DMD Engineering

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@BadBrother 11 күн бұрын

Great explanation, better than my lecturer in my college. Thanks

@bbhh-ud9zo 21 күн бұрын

Your explanation is concise. Thank You!

@SilentMeek 22 күн бұрын

It's very good I appreciate it but you are writing your A, B, D, & F like a psychopath 😅

@rafeyhasan1189 Ай бұрын

How the hell are you holding that pen!!🫥

@chongochishimba6207 Ай бұрын

😂😂

@ARTIOMIVANCUEVACHEKALIOVA Ай бұрын

Thanks for your video mate

@foreverfugazi245 Ай бұрын

the most easiest explanation I've heard on anything till date, . thanks mate

@golyasa9558 Ай бұрын

thanks a lot

@pagcasmayeth8251 Ай бұрын

What about moving the summing junction across a takeoff point and vice versa? Helpful video by the way.

@dmdengineering Ай бұрын

Glad you found the video helpful! In this kind of block diagram reduction, swapping the places of summing junctions and takeoff points isn’t allowed. If you try to do this, you will find that you actually need to make the block diagram more complicated with additional branches to accommodate it.

@HaoranFeng Ай бұрын

University of KZbin

@idahosprings2224 2 ай бұрын

Thanks for not wasting time

@Baraka_SYP 2 ай бұрын

I was lost when you switched from one exercise to the other without mentioning it’s a new question (asymptotes part).

@IyadeTest Ай бұрын

OMG SAME ! i dont know why he did not finish it

@christophkassir1559 2 ай бұрын

Amazing, thank you!

@AkimboOfficial 2 ай бұрын

These videos were super helpful, thank you!

@probably_drew 3 ай бұрын

Thank you so much, this video made the concept of block diagrams click. Really appreciate it!

@efrenvargasbocanegra8469 3 ай бұрын

Bro is him

@Dhiaa78 3 ай бұрын

❤❤

@nickweddle677 4 ай бұрын

Nice video man. Good job 👍

@cassandrathompson8969 4 ай бұрын

This was so helpful, thank you!

@IcRDlayout 4 ай бұрын

Use base concept :3secs Voc=(40/16)*4=10v Rab=4kohm( I open, V short) Isc=Voc/Rab=10/4=2.5kmA(use Matrix)

@borisj4054 4 ай бұрын

Called super position.

@willthecat3861 5 ай бұрын

The video doesn't mention why a voltage source is short circuited, while a current source is open circuited.

@averygeneralnamecauseicant209 5 ай бұрын

For a voltage source to equal zero, it has to be short circuited. The piece of wire that "short circuits" a voltage source (connect a piece of wire from the positive terminal to the negative terminal of a AA battery) will have the same potential on both ends of the wire. Using Va (positive terminal voltage) - Vb (negative terminal voltage), the potential difference across the wire is 0 V (AA is 1.5 V therefore 1.5 V - 1.5 V). For a current source to equal zero, no current is allowed to flow. The only way to achieve this is to literally open the circuit by opening a switch, or removing a component (resistor, capacitor, inductor, etc.) from the circuit.

@byzorbi 5 ай бұрын

What software do u use to create these tutorials?

@dmdengineering 5 ай бұрын

I write in Microsoft OneNote and capture the video with OBS Studio

@harrisonelliott8305 5 ай бұрын

Great vid!

@neonnnXD 6 ай бұрын

my god bro, become a teacher please

@panelty8379 6 ай бұрын

nice, how do i apply this in irl now?

@blessingshenjere484 6 ай бұрын

is this the evans method

@vojastevanovic6634 7 ай бұрын

How about when i have three or more equations ?

@omaraliraqi3056 7 ай бұрын

I am grateful to you for this good explanation

@LennoxOjore 7 ай бұрын

Thanks a lot. Clear and precise😄😄

@emilewepener3716 7 ай бұрын

Thank you for this video !

@rileighsevigny468 8 ай бұрын

this is super helpful, thank you!

@019__4 9 ай бұрын

Thank you so mush🙏

@karycolin9046 9 ай бұрын

Thanks a lot, regards from MX❤

@jebb360 10 ай бұрын

Bruh why do i finally find this video AFTER I have done this exact question for my control systems analysis assignment. Nice to know it’s right though. I’ve done the laplace and just gotta do state space stuff today

@TheWrongButton Жыл бұрын

Very helpful and concise summary, thank you.

@vassilisbakalas3423 Жыл бұрын

godsent

@K0ldsoul Жыл бұрын

Does DMD refer to dynamic mode decomposition by any chance? nice video btw.

@dmdengineering Жыл бұрын

Nope. Just my initials. Thanks!

@MusaYmc Жыл бұрын

+rep

@ammy1562 Жыл бұрын

THANK YOU SO MUCH! Clear and helpful. God bless.

@GoatMen Жыл бұрын

Finally a video with clear English.

@sicco9326 Жыл бұрын

Great Video!!

@feli734 Жыл бұрын

Thank you so much. That helped a lot

@happysquirrelwhats-tube8768 Жыл бұрын

Thank you, true life saver

@shivamtrivedi5639 Жыл бұрын

Really helpful content 🙌

@reillyjensen2641 Жыл бұрын

Use masons gain formula! It always works

@michaelgershon9077 Жыл бұрын

Can someone one take the junction downstream and get the same answer?...

@dmdengineering Жыл бұрын

Yes! There are many ways to solve this kind of problem, and I just showed one

@marcodiprima4989 Жыл бұрын

I didn't moving g2 after g4 and not before g3. I got a different answer

@michaelgershon9077 Жыл бұрын

I don't get the same answer when I move the junction between G3 and G4 in front of G4 , Why?

@dmdengineering Жыл бұрын

I just went through the problem again starting with moving the right-most summing junction to the right of G4 putting a G4 into the upper right branch. I got the same answer as in the video. The steps I followed were as follows: • move right most summing junction to right of G4 and make upper right branch contain G4 • multiply original G4 with G3 since they are now in series • move takeoff point to right of G2 upstream similar to how I started in the video which makes the upper right branch G2G4 • combine G1 and original G2 in parallel to get G1-G2 • move summing junction to the left of G3G4 downstream of G3G4 making the bottom branch G3G4G5 • multiply (G1-G2) with G3G4 since they are in series • combine left side of diagram in parallel to get (G2G4 + G1G3G4 - G2G3G4) • use feedback rule on right side of diagram (before G6) to get 1/(1-G3G4G5) • multiply together remaining three blocks in parallel to get final transfer function I hope this helps. There are many different ways you can do this kind of problem, but they should all get you to the same answer

@SaraStigmar Жыл бұрын

I learned a lot! The pace is not stressed. You turn over every stone and do it very methodically. Thank you very much for the video! Helpful! :)

@marriotnyeleti3564 Жыл бұрын

Well explained sir

@Ali-cc3zz Жыл бұрын

Well done pro

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