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@ChipoMuloongo-v8h8 күн бұрын
Thanks I have learnt a lot
@aayushbhandari83778 күн бұрын
here are a few questions from my side: 1. 5:37 is the normal force on block A by block B F1-F2, and the normal force on block B by block A F2-F1 ? since the directions are opposite and equal? 2. what happens to the normal force between the blocks when the blocks accelerate, lets say to the right, with same magnitude ? i am confused on whether there will exist a normal force between the two blocks when in motion. 3. in general, is the magnitude of the normal force (horizontal) between two bodies in contact the difference between the forces acting on them. 4. you said that the normal force on a body is always normal to the surface. so we can take the normal force by a book on a table and the force by the table on the book as equal and opposite, right ? so can the same logic also be applied in the case of the two bodies in contact ? please do answer. please love from nepal <3
@physicslab428 күн бұрын
Thanks for the questions! 1. In this scenario, we're not told whether the blocks are accelerating or not. For each block, the net horizontal force is equal to its own mass times its acceleration (Newton's 2nd law, Fnet=ma). If the blocks are not accelerating then F1=F2, Fn(B on A)=F1, and Fn(A on B)=F2. And it's always true that Fn(B on A)=Fn(A on B) because they're a pair of equal and opposite forces. 2. If F1 or F2 was greater than the other then the blocks will accelerate together at the same rate, and the relationship between the horizontal forces will depend on masses of block A and block B. There will still be a normal force between the blocks when accelerating, and they will always be equal to each other. However, if we removed F1 and F2 then there is nothing pushing the blocks into each other and there would not be a normal force between the blocks. There would be a normal force if only F1 or F2 was still acting on the blocks, causing one block to accelerate the other block. 3. In order to figure out how the normal force between two bodies is related to the other forces, you need to write out Newton's 2nd law (Fnet=ma) in the horizontal direction. The relationship between the forces will depend on the acceleration and the masses. 4. Yes a normal force is always normal (perpendicular) to the contact surface between the two objects. So the normal force by a book on a table is equal in magnitude and opposite in direction to the normal force by the table on the book. This is true for any two bodies that are in contact. I hope this helps!
@aayushbhandari83778 күн бұрын
@@physicslab42 yes, it helped. thanks.
@physicslab428 күн бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any questions or feedback about this video. And if you know someone else who's learning physics, share this video with them!
@samusankhulani542311 күн бұрын
You are the best
@mindysmith-langel630714 күн бұрын
Thank you 🙏 ❤
@tofunmio18 күн бұрын
Very good video, i watched about 7 different videos about tangential velocity and was still confused but watched the first few seconds and understood immediately
@physicslab4217 күн бұрын
That’s awesome to hear thanks, I’m glad it helped!
@1984Panda23 күн бұрын
Thanks
@raniahabbas8526 күн бұрын
How do you know whether to measure from the horizontal or vertical when we want to find the x and y component. Like how do we know where to put the theta? If it’s not given in the question and we don’t know theta.
@physicslab4225 күн бұрын
Good question! If you don't know any of the angles in the right triangle (and you can't find them from other angles that are given) then you wouldn't be able to find the x and y components. The question would have to give you an angle and tell you which angle it is.
@heyes3613Ай бұрын
I don't take any physics lessons, I just started learning physics to understand life better and you explained it in a way that can easily be taught to someone who has nothing to do with physics, thank you for the video
@physicslab42Ай бұрын
I’m glad to hear the video helped, thank you for your comment!
@soniaperla1893Ай бұрын
For the problem at 6:40 why was the unit kg if the exponent was not that if kilo which is 3 ?
@physicslab42Ай бұрын
Good question! You can actually combine scientific notation and prefixes. So if something is 1 x 10^24 kg then it would be equal to 1 x 10^27 g (the exponent would increase by 3 if you convert from kg to g).
@sincity147Ай бұрын
Fruit 🍎 of thought - If both forces manifest at instantaneous time it means that both manifest faster than speed of light? Can’t be cause then objects could not touch each other? Or their infinitesimals first contact turn in infinitesimal black holes 🕳️?
@physicslab42Ай бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any feedback about this video or requests for new videos. And if you know someone else who's learning physics, share this video with them!
@JeffMckee-d6o2 ай бұрын
Never put down Billy Carson. Pussy boy.
