I accept this flow behavior and I can successfully calculate every point in a CD Nozzle at given back pressure to stagnation pressur ratio and expansion ratio. But today I talked with an aerospace colleague and he said that in real life, it is not possible to get supersonic flow in a nozzle (and then a normal shock) if the backpressure is a higher than fhe pressure at the throat p*. Imagine, that the nozzle is evacuated and then you let a gas flow in with a given stagnation pressure. The gas reaches p* at the throat, but then the backpressure is higher then p*, so how can the flow get supersonic initially? Yes I do understand that the static pressure significantly increases after a normal shock, but still. So my question is specially about the case where (Pb/P0 | subsonic) > (Pb/ P0) > (p*/P0) I hope my question is understandable.

great introduction. thanks a lot

Why this doesn't work in my excel 😮‍💨

7 years later and this is saving me on my propulsion final. Thanks GOAT

is the converging nozzle exclusively for after burner use or it also varies depending on speed in flight. My theory is that when the jet is flying slow the nozzle would stay wider for lower engine load and fast response and as the jet goes faster, the nozzle gets smaller to produce faster thrust. A bit like a gearbox, where open wide is first gear and choked is 6th gear. Or would it be better to have a fixed nozzle size if not for afterburner? Thanks

It isn't your fault, but this video brought me to tears

Gyot dayum thanks!

Is this playlist meant for undergraduate fluid dynamics?

Superb. Thank you.

great presentation

Where are u plotting what?😂

Good lectures !

Why every airfoil is showing as bad for me?

My teacher never explained the reason behind the knife edge.

It's been 6 years & I am still watching this after reading it for 16 hours without understanding. Thanks Josh

I worked on this for motorcycles but I came across an interesting fact. Peak power is produced before the redline. So when the vehicle is at peak power, the gearing does not allow for that theoretical top speed. But as you approach the redline, as gearing increases to allow for higher top speed, your power drops. So you have to calculate the speed at which both gearing and aerodynamic top speed intersect, that’s your real top speed. For your example, I wonder, at 6400rpm in whatever top gear is, does the gearing allow 269.7mph? If not, you have to go past 6400rpm to reach aerodynamic top speed, but as you go further past 6400rpm, you lose power, and thus you will have a lower top speed.

lol getting to 64th accuracy with dims and then hand drilling

Genius, thank you so much

Great explanation ..... Thank you

How can we get the drag coefficient for two elements?

Very intersting ,this proof is better than other

The speed is perfect for my ADHD.

This was great. I hadn't used JabRef for about a year and forgot most of it. This was a great refresher.

Josh this was fantastic! Thanks so much!

Im literally about to go into school for engineering and was trying to figure out how to do notebooks and notes and this is a crazy discovery while trying to figure out how to write a fictional notebook for a character studying a new magic type and accidentally just probably saved myself years of pain finding this thank you so much

Where I can find a Spherical concave mirror less than $50?

Subbed

THANK YOU FOR EXPLAINING THIS SO THOROUGHLY AND SUCCINCTLY YOU DESCRIBED LITERALLY EXACTLY WHAT I NEEDED TO LEARN

thanks man

sorry if this is a silly question but why is the d not squared for dphi/dydz and all the others?

I got lost after good morning everyone

I saw your video repeatedly, and thank you for this Gold Mine, I have a question when I go to the steps on making that loaded file to be deleted on the Matlab code the comment "% Delete files if they exist" and "delete(saveFlnmAF); " parts, when I uncomment it and click RUN it is saying to error "Warning: File 'Save_Airfoil.txt' not found. > In MATLAB_XFOIL (line 52) Undefined variable 'dataBuffer'. Error in MATLAB_XFOIL (line 55) XB = dataBuffer{1}(:,1); % Boundary point X-coordinate >> What should I do, I watched your video for the 5th time today and I can't see any difference that I am making to get this kind of error, and anyone who can help, Please

Thank you This Video helped me with my University Exam🙂.

I love how this guy just deduces that everybody that is curious enough to watch his videos must be a skilled matematician, capable of easily solving the last equation. He spent 7 minutes explaining how to formulate the damn equation then he just shows the result without even showing the process...

Talking fast is most of the time a sign of insecurity and not helpfull if you want transfer information.

Hii what kind of engineer are you?

Literally the perfect instructional video.

You saved my IB MATH HL IA, thank you so much really clear and straight to the point

Is there any intuitive analogy that Cp and Cv that we can relate this to in real life? So abstract.

Nice and simple explanation for something so complicated.

Thank you so much for sharing valubale information :)

Amazing video. I have a quick question, if you have the time. What is the minimum temperature difference that can be shown in this setup? Can heat rising from a human body be shown like this? Thanks very much.

one of the most harsh topic i have ever seen in engineering.

This is brilliant! I finished college many years ago, but I still use notebooks for notes on books I'm reading so I won't forget. I've made "cheat" sheets for my son, who is dyslexic, on books he has to read for school with characters' names, settings, events, maps, and pictures. Grid notebooks are my favorite.

Hey, do you (or anyone else) still know where i could find a viable source for the equation?

Thanks good video

I like how you get to the point immediately. The inclusion of the diffuser makes sense but is also kinda counterintuitive. The afterburners are there to increase the velocity of the gases but to utilize them optimally we need to slow down the gasses first. I imagine that tuning the diffusers must be quite a challenge. To have a design that results in the maximal net velocity gain.

This explanation really helped me.

Thanks...it's a really nice video..

josh i cannot hear you no one can