9 ай бұрын
9 ай бұрын
9 ай бұрын
9 ай бұрын
10 ай бұрын
Пікірлер
@johnrylroda5631 7 сағат бұрын
What counterclockwise is positive? And clockwise is negative??
@hajaraakouk576 Күн бұрын
Thank youu!
@AhsanTariq-vy6lf 7 күн бұрын
there is a mistake i th ink in the 2nd last line F2y=F2vsin(30)
@PedroHenriquePS00000 10 күн бұрын
BEST VIDEO IVE FOUND
@henriknh_hugo 14 күн бұрын
lo pude entender sin hablar su idioma...gracias!
@zkcnwif 19 күн бұрын
2:40 can you explain it why tangent-direction don't have a force?
@Ной-п2ц 25 күн бұрын
thank you so much
@HaleyJenkins-b7w 28 күн бұрын
why didn't you include the 400N in calculating the moment of point C?
@farzadkargar671 29 күн бұрын
why did we get -T for Fx, wasn't supposed to be positive.????
@alqudude16 Ай бұрын
Hello why did we not consider thr tension of the cable from E to the middle of C ?
@NdumisoKhanyile-dp4lr 2 ай бұрын
I'm learning a lot from your videos mam. thank you very much ❤❤❤
@JasonLords-vw4lt 3 ай бұрын
Thank you very much your channel deserve more views and subscribers ❤❤❤❤
@engomarabdallah6556 3 ай бұрын
please complete it i am engineer and i return study it you are so good as teacher thank you so much you make me understiand it more than before i wish make plAYlist have lecture from one to
@myviews4967 3 ай бұрын
component method is easier
@Denise-i6u 4 ай бұрын
I understand everything from u thank u so much ❤
@Denise-i6u 4 ай бұрын
U re aweome danke schön❤
@HalimawUmibabaw 4 ай бұрын
Thank you.
@naberyoutube2802 5 ай бұрын
Very clear explanation of the uses and formulas. Thank you professor!
@vivialynbingel1235 5 ай бұрын
I just want to ask, how do you come up in 6.50 in FR in Y, thank you
@rickliu2100 4 ай бұрын
For F1: (3/2)j =1.5j and F2: -5(4/5) j= -4j and F3: -4j If you count these up for the FRy component: 1.5 - 4 - 4 = -6.5
@truesonsilo2264 5 ай бұрын
tnx that helped me a lot
@HudanurDilaver 5 ай бұрын
Your teaching is perfect. Thanks for the videos it will help me for my final exam 🤍
@DhakshithaS-r6e 5 ай бұрын
Woww...Thanks a lot!!
@SurprisedBlueMackerel-qe5dy 5 ай бұрын
A student from the HELL of PU lebanese university
@amaraseeri7256 5 ай бұрын
thank you so much
@aytkaa 5 ай бұрын
ليش ماكو ترجمة للعربي 😭😭
@GauthierShabani 5 ай бұрын
why ain't you considering the forces at point D??
@Nick-cz3gl 6 ай бұрын
Good stuff, very helpful 😊
@jariatouhydara5955 6 ай бұрын
Thank you
@alperutkuceylan520 6 ай бұрын
its a bit stupid question but How we found W^NC = 0 ?
@LeenHamdan-u5p 6 ай бұрын
6:23 why did you add the minus ?
@ZerihunYonas 6 ай бұрын
What a great explanation.
@aidanepply-schmidt1647 6 ай бұрын
I think perhaps the tangential reaction at O (Ot) should be in the opposite direction. Solving your equation 1 with alpha = 5.905 yields a negative answer. Wouldn’t that mean it’s in the opposite direction from what was initially assumed? (20)(1.5)(5.905) = 177.15 But 19.05 + (20)(9.81) = 215.25 However, -19.05 + (20)(9.81) = 177.15
@thatguytheethee6194 6 ай бұрын
can anyone explain why we assume the curve is concave down for the moment diagram? Do we just assume we took the steps to find it? Or is it always concave down because its negative "x" no matter the exponent?? 10:21
@shelbyarnold1648 6 ай бұрын
Can someone explain why it is 2/3x multiplied by x then divided by 2 please!!! 4:40
@cmullerk_Mechanical_Eng. 6 ай бұрын
When you have a triangular distributed force, you find an equivalent force that is the area under the curve, bh/2. This equivalent force is located at 2/3 of skinny side of the triangle.
@ayeitzdevo6253 6 ай бұрын
At 4:28 why is K used on WAB to find VB but K is not used on WAB to find alpha B
@IronElephantProductions 7 ай бұрын
Thank you for the explanation
@rauljohnson7450 7 ай бұрын
AWESOME
@codycosy7153 7 ай бұрын
Thank you so much I have mechanics exam tomorrow and this help me understand so much.
@cmullerk_Mechanical_Eng. 7 ай бұрын
Glad it helped!
@mouhamethba9305 7 ай бұрын
Thank you so much, I regret why I did not discover your page earlier, u are really helpful for my upcoming exam
@cmullerk_Mechanical_Eng. 7 ай бұрын
All the best
@divineojugbeli483 8 ай бұрын
Hello, in the distance coordinates, R(a/b) is (-0.3sin(60)i + 0.3cos(60)j) and R(b/a) is -R(a/b). You wrote in the formula R(b/a) but proceeded to write out R(a/b), the same for R(c/b) and R(b/c) as well. I would really appreciate a response if it's an error or my math is not so good. Thank you😊.
@cmullerk_Mechanical_Eng. 7 ай бұрын
The Vector R (b-a) reads vector from b to a, the Vector R(a/b) reads vector b relative to a, and represent the same. The Vector R (a-b) reads vector from a to b, the Vector R(b/a) reads vector a relative to b, and represent the same. The formula for the velocity can be written as: Vb= Va + w x R(b/a) + Vb/a .... the known velocity is at a, and you are calculating the velocity at b, therefore the vector goes from a to b, which is the same as saying b relative to a. if you would like to do the inverse: Va= Vb + w x R(a/b) + Va/b .... the known velocity is at b, and you are calculating the velocity at a, therefore the vector goes from b to a, which is the same as saying a relative to b. I hope this help.
@566ab7 8 күн бұрын
There is no words can describe how is your effort very much helpful Thank you so much , I'm sad cuz I just found this channel 4hrs before the exam😢 @@cmullerk_Mechanical_Eng.
@cuyorodriguez7106 8 ай бұрын
Hola compañeritos de mecatrónica
@leonardobarbosa6947 8 ай бұрын
Thank you. Your explain help me a lot. Thank you very much. Your teaching is incredible
@juancarlossanchezveana1812 8 ай бұрын
Excellent explication. Thanks 😊
@weekdays206 8 ай бұрын
Hi maam! How did you get the answer of Nb?
@weekdays206 8 ай бұрын
Because we have different value
@panghulanandree.3482 8 ай бұрын
i always love your videos. it helps me a lot. hoping you could upload also lecture videos of mechanics of deformable bodies/strength of materuals. thank you so much!
@007devraj 8 ай бұрын
thank you mam!!!❤
@mdgulamsarwar6807 9 ай бұрын
❤
@malekabozaid1536 9 ай бұрын
Nice
@mohammedferas4393 9 ай бұрын
U are a legend
@Songvibez10146 9 ай бұрын
❤