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@johnusadispatch 7 күн бұрын

2^256 and the story is ended... No algorithm can search this range... maybe quantum in the future

@linanwx6217 11 күн бұрын

Good video with mistake

@pbvideo5412 Ай бұрын

The definition of linearity on the first slide is incorrect. It should be <λx+y, z> = λ<x, z> + <y, z>.

@ProfessorX12321 Ай бұрын

how can we do this for module lwe?

@Chipster-r6o Ай бұрын

Hi Jean-Francoise, I would like to thank you for sharing this amazing content on Lattice based cryptography , I just have one question ...based on the assumptions of the proof that works out the bound on lambda(L) @15: 34 , shouldn't the Volume of the hypercube be greater than 2^n * Vol (L) for Minkowski's theorem to be applicable ?

@W_Z_Y_X 2 ай бұрын

When using the primal attack for MLWE, do you just plug A' found from the circulant matrix into the lattice (Im x n A'), or do you substitute A' as A from the LWE example?

@CynthiaHiggins-g7x 2 ай бұрын

Fritz Ferry

@allaboutastronomyy 2 ай бұрын

at 21:36, can you please explain how we got the A matrix? Thanks!

@JoeCharron-c4g 2 ай бұрын

Labadie Stravenue

@ScottHugo-t4d 2 ай бұрын

Arlie Ports

@LeopoldCamille-y3z 2 ай бұрын

Jude Circle

@RavenMariah-o3u 2 ай бұрын

Tierra Path

@HelenBrown-z1l 2 ай бұрын

Bernier Squares

@jimihendrixx11 3 ай бұрын

Well explained & taught 😊

@jimihendrixx11 3 ай бұрын

Cryptosystems😊

@MuscleTeamOfficial 4 ай бұрын

Go bulls lol

@principalcookie2163 4 ай бұрын

Do you have a source, explaining why this works?

@hosseinbornak 4 ай бұрын

thank you very much

@JakeHemmerle 5 ай бұрын

at 6:08, why is Span(S) = R^3 and not Z^3? While V = R^3, the vectors are a subset of R (specifically, in Z), so wouldn't Span(S) be Z, since we're just using whole numbers, eg (0,1,0). Isn't Span(S) a subset of R^3?

@gameshoot8571 5 ай бұрын

This channel is so underrated! Thanks!

@yacc1706 5 ай бұрын

7:48 important: BS is a PBS, what divides in state Vx with cos2theta, and state Hy with sin2theta. The second PBS "recombines" the original state

@yacc1706 5 ай бұрын

23:54 a possible explanation, I think, is that "something" goes both paths and recombines in space and time in the second PBS to give the original state. If a path is longer than the another, then it doesn't get the original state. And if we put detectors in both paths ONLY ONE will get a click

@yacc1706 5 ай бұрын

23:04 erratum??? Is it not: cos H kl + sin V ku ???

@franciskv2859 6 ай бұрын

Very good

@bouncycrabboomz 6 ай бұрын

Thanks for the clear and great proof on Minkowski's convex body theorem. It really helped alot

@sebastiannunez1362 6 ай бұрын

Hi! I think you mean "How many functions F(0) = F(1) are there?"

@aspidistrax_x2722 10 ай бұрын

Thank you for ur awesome video. I only wish u added an example of asymmetric lwe in the end. Im a bit lost.

@PunmasterSTP 10 ай бұрын

I'm still trying to wrap my head around this material, but this was a nice clean lecture. Thank you for making and sharing it!

@PunmasterSTP 10 ай бұрын

I haven't come across Maple in a while; it's cool to see it again!

@PunmasterSTP 10 ай бұрын

How'd you start with x0 = y0 = 2 and get x1 = 8 and y1 = 68? Anyway, this was a cool video 👍

@AmitYellin Ай бұрын

X²+4

@PunmasterSTP Ай бұрын

@@AmitYellin Yeah, I guess he just changed his mind while coming up with the example and forgot to update part of his script.

@akhsinak Ай бұрын

true lol

@hanie.e 10 ай бұрын

this helps a lot, thank you!

@omargaber3122 10 ай бұрын

Great thank

@jameskingsbery3644 Жыл бұрын

The audio is pretty quiet on this one.

@pmatos0071 Жыл бұрын

Excelent video. Thanks for that. Pleasr keep up the good work. 🎉

@windy-j7f Жыл бұрын

Thanks for u video, but why did I get an A' in the form of some fractions?

@windy-j7f Жыл бұрын

emmm,I got the right consult,but What if the elements and modules in the matrix are not mutually prime。。。

@theping1920 Жыл бұрын

how is x1 = 8 and y1 = 68 shouldnt it be x1 = 5 and y1 = 26 ?

@karthiksk2748 Жыл бұрын

That's what Im too confused

@dwightschrute4056 Жыл бұрын

Same doubt here

@0phir123 Жыл бұрын

same here lol, happy X-MASS btw :D

@PunmasterSTP 10 ай бұрын

Yes, and I think we're all confused!

@Abcabraabc 2 ай бұрын

i think he used p(x) = x^2 + 4 instead for some reason

@ThefamousMrcroissant Жыл бұрын

Thanks again for making these easy to digest videos

@bennieterrell4139 Жыл бұрын

"Promo SM"

@jackbreeazy6710 Жыл бұрын

I could barely hear you as well but the video is good otherwise...

@ThefamousMrcroissant Жыл бұрын

The example of LWE is marvelous however. Bit heavy on the rounded Gaussian maybe (which didn't feel like it was important enough to take up 1/3 of the entire lecture), but overall easy to grasp. Thanks for publishing this to youtube as well.

@ThefamousMrcroissant Жыл бұрын

This has to be the most confusing explanation of Gaussian elemination I've ever seen. For example in slide 4:28 what are the indices here? In step 1 they are (column, row), but in step 3 they're suddenly rows? This is one of the extremely few instances were Wikipedia is actually way more understandable than some introductory video. At around 6:13 you reduce row 1 by subtracting row's 2 coefficients from it twice, but how does that result in -2 when the residue class is already at 0 at that point?

@IP1kachuI Жыл бұрын

The video is too silent, (much) louder would be better

@morrisbarnett4457 Жыл бұрын

promo sm

@danceordrink Жыл бұрын

Thank you but why does x2 also contribute to the second qubit?

@sumanghosh8390 2 жыл бұрын

calculation mistake when calculating c'=c.P^{-1}=(1,0,0,1,1) it should be (1,1,0,1,1) so we can get back the correct message (1,1)

@niafally1240 2 жыл бұрын

Great Video! Thank you! The only thing I'm not sure about is: what exactly is the difference between Ring LWE and Module LWE? If you could explain, i'd be very grateful! Thanks again!

@usfcryptocenter9924 2 жыл бұрын

Good question! Ring-LWE is Module LWE with k=1. Check out our notes here: www.usf-crypto.org/lattice-based-crypto/ (apologies for the typos).

@niafally1240 2 жыл бұрын

@@usfcryptocenter9924 awesome! Thanks! :)