Good

others have said it too, but with more explanation; steps 5 and 6 should use D' and d'. L / (360° - ∠0°) = (D' * pi) / 360° L and l (lowercase L) are just a fraction of the full circumference of the circle with a diameter of D' (so to find the theoretical full circumference 2*pi*r you get D' * pi). Its essentially just creating a ratio of the sectional length at the unknown angle to the theoretical length of the full cutout diameter at 360°. This was a very good explanation otherwise, I wasn't sure how to go about this at all, but unfolding the cylinder spiral really was an "ooooh that makes perfect sense" moment and its simpler than I thought. This doesn't account for material thickness / bending though but it should at least get you in the ballpark, and the thinner the material you use the closer you should get to having the cutout work as intended for a prototype or something.

I liked watching the video, you are amanzing!

Thanks for this video Please share link the application ✌️

Finally i learned 🫠👍

Good afternoon! Can I buy equipment or drawings from you?

App download link send

#Thank you sir 🙏🙏🙏🙏🙏🙏🙏🙏

Good day There is one videos i saw in your channel for Designing of a 15000 Gals elevated Steel Tank. I saw that its comment section is turned off. I really liked the video and was hoping to find more of this type and possibly other Structural design related videos. I am working on a similar project which i am designing. I was hoping to get any help i can. If there are other channels you have related to the topic or any other channel, kindly share. 😊😊😊😊

copying our company's patent did make things easier, huh?

Perfect explanation. And not too ear bleeding accent. Thank you very very much

기계교수님 정말 궁금했는데 기계영상 정말 감사합니다

Very clear and easy to understand explanation.... can you also make a video for screw flight layout how to calculate inside diameter if the shaft diameter is increasing or tapered shafting

Bro please share the formula for making die

Would like if the music was turned down. Can barely listen to your voice in the background.

Please provide the application link

sir, in opening chain weight 8 kg/m, why at the ending slide weight of chain change to 2,5 kg ??

👍

I didn't understand that 7.9/0.7457= 5.9kw

God bless u sir. Got it easily.

I Love you SO much THANKsssssssssssss😍😍😍😍

Thanks

Asked for the app please

Horrible video learn not to breathe in to the mic ffs

Sir vanakkam I want full formula details please Thanks

Please make a video or share size for D-300, P-300, d-72 T-3 mm

6:03 The output appeared to me - 2 what to do? 😅

❤❤❤❤

great can you share app link?

Sir can you upload video on Fabrication of limpet coil on cone

so two types

Please share app link sir

ehoo: look at me

D should be D'

Receive greetings from kenya

Nice explanation and informative video. Please share link.

Please share link for apk

Sir, I am making a spiral with discs, outer dia is 3" & inner dia is 1.5" Can you please help me make the pattern to cut. Thank you Sir

How to get the application sir? Im interested.

Пригодится в жизни,сегмент можно и не вырезать,а на последнем кольце вырезать сумму углов.

Whit cursus i need to do this ?

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

Can you share the apk file? Thanks.

Good information ji sir tq so much for giving this information

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor

Please share with me a link of the app

Need application

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