Nice work sir

Sir your videos are helping lot sir thank you so much😊

Thank you Sir ❤

Final ans is wrong

Sir plz do Isoperimetric problems

Thank you sir... Great explanation ❤

Thank you so much sir 😊

for bsc

Very nice explanation sir.. thank you so much ☺️

Thank you sir 🙏🙏🙏🙏

👍 sir nice

Super explanation sir U teach very best more than my teacher 👏👏

We are belagavi students sir

Thank you sir❤❤❤

Do for square of it

Please talking in kannada 😢😢😢😢

Thanks sir that was so helpful to me

Thank you so much ❤

🎉👌👌👍👍🙏

Tnx sir 😊❤

I have a question

Very nice sir

Sir Why dont u show the integration part its too confusing, otherwise ur explanation is superb.

Did a mistake... but you cleared my mistake now ...thanks sir❤

Thankyou so much sir.

Sir explanation theek kr rhe ho pr ye toh dhyn rkhoo kii x² hai toh wahi lo bdme x² ko x³ bana diya do baar ki ye mistake🙂💔

Nice

sir - 2e^t.e^-t how it become - 2 .What value did you apply for that

Thank you 😊

Thankyou sir ♥️

Nice sir❤

Thank you sir 🙏

Tq sir really helpful video

Great👏👍

How will come f4 ans, sir

Thank you so much sir It was crisp and I understood this topic within no time 😊😊😊😊😊😊

Sir can we take f(x) as y even if it is given as f(x) in question

But sir evaluating the sin cos term we can get the answer without differentiation

You do wrong sir in ou/oy in first step

Why you write u(x+h,y)=u i+1,j instead of u(x+h,y)=u i+h,y

2.0043-4.25-6.6825= -8.9282✅ (Not= -8.9284)❌

Sir, in inverse fourier sine transform, question given " find f(x) if fourier sine transform is e^(-a lamda)/lamda " ,if i take Fs(lamda)= int 0 to infinity f(x)sinlamda x dx = e^(-alamda)/lamda and then multiply sqrt (2/pi) both sides my answer will be in 2/pi is it right ??? As in some book it is given as sqrt 2/pi (without multiplying sqrt 2/pi) and others in only 2/pi.which is right?? Or i can use both??☝️☝️. Please sir reply .🙏🙏🙏🙏🙏

Good explanation sir I understand everything sir

Thank you

Cz/(z-3) ^2 hoga na?

Sir explain in kannada also

Thank u so much sir

Square root can be written as value raised to 1/2 then sir how did you take 1 /2 as normal number and not power??

Thank you sir 🙏

thank you sir