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The best teacher I have ever seen ❤❤

i like your explanation Teacher MJ😍🤩

Nice question 👍👍

you use just addition to solve this, very goood👌

good question and simple solution

Think about this. Divide the first equation by 2 and subtract it from the last four equations. What happens? The unknown variable x disappears from the last four modified equations. Now scale the modified second equation and subtract it from the remaining three modified equations to cancel out the unknown y variable from the last three modified equations. Then scale the new modified third equation and subtract it from the remaining two modified equations to cancel out the unknown z variable. Then scale the new modified fourth equation and subtract it from the remaining modified equation to cancel out the unknown w variable. The final modified fifth equation contains only the unknown u variable. You have just performed forward elimination. Now solve for u, then for w, then for z, then for y, and finally for x, and you have just performed backward substitution. This is the most straight forward and simplest method, but could fail for many systems of linear equations. That is where Gilbert Strang's "Linear Algebra" book comes to the rescue to help students understand the Gaussian Forward Elimination and Back Substitution processes and why Gaussian Elimination with Complete Pivoting is the most reliable method for solving systems of linear equations.

I would teach the more advanced students how to perform Gaussian Elimination with Complete Pivoting, (GECP) and they would be able to reliably solve any set of linear equations. This set of linear equations doesn't require GECP because they are linearly independent and already given in optimal order for direct forward elimination and back substitution. Teach the basics of linear algebra in 10th grade, the basics of matrix methods in 11th grade, and the basics of Gaussian Elimination, including GECP, in 12th grade. Gilbert Strang's "Linear Algebra" book would be ideal for teaching advanced high school students.

Nice video ❤❤❤❤❤❤

Nice question and comprehensive explanation 👍👍

Informative video ❤❤

What a beautiful question❤

Do you know any different solutions?😊

😊

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Nice video ❤

I always had problems to this But now with PEMDAS I can remember it easily 🙏🙏

Perfect👌

1098😊

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😂1098

1098

1098

1098

4(4×4)^1/2

4√(4×4)

√ 4 * √ 4 * 4=16 😅

D

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Can we use radical?

Super hard 😮

4x4-4

ID Test

Nice question

-9

What is the 69? Ate something

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Shall we Dance!!

Dance with me ❤

like a lazy ocean ...

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91.1060205

solved it in a blink since I am preparing for Jee advanced exam (toughest engineering entrance exam in INDIA)😀

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Yippee 🎉🎉🎉🎉🎉🎉