i feel smart for understanding this

fail its pi/2 on first one(half circle LOL), but it not matter bcoz we just make semi circles 2x smaller it wont effect pi its allways 3.14.... xD

NOOOO!! RADIAN IS 38/6 CIRCLE!!!!!!!

it's 38/6

Came here from acerola who used it to make a particle system

A Weiner process. Can’t calculate f(x+h)-f(x) if you don’t know f(x+h)

I think fractals can't be defrentiable

2π?

≈0.18

..superb

Super..

I guess you could also look at the circles as functions and solve for the integrals. First you put the x-axis at the bottom tangent point. Then you find the integral of the top circle between the x values of the other two tangent points. Then you subtract the integral of the left circle from the x value of the left tangent point to the bottom point and same thing for the right circle from the bottom point to the right point. The remaining integral will be the area between the three circles.

Looks "relax tangle" game like

Hence, 2PI × R

Sqrt(x)

If you draw two semicircle with equal diameters in a semicircle, the length of the curve won't be half the bigger diameter. That's just insanity.

why is this famous? i have created numerous random shapes that look better than this, does this have a use?

So awesome

Really nice. May I ask what software do you use for these animations?

Nah I just know that pie is closer to3 therefore its pie first

Well, 1/2 of the circumference doesn’t equal the radius. There is a difference between the distance of one point of an arc to another, is not the same as the total length of the arc itself. And that is why this conundrum is not correct👍

72 hours after 52515151 minute +♾️

kzbin.info/www/bejne/hZ7TdmSArKaqb5Y - yet another example of non-differentiable function where left limit not equal right limit in the x0 point

What was the middle bit?

The triangle is 1/4 of the square. It is made of 2 similar triangles and a trapezium. After overlapping, I found out that the trapezium = 3 small triangles, so the big triangle = 5 small triangles. More overlapping done and I found out that the middle square = 4 small triangles. The total figure is 20 small triangles. Since the area of the squre is 1, the small triangle is 1/20 so the middle squar is 1/5

What about √x ?

Lim n > inf π/n * n = π

the cemi-circke cannot become flat to the diameter

Nope. Functions 1, 3 - are differentiable everywhere they are defined.

I prefer the method of making a big square out of four identical triangles. It's much simpler visually than this moving proof.

Fractals?

😶‍🌫️

Actually the first one is almost a venn diagram and it could become one if you put it on a spherical surface so you could let AC and BD overlap. Although you would get 4 regions where none of them overlap.

Do not need to go so complex Just draw graph of y=x to power 1/x,it is also called gaussian curve,its peak reaches as x=e,so since pi>e so e to power 1/e >pi to power 1/pi then after raising power e×pi both sides,we will get e to power pi> pi to power e.🎉

Once we show that the two triangles are similar we can just set the proportions and we’re done, don’t see the value in the extra steps

I'm subscribing you for this clip. ❤

xsin(1/x), continuous but not differentiable!

abs(x) can be differentiated technically

Area(🩲) = \sqrt{3} - \frac{\pi}{2}

If the domain is finite, obviously it’ll be undifferentiable outside of that domain!

f(x)=sin(1/x) - not differentiable at 0 and Weierstrass function which is not differentiable wherever

hmm an oscillating discontinuity as in sin(1/x)?

I love your work, keep going dude

The way each width of the overlap is the same as well

Uh... what is differentiability? 😅

f(x))= sqrt(abs(x) - a) Where a is a positive value

I like the Weierstrass function, which is continuous everywhere and differentiable nowhere

A function can fail to be differentiable if it oscillates too much or the set is not dense

well the formuula i use is not normal if a 1x1 i will 1^3 and if 2x2 i will 1^3+2^3 if 3 i will 1^3+2^3+3^3 this is an easy method thank me later

As a math nerd, I instantly realized it was 2 pi as radius times two =diameter and diameter*pi=perimeter