Great teaching style. Thank you for the refresher lesson
@dremph5611Ай бұрын
Thank you!
@Crown-and-DownАй бұрын
A song about the beheaded Anne Boleyn
@ricardoprata6102Ай бұрын
Great video
@dremph5611Ай бұрын
@@ricardoprata6102 thank you!
@durojaiyedaniel72 ай бұрын
thank ypu very much sir, It really helped alot. Daniel from NIGERIA
@alfredjuliant99282 ай бұрын
Thank you so much, you saved my mid exam. God bless you sir
@yasirshah84683 ай бұрын
This is an excellent summary of the key pillars of Beam Theory, even for seasoned professionals, in a very concise delivery format, thank you Dr. Hernandez and hope that you continue distilling out similar content in the future!
@dremph56113 ай бұрын
@@yasirshah8468 Thank you!
@gnidnoeled7864 ай бұрын
About "c" that you are referring to in f(c), is it the location of the neutral axis in the strain diagram?
@LachieMac5 ай бұрын
Hey, are these two deflection eqn found definitely right?
@dremph56115 ай бұрын
The correct answer for the tip deflection is simply the deflection at b + angle(at b)*a,. This is true because the end portion of the deflected shape is simple a straight line. This comes out to = Pb^3/3EI + Pab^2/2EI. If you plug in x=a+b on the equation for the deflection of the end portion, you get this answer. Did you try that?
@LachieMac5 ай бұрын
Theres a mistake in your integration at 3.42
@dremph56115 ай бұрын
Yes, you are correct, but I actually realize (in real time) that I have a mistake and fix it in 8:40...Good eye!
@LachieMac5 ай бұрын
@@dremph5611 Ah! i see, great pickup!
@asbernraj25576 ай бұрын
En vaalkaiyai kaapathiviteergal aiyyaa
@BB-rm3tp8 ай бұрын
Thank you Dremph... Possibly the best explanation out there...no BS...just logic. Thanks
@PhyDingmyway8 ай бұрын
I am studying system identification and I found the 2 videos regarding state-space models of yours super helpful!!
@dremph56118 ай бұрын
Thank you! Glad to hear they were useful.
@tommytran596210 ай бұрын
THANK YOU
@amalms9201 Жыл бұрын
Interesting indeed!
@alligodfreyukuni2975 Жыл бұрын
Good presentation
@CivilEngr555 Жыл бұрын
If there were 3 legs, would all 3 be considered for torsional At/s?
@CivilEngr555 Жыл бұрын
If there were 3 legs, would all 3 be considered for torsional At/s?
@dremph5611 Жыл бұрын
Depends on the location. Since this reinforcement is designed to resist torsion, the reinforcement near the perimeter is more effective than the reinforcement near the center. Personally, I would only account for it if it is on the perimeter.
@Abhi-nandan Жыл бұрын
Sir your videos are great....Sir i have a doubt that what is the purpose of using logarithm in calculation....?
@chaturyavegi1082 Жыл бұрын
Thanks a lot sir . The video is very informative . A small doubt sir. Like if we need to find the value of A i.e., cross sectional area ..., We can use the derived formula , but we also need to know the value of Integration constant. How to find it sir.
@peterhun3185 Жыл бұрын
Great explanation.
@danieltembo3376 Жыл бұрын
❤
@stonecope4412 жыл бұрын
Weight
@garyadamos2 жыл бұрын
🤯
@mohamedharun53552 жыл бұрын
you are the best
@gamingfps16112 жыл бұрын
Av including all legs or only the outers legs???
@dremph56112 жыл бұрын
Av is the shear reinforcement (regardless of its location). It must adhere to the definition/requirements of shear reinforcement.
@btulsa89832 жыл бұрын
Thank you
@李守宝2 жыл бұрын
can you share the code?
@johnt21402 жыл бұрын
thank you very much
@matteoponzano33182 жыл бұрын
Not sure for shear. Critical Section is inclined, as shear stresses, in italian classical text, not vertical. Max Shear stress is at the centre of rectangular section, so your critical section should be at d/2 not at d. More you must consider that max shear stress at the centre is 1.5 times mean value. Where i wrong?
@kerenjacob5298 Жыл бұрын
This must be from some other code I'm guessing. ACI code says to take critical section at distance d
@asterixgalo60203 жыл бұрын
Thanks
@samridhimishra26403 жыл бұрын
This is what I was searching for..... amazing
@NurHafizh3 жыл бұрын
Thank you sir,
@Shishir-Veer3 жыл бұрын
Thank You Sir for Sharing!
@fahadmohamedaliadawe28833 жыл бұрын
How about if do moment in terms of y
@arash42323 жыл бұрын
Thank you so much. That was grate.
@ziaulhasan67203 жыл бұрын
Thanks
@khaledtaha48143 жыл бұрын
you just saved my life.
@arwindersingh68794 жыл бұрын
great sir👍
@avulashandilya98844 жыл бұрын
Sir can you please make some videos on polar moment of inertia.
@vaibhavpatel64014 жыл бұрын
Can you name the text book?
@CR7andLetoFan3 жыл бұрын
Anil K. Chopra , Dynamics of Structures
@shivamsangar4 жыл бұрын
Why is Torsion- Vu x e ??
@dremph56112 жыл бұрын
I just saw this, apologies for the (very) late reply. It is because "e" is the eccentricity that exists between the externally applied force and the internal shear force resisting that force.
@diabrown4 жыл бұрын
Thank you for this!
@dremph56114 жыл бұрын
Thank you!...
@FaisalKhan-tv6vp4 жыл бұрын
Aoh should be equal to 174.25 in2 not 200.5 in2.
@Prepre10184 жыл бұрын
Hi! Thanks for the lecture :) I do have a question though, why is it @2:35 the Tt = 3.94 then @6:21 it became 4.55?
@TheArchicad4 жыл бұрын
Awesome
@chetankumar94634 жыл бұрын
1.Can you please tell that what if i takes a critical section for shear at the point of max. Shear force. Is the design wrong or it is only uneconomical but ok. 2.what should be the critical section if the beam is over hang from one side with 2 supports and a udl over the whole span.
@anujasohani87584 жыл бұрын
Instead of providing only the corner bars can I provide reinforcing bars in the inner side as well? will that be able to resist the applied torsion?
@udaysharma85123 жыл бұрын
did you find the answer?
@MaycolRugamaIdiaquez4 жыл бұрын
Profesor que libro está usando?
@dremph56114 жыл бұрын
No es un solo, he tomado informacion de varios. Te puedo mandar una lista por email.