x=log30/log3=(log3×log10)/log3=1+1/log3 x≈1+1/0.477≈1477/477≈3.096 Deviation is about 0.0005 3^3.096≈30.003

x-1=(log4-log5)/log5 x=2log2/log5 x≈2×0.301/0.699≈602/699≈0.8612 Deviation is about 0.0001 5^(602/699-1)≈5^(-97/699)≈0.79984

7^x(7²+1)=70 7^x=7/5 x=(log7-log5)/log7=1-log5/log7 x≈1-0.699/0.845≈146/845≈0.1728 Deviation is about 0.0001 7^2.1727+7^0.1728≈69.985

x=log45/log5=(log5+log9)/log5=1+2log3/log5 x≈1+2×0.477/0.699≈551/233≈2.365 Deviation is about 0.0004 5^2.365≈44.985

x=log120/log8=(log8+log15)/log8=1+(log3+log5)/3log2 x≈1+(0.477+0.699/(3×0.301)≈693/301≈2.3023 Deviation is about 0.00003 8^2.3023≈120.00078

x=log60/log4=(log4+log3+log5)/log4=1+(log3+log5)/2log2 x≈1+(0.477+0.699)/(2×0.301)≈889/301≈2.95349. Deviation is about 0.00004. 4^2.95349≈60.0037.

5^1,215… x 5^1,215….. = 50

Круто он с ним разделался !!! 😆😅😂🤣

Это уравнение уровня математической олимпиады?! Это обычное показательное уравнение обычного 11 класса. Но как же вы его размусолили.

x³ - x² = 18 = 3³ - 3² x = 3 😊

Nicely explained

let t = 7× 7² * t + t = 70 50t = 70 5t = 7 t = 7/5 7× = 7/5 log(7×) = log(7/5) x * log(7) = log(7) - log(5) log(7) - log(5) x = --------------------- log(7) log(5) x = 1 - --------- log(7)

X^X=8 3^X=? Please

3*3*3 - 3*3 = 27 - 9 = 18 8 seconds

Debe tomar solo 2 minutos el video

Mathematics

(Log(12/7))/(log(6))

a = log(40) ÷ log(5) a = log(4 * 10) ÷ log(5) a = [log(4) + log(10)] ÷ log(5) log(4) + 1 a = ------------------ log(5)

200=100x2 log200 = log100 + log2 log200 = 2+log2

x=log_4(60)=2.953445297804259 4^2,953445297804259=60

x³ - x² = 18 27 - 9 = 18 x³ = 27. x² = 9 x = 3. x = 3 So, x=3 x=3

c pour ça que le Nigeria est sous développé

payı 3 üssü 49 ortak çarpana alalım. sonuç B şıkkı. keşke ingilizce bilsem .ben 70 yaşındayım Türkiye de matematik öğretmenliği yaptım şimdi emekliyim. zevk için izliyorum. İyi seneler.

Guessed it

😊too easy for olympiad level

How does this Math Olympiad score the answers? This is an awkward-looking expression for x. Wouldn't it be simpler to say A=6^x, 6^(x+2)=36*A, 35A=60, 7A=12, A=12/7, x = log base 6 of 12/7 which a forbidden calculator tells me is approximately 0.300819674733

Good ❤

6^x+2 - 6^x=60

X=1+log²-log⁷ 6 6

6^x(6²--1)=60 6^x=12/7 x=(log6+log2-log7)/log6=1+(log2-log7)/(log2-log3)≈1+(0.301-0.845)/(0.301-0.477)≈1-544/788≈234/778≈0.30077 Deviation is about0.00005 6^2.30077-6^0.30077≈59.995

Can one not take log2 from log 7 to get log 2/7 at base 6? ( and then just look that up and avoid another 30 steps 😀

X=(in(12/7))/in6

x=10

👍 great job

Good job

Why aren't there three solutions, since the highest power is 3? Thanks for the great videos.

Very clear, thanks!

Please simply apply log to base 10 to both sides and solve.

You explain this very well and it is very helpful that you do this step by step with such a large variety of examples

1- In multiplication, if the bases are the same, the exponents are added regardless of what they are. 2- The result is reached by multiplying the difference of two squares using the addition-subtraction method.🙏

54

Great work my fellow Mathematician ❤ Is there crime when I just use calculator

👏🏻

B

Instead of doing log(2*5)/log6, why not keep it log10/log6?

Interesting 🎉

Interesting 🎉

Interesting 🎉

You complicated a lot .easy way could be

Interesting 🎉