Ok will try to cover soon

Thank you sir

Ok 2019 Jee Mains pehle karta hun 👍

Thank you sir

Yes, thanks for such a good suggestion, main vichar karta hun 👍🙂

Sure, noted 👍

Yes ok, keep learning 👍

@@basics1729 Thankyou sir for this nice lecture..

@nnobodyn Welcome 🙂👍

Tumhe sirf question ka pdf chahiye ya solution ke saath question ka?

@@basics1729 solutions ke sath, revision aur new methods se karne mein help milti hai. Btw please baaki adv solving sessions ke bhi pdf provide kar diyo.

@anshpatil8232 Actually, maine aise solutions ka koi pdf to filhal nai banaya, video main ppt pe solve karta hun in somewhat random manner. I will try to make pdf in a formal way 🙂👍.

Contact me on Telegram - @ravisinghisking41

We can say for JEE Advanced

Thanks 🙏

Next lecture on Monday. What is your suggestion regarding thumbnail? Thanks

@@basics1729 Bhaiya you can take some thumbnails as refrence such as munil sir ( unka bhi me bhot phele se subscriber hun bhot neeche se upar uthe h wo bhi) Thumbnails bhot attractive h unke like that matter krta h thoda bhot to I don't know I guess KZbin algorithm ka thumbnail ke sath kuch to h relation

@yatharth5166 Thanks for your suggestions, check karta hun main Munil Sir ka

Thanks Parth 🙂

Circular motion pehle ka chapter hai and thats why it is expected ke tumhe aata hoga Rotation main aane se pehle. Isliye kar loge to jyada behtar hoga.

@@basics1729 uska one shot hai kya bhiaya? kyuki dusre one shots 4-5 hour ke h ap thode proper time ke one shot bante ho theory ke which i like about your channel please dont stop that series till jee 2025

@yatharth5166 Yes okay I will not stop, but circular motion ka one shot nai hai, par palylist hai jisme 2-3 lectures main theory covered hai. You can watch that. Although again I am gonna cover that in one shot in the near future.

Ok I will do that in the coming lectures for sure 👍

Okay Yatharth, I am gonna start a basic series about problem solving on Kinematics but only after the thermal part as I have already promised this in another comment. Meanwhile you can refer my previous lectures on Kinematics ( kzbin.info/aero/PLHMNREd8J-BpPBRffxuIxtHGRIZ-zyPkc&si=xIjT0SO56qwoJ8Eb) which I have already covered to some extent.

@@basics1729 Sure sir no problem & Thank you very much you help the students as per their needs/ their weak topics etc....I wish & Hope that soon your channel will grow

@yatharth5166 Thank you very much for your best wishes 🙂👍

Let me check and analyse, meanwhile you can follow PW lectures although I am not completely sure about the content.

Ok, next theory uski he karunga after questions of Gravitation 👍

Welcome 🙂, keep learning and shining 👍

Now don't think about that. Although that paragraph question was good. How was the overall exam?

@@basics1729 Exam was mid, but i messed up big time, so not expecting good rank

Maybe more number of students messed it up, we dont know. Now dont overthink about the exam. Hope for the best 👍🙂

@@basics1729 doesn't look like too many messed, I m getting least in my class

Okay, but still I am gonna say that wait for the final results. One thing very philosophical to note here is that 'No one gets anything prematurely before the fated time and no more than one's fair share as destined'.

Thanks 🙂👍

Now I suppose, you know the truth 🙂👍

Here you need to consider the kinetic energy also. In case of AP, the initial velocity was 0, but here at point P, velocity is there and thats why I used Energy Conservation. I hope you got my point.

Waoo 😀, thanks. All the very best to you for the exams that you are preparing for 👍.

Yes, ho sakta hai, possible 👍

Yes, its very obvious. Good 👍🙂

Thanks 👍, keep learning and growing 🙂

Suppose you are having a similar but not exact scenario as in the question above in which a piston-cylinder arrangement is there and the gas within the cylinder is expanding but very very slowly thus undergoing a quasi-static process. But at the same time it is also transferring heat to the surrounding because of finite temperature difference with the surroundings. This is the case (although very bookish) of internally reversible but externally irreversible process. If the temperature difference with the surroundings are to be infinitesimally small too, then the process would have been externally reversible also. This is the complete definition of a reversible process having both internal and external reversibility involved.

@@basics1729 oh got it thanks

Yes, but here you can say that the internal energy lost by the gas is helping piston to do the work against gravity. You cannot apply Energy Conservation (1st Law of Thermodynamics) directly to the gas itself.

Thanks 👍

You're Welcome 👍

I am answering as per your points - 1. In this particular case, we are actually taking work done by gases in the 1st law but suppose a system having no gas within it and some other fluid or maybe some solid. That is why its better to write work done by the system instead of work done by the gas. 2. Yes, here the system consists of both the springs and the gas and that piston too. But the phenomenon that is triggering the springs to compress or expand is basically heat transferred to the gas which is getting expanded and due to which springs are doing work. So, either you take the work done by the gas or -ve of work done by the spring but not both as you will get zero by adding both because both are one and the same thing (action-reaction) kind of thing. I hope you get my point. You can even see other comments below based on the same doubt.

You're welcome 👍

Actually system is doing work when Q heat is given to it from the right side and as a result the potential energy is getting stored in the spring.

@@basics1729 can we say that total work was zero.. Work by gases + wspring = 0 ...?

Yes ofcourse, this is because when Q amount of heat is transferred to the gas then as a result of pressure on the piston, spring will get expanded on the right hand side of the partition and compressed on the left hand side and so gas is doing work upon the system. But springs in turn will try to regain its original length and thats why the force acts in the opposite direction to their displacements. That is why the work done by the gas and springs are opposite and getting cancelled when you add them up.

See, because gas is doing work upon the system thats why springs are getting disturbed but spring will also try to regain its natural length and you are considering this spring force only while getting work done by the springs and that is why you are getting zero as work done. Don't consider like this, you have to be very clear about the system consideration otherwise you are gonna commit mistake like this by considering the same action-reaction kind of work. I hope you get it 👍