheem18 күн бұрын
thank you this video is really amazing
@wheelsoncrisis19 күн бұрын
Good video mate
@ruler000719 күн бұрын
12yr later u r a life saver m gonna younk this derivation nd write it in my Master degree exam Ps-studying this 3 hr befor exam u r life saver 😢
@gamingwithdingo21 күн бұрын
I love this guy
@themovingmachine732122 күн бұрын
thank you so much. I read many and many explaination but I cannot understand until saw yours
@esosaekuobase475322 күн бұрын
Thanks
@jayavardhan076025 күн бұрын
Great illustration
@maxarnold20626 күн бұрын
Excellent video thx
@akindekoayoola980227 күн бұрын
Thanks
@liamj3141527 күн бұрын
Thank you
@Falcon724-rh9iz29 күн бұрын
C is the correct answer
@muhammadomarkhayyamkhan3593Ай бұрын
You are a wonderful teacher. Please make videos on thermodynamics. You explain all little steps . Thank you very much .
@wernervanderstratenАй бұрын
Well, i did the calculations and got -39.1Kj for one mole total of condensing the mentioned gas mixture of CH3OH and H2O.
@user-nr7qt6ss2uАй бұрын
You need to put a compressor/limiter on your vocals
@samjohnson609Ай бұрын
How are you getting Z value???
@tomnethan757Ай бұрын
I have never understood the actual meaning of DOF.
@ShaneWelcherАй бұрын
Thank you for helping the automation industry, we all have to do our part to help the growth
@user-cz5qd6nd4jАй бұрын
See the running carnot engine. kzbin.info/www/bejne/eaHWmKukf8yYpqc&pp=ygUUUm90YXJ5IENhcm5vdCBFbmdpbmU%3D
@dchanna2656Ай бұрын
2:49 where is the notation for partial derivative w.r.t. Y
@partyhardcakeАй бұрын
Good stuff
@gooddeedsleadto7499Ай бұрын
How pressure remains constant in condenser despite the temperature drop from superheat rejection after compressor & sub-cooling heat rejection before expansion valve? Thank u How pressure remains constant in evaporator despite temperature rise from superheat gain before compressor?
@jinjan1552Ай бұрын
Hi ,@3:54, T is indepent of density, which I don't understand , could you explain??
@jinjan1552Ай бұрын
Ok, I see, calculating departure function @constant Temperature. Add that maybe clearer. Just my 2 cents
@berkanbayndr6138Ай бұрын
el yazını sikeyim
@alialthuraya5646Ай бұрын
I have some questions I want discussion with who have experenice with membrane , if have email ,u can tell me it i will message u
@abrahamyrnАй бұрын
This was very helpful, thanks to you❤️🙏🏾
@thucpham4598Ай бұрын
there is a trick in Question 4 for me. So in this case, the kinematic viscosity of air > water, so the critical point of air is further (according to the formula). But in reality, the fluid with smaller kinematic viscosity, its critical point will be further! This means water will have the further point! Can you help me to explain, thank you so much!
@heysora6075Ай бұрын
How to graph it using equilateral? Its so confusing…