If oxygen can gain and lose electrons,then why does it need to share them?? Is it because sharing them would make them more stable?? But gaining and losing would also make them stable so why sharing??
@learn_trek29 минут бұрын
Let's assume if two oxygen atoms try to form a O₂ molecule by gaining and losing electrons instead of sharing electrons, For that the 1st oxygen atom have to gain two electrons to become O²⁻ and the 2nd oxygen atom would have to lose electrons to become O²⁺. NOW, 1st atom of oxygen can easily gain 2 electrons to form O²⁻, because oxygen atom has high electronegativity, meaning it strongly attracts electrons. But the problem arises with the 2nd atom of oxygen which has to form O²⁺ by losing 2 electrons. because every oxygen atom strongly prefer to gain electrons, not to lose them, because they have high electronegativity. Removing even one electron from oxygen atom requires a significant amount of energy (ionization energy), and removing a second electron is even harder. So losing electrons to form O²⁺ is highly unfavorable. AS a result both 1st and 2nd oxygen atom will have a fight because both oxygen atoms wants to gain electrons, not to lose them. Instead of fighting over electrons, they share their electrons, forming a covalent bond. This sharing allows both oxygen atoms to complete their outer shells and achieve stability without creating charged ions." Nature prefers arrangements that require the least energy and provide the most stability. For oxygen, forming a double covalent bond (O=O) is the most energy-efficient way to achieve a stable molecule. covalent bonding in O₂ requires much less energy to form than an ionic bond(transfer of electrons) because there’s no need to completely transfer electrons, which would demand high ionization and electron affinity energies.
@UCHIHAITACHI-yc8ob5 күн бұрын
Super
@learn_trek28 минут бұрын
thanks
@zaiira77259 күн бұрын
Thankuu so much
@learn_trek8 күн бұрын
welcome
@AnshuSangwan-dr8iu3 ай бұрын
Good bhi carry on🎉
@AnshuSangwan-dr8iu3 ай бұрын
Good bhi carry on🎉
@learn_trek8 күн бұрын
thankyou 🙂
@AnshuSangwan-dr8iu3 ай бұрын
Good bhi carry on🎉
@AnshuSangwan-dr8iu3 ай бұрын
Good bhi carry on🎉
@AnshuSangwan-dr8iu3 ай бұрын
Good bhi carry on
@crying7048 ай бұрын
i have my science exam tomorrow and i am wondering why i never came across this wonderful video before, i had this doubt for like the whole year 🤡. Tysm 💗
@learn_trek8 ай бұрын
thankyou so much for your kind words 🙂 and best wishes for your exams and future
@crying7048 ай бұрын
@@learn_trek To you too for ur KZbin channel!! Keep going, you're doing a wonderful job ❤️
@learn_trek8 ай бұрын
@@crying704 welcome and thankyou again😇
@tabletopa45489 ай бұрын
Question: why doesn’t this happen to an element for example Germanium, it also has four valence electrons but it forms a cation instead of being neutral
@learn_trek8 күн бұрын
Germanium, which also has four electrons in its outer shell, acts differently because it's a much bigger atom than carbon. Its outer electrons are further from the nucleus, which means they aren’t held as tightly to the center as carbon’s, so it’s a bit easier for Germanium to lose some electrons. Because of this, Germanium sometimes loses two electrons to form a positive charge, which makes it more stable in certain compounds.
@ashnilkumar253010 ай бұрын
Awesome bro ...yesterday is my presentation ...on carbon and its conbound...and after watching your video ...i feel really free ...just like carbon is found on the free state ...diamond,graphite and coal...😅but really bro its too simplest and amazing form that you had studied... Great work👍👍
@learn_trek10 ай бұрын
thankyou so much for your kind words 😇......I am glad that you liked my work
@divydwivedi544910 ай бұрын
Sir my question is that how do we know that a carbon atom is going to form a single bond or double or triple bond,it means that in which case a carbon atom would form which type of bond.
@learn_trek10 ай бұрын
The type of bond(single or double or triple) that will typically form will depend on the conditions such as temperature, pressure, and presence of catalysts. At relatively low temperatures and in the absence of a catalyst, the most likely bond to form first would be single, as it requires the least amount of energy to form and is the most stable bond under those conditions. However, if you increase the temperature or introduce certain catalysts, the formation of other bonds such as double and triple becomes more favorable due to the increased energy available for breaking and forming bonds. In short, the formation of more complex bond (like double bond and triple bond) compared to single bond typically requires higher energy input or specific conditions due to the need to break and form multiple bonds, the thermodynamics of the reactions involved, the multi-step reaction pathways, and the influence of factors such as temperature, pressure, and catalysts.
@divydwivedi544910 ай бұрын
@@learn_trek Thank you sir
@learn_trek10 ай бұрын
@@divydwivedi5449 welcome .......and feel free to ask any questions or queries.
@banitachauhan205211 ай бұрын
My question is that how the electronegativty of C4+ will be very high
@learn_trek11 ай бұрын
electronegativity means the power of attracting electrons .........C4+ cation has only 2 negatively charged electrons left but it still has 6 positively charged protons ......so the net charge(of C4+ cation) = 6 positive charges(of 6 protons) ---- 2 negative charges(of 2 electrons) = +4 positive charges .......................this +4 positive charges on C4+ cation will attract negatively charges electrons very strongly ............thus C4+ cation has high electronegativity (as strong tendency to attract electrons = high electronegativity)
@tsmenxkrish62310 ай бұрын
Ok I came to know that there will be increased attraction between the remaining electrons and the 6 protons of nucleus but my doubt is Will the protons present in the nucleus