@chardrichie2 ай бұрын
This is so helpful and clear. Should have thousands of likes and comments💌
@isaiahkruz85442 ай бұрын
I think it would have been better to choose the sign of parameters according to the gravitational force. It is so understandable but thanks for the good work ❤
@physicslab422 ай бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any feedback about this video or requests for new videos. And if you know someone else who's learning physics, share this video with them!
@theengineerr2 ай бұрын
Very well explained thanks
@ElizabethBwalia2 ай бұрын
Your videos help me a lot please make the Newton third law of motion
@physicslab422 ай бұрын
Thanks I’m glad they help! Working on Newton’s 3rd law next.
@physicslab422 ай бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any feedback about this video or requests for new videos. And if you know someone else who's learning physics, share this video with them!
@swappy-k6l2 ай бұрын
you are a saviour! thank you
@physicslab423 ай бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any feedback about this video or requests for new videos. And if you know someone else who's learning physics, share this video with them!
@sarasulyman62073 ай бұрын
TYSM THIS HELPED A LOT KEEP IT UP 🙏👍🏾
@enderman10533 ай бұрын
What a logical and efficient system, I hope that a country that loves to feel especial does not use objects that vary in size or body parts to define distances or mass.
@MOMWYD73 ай бұрын
Thank you so much! this helped me a lot💗
@Mari-gq6wu3 ай бұрын
by far best one ive watched
@physicslab423 ай бұрын
Thanks!
@Eliasasgedom773 ай бұрын
0.000 000 000 135 T into M please
@CharicelPanis3 ай бұрын
I still don't understand why we always use (-g) whether the object is going up or down
@physicslab423 ай бұрын
Yeah that's a common point of confusion. The acceleration of g (9.8 m/s²) is caused by gravity, which always acts downwards no matter what's happening, gravity and the acceleration never act upwards. So even if an object is moving up (it's velocity is up) the acceleration is still down. That has the effect of slowing down the speed of an object moving up, and speeding up an object if it's moving down. Does that help or still confused?
@SunShine-2213 ай бұрын
Thank u I'm a senior this my last year and u helped me understand a lot 💕💕💕💕💕
@dellayz3 ай бұрын
Best Physics Teacher!!
@borky17603 ай бұрын
More videos please
@physicslab423 ай бұрын
More videos coming soon!
@physicslab423 ай бұрын
⬇ Check out the Physics Lab website for more videos, study guides, practice problems and more! physicslab.app/p/physics-1? Leave a comment if you have any feedback about this video or requests for new videos. And if you know someone else who's learning physics, share this video with them!
@CabdinaafacCabdi-s4q3 ай бұрын
Thank you thank you thank you🎉❤❤❤❤❤
@abrupsuper9723 ай бұрын
awesome teacher i have ever encountered
@be_a_biologist-20233 ай бұрын
Thank you
@johnsillah70463 ай бұрын
Thank you
@jessicao60564 ай бұрын
Awesome pace and very clear explanation, thank you!!!
@asthetic_bae934 ай бұрын
Please upload vectors
@physicslab424 ай бұрын
I have a few videos on vectors if you want to check them out! Vectors and Components: kzbin.info/www/bejne/b2elf3mJfq6Sj68 Displacement Vectors: kzbin.info/www/bejne/jZK2qqeoarqno6csi=SS2uIUUm3EUIZj7S Velocity Vectors: kzbin.info/www/bejne/rYO9ZWuCntWXbcUsi=RLixmNJufR_ubPrU 2D Motion and Vectors - Practice Problems: kzbin.info/www/bejne/inybc2yifaimbZIsi=EuQ0PgdUsHSFfsqv
@JoLucy14 ай бұрын
we have make all the number to have only one number in the left?
@physicslab424 ай бұрын
Yup if you are writing a number in scientific notation you would move the decimal until there is one digit to the left of it. The number of places you moved the decimal is the exponent above the 10 (the exponent is positive if you moved the decimal left and negative if you moved it right).
@ibtisaammohamed-p8z4 ай бұрын
you r amazing nd i lke you thanks a apreciate that
@SadhanaKalakheti4 ай бұрын
i love you thanks for these videos. you're awesome, i get it better than anything else
@physicslab424 ай бұрын
Awesome I’m glad they’re helping!
@kalumff4 ай бұрын
Greatly appreciated .. 👏
@Zonaaaaa1014 ай бұрын
This formal is so good Im gonna tell my teacher to recommend your videos for her future classes
@Zonaaaaa1014 ай бұрын
Format**
@physicslab424 ай бұрын
Thank you so much! I have more videos and content for teachers in the Physics 1 course if they're interested: physicslab.app/p/physics-1