Stiffness Matrix - The Basics
24:29
How  long can a cantilever be?
10:17
4 жыл бұрын
JS Bach BWV1007 - Prelude
3:04
4 жыл бұрын
Classical Damping in Modal Analysis
12:08
Пікірлер
@alexanderezeh5084
@alexanderezeh5084 Ай бұрын
Great teaching style. Thank you for the refresher lesson
@dremph5611
@dremph5611 Ай бұрын
Thank you!
@Crown-and-Down
@Crown-and-Down Ай бұрын
A song about the beheaded Anne Boleyn
@ricardoprata6102
@ricardoprata6102 Ай бұрын
Great video
@dremph5611
@dremph5611 Ай бұрын
@@ricardoprata6102 thank you!
@durojaiyedaniel7
@durojaiyedaniel7 2 ай бұрын
thank ypu very much sir, It really helped alot. Daniel from NIGERIA
@alfredjuliant9928
@alfredjuliant9928 2 ай бұрын
Thank you so much, you saved my mid exam. God bless you sir
@yasirshah8468
@yasirshah8468 3 ай бұрын
This is an excellent summary of the key pillars of Beam Theory, even for seasoned professionals, in a very concise delivery format, thank you Dr. Hernandez and hope that you continue distilling out similar content in the future!
@dremph5611
@dremph5611 3 ай бұрын
@@yasirshah8468 Thank you!
@gnidnoeled786
@gnidnoeled786 4 ай бұрын
About "c" that you are referring to in f(c), is it the location of the neutral axis in the strain diagram?
@LachieMac
@LachieMac 5 ай бұрын
Hey, are these two deflection eqn found definitely right?
@dremph5611
@dremph5611 5 ай бұрын
The correct answer for the tip deflection is simply the deflection at b + angle(at b)*a,. This is true because the end portion of the deflected shape is simple a straight line. This comes out to = Pb^3/3EI + Pab^2/2EI. If you plug in x=a+b on the equation for the deflection of the end portion, you get this answer. Did you try that?
@LachieMac
@LachieMac 5 ай бұрын
Theres a mistake in your integration at 3.42
@dremph5611
@dremph5611 5 ай бұрын
Yes, you are correct, but I actually realize (in real time) that I have a mistake and fix it in 8:40...Good eye!
@LachieMac
@LachieMac 5 ай бұрын
@@dremph5611 Ah! i see, great pickup!
@asbernraj2557
@asbernraj2557 6 ай бұрын
En vaalkaiyai kaapathiviteergal aiyyaa
@BB-rm3tp
@BB-rm3tp 8 ай бұрын
Thank you Dremph... Possibly the best explanation out there...no BS...just logic. Thanks
@PhyDingmyway
@PhyDingmyway 8 ай бұрын
I am studying system identification and I found the 2 videos regarding state-space models of yours super helpful!!
@dremph5611
@dremph5611 8 ай бұрын
Thank you! Glad to hear they were useful.
@tommytran5962
@tommytran5962 10 ай бұрын
THANK YOU
@amalms9201
@amalms9201 Жыл бұрын
Interesting indeed!
@alligodfreyukuni2975
@alligodfreyukuni2975 Жыл бұрын
Good presentation
@CivilEngr555
@CivilEngr555 Жыл бұрын
If there were 3 legs, would all 3 be considered for torsional At/s?
@CivilEngr555
@CivilEngr555 Жыл бұрын
If there were 3 legs, would all 3 be considered for torsional At/s?
@dremph5611
@dremph5611 Жыл бұрын
Depends on the location. Since this reinforcement is designed to resist torsion, the reinforcement near the perimeter is more effective than the reinforcement near the center. Personally, I would only account for it if it is on the perimeter.
@Abhi-nandan
@Abhi-nandan Жыл бұрын
Sir your videos are great....Sir i have a doubt that what is the purpose of using logarithm in calculation....?
@chaturyavegi1082
@chaturyavegi1082 Жыл бұрын
Thanks a lot sir . The video is very informative . A small doubt sir. Like if we need to find the value of A i.e., cross sectional area ..., We can use the derived formula , but we also need to know the value of Integration constant. How to find it sir.
@peterhun3185
@peterhun3185 Жыл бұрын
Great explanation.
@danieltembo3376
@danieltembo3376 Жыл бұрын
@stonecope441
@stonecope441 2 жыл бұрын
Weight
@garyadamos
@garyadamos 2 жыл бұрын
🤯
@mohamedharun5355
@mohamedharun5355 2 жыл бұрын
you are the best
@gamingfps1611
@gamingfps1611 2 жыл бұрын
Av including all legs or only the outers legs???
@dremph5611
@dremph5611 2 жыл бұрын
Av is the shear reinforcement (regardless of its location). It must adhere to the definition/requirements of shear reinforcement.
@btulsa8983
@btulsa8983 2 жыл бұрын
Thank you
@李守宝
@李守宝 2 жыл бұрын
can you share the code?
@johnt2140
@johnt2140 2 жыл бұрын
thank you very much
@matteoponzano3318
@matteoponzano3318 2 жыл бұрын
Not sure for shear. Critical Section is inclined, as shear stresses, in italian classical text, not vertical. Max Shear stress is at the centre of rectangular section, so your critical section should be at d/2 not at d. More you must consider that max shear stress at the centre is 1.5 times mean value. Where i wrong?
@kerenjacob5298
@kerenjacob5298 Жыл бұрын
This must be from some other code I'm guessing. ACI code says to take critical section at distance d
@asterixgalo6020
@asterixgalo6020 3 жыл бұрын
Thanks
@samridhimishra2640
@samridhimishra2640 3 жыл бұрын
This is what I was searching for..... amazing
@NurHafizh
@NurHafizh 3 жыл бұрын
Thank you sir,
@Shishir-Veer
@Shishir-Veer 3 жыл бұрын
Thank You Sir for Sharing!
@fahadmohamedaliadawe2883
@fahadmohamedaliadawe2883 3 жыл бұрын
How about if do moment in terms of y
@arash4232
@arash4232 3 жыл бұрын
Thank you so much. That was grate.
@ziaulhasan6720
@ziaulhasan6720 3 жыл бұрын
Thanks
@khaledtaha4814
@khaledtaha4814 3 жыл бұрын
you just saved my life.
@arwindersingh6879
@arwindersingh6879 4 жыл бұрын
great sir👍
@avulashandilya9884
@avulashandilya9884 4 жыл бұрын
Sir can you please make some videos on polar moment of inertia.
@vaibhavpatel6401
@vaibhavpatel6401 4 жыл бұрын
Can you name the text book?
@CR7andLetoFan
@CR7andLetoFan 3 жыл бұрын
Anil K. Chopra , Dynamics of Structures
@shivamsangar
@shivamsangar 4 жыл бұрын
Why is Torsion- Vu x e ??
@dremph5611
@dremph5611 2 жыл бұрын
I just saw this, apologies for the (very) late reply. It is because "e" is the eccentricity that exists between the externally applied force and the internal shear force resisting that force.
@diabrown
@diabrown 4 жыл бұрын
Thank you for this!
@dremph5611
@dremph5611 4 жыл бұрын
Thank you!...
@FaisalKhan-tv6vp
@FaisalKhan-tv6vp 4 жыл бұрын
Aoh should be equal to 174.25 in2 not 200.5 in2.
@Prepre1018
@Prepre1018 4 жыл бұрын
Hi! Thanks for the lecture :) I do have a question though, why is it @2:35 the Tt = 3.94 then @6:21 it became 4.55?
@TheArchicad
@TheArchicad 4 жыл бұрын
Awesome
@chetankumar9463
@chetankumar9463 4 жыл бұрын
1.Can you please tell that what if i takes a critical section for shear at the point of max. Shear force. Is the design wrong or it is only uneconomical but ok. 2.what should be the critical section if the beam is over hang from one side with 2 supports and a udl over the whole span.
@anujasohani8758
@anujasohani8758 4 жыл бұрын
Instead of providing only the corner bars can I provide reinforcing bars in the inner side as well? will that be able to resist the applied torsion?
@udaysharma8512
@udaysharma8512 3 жыл бұрын
did you find the answer?
@MaycolRugamaIdiaquez
@MaycolRugamaIdiaquez 4 жыл бұрын
Profesor que libro está usando?
@dremph5611
@dremph5611 4 жыл бұрын
No es un solo, he tomado informacion de varios. Te puedo mandar una lista por email.
@raulbrito2792
@raulbrito2792 4 жыл бұрын
Muy buen interpretación Eric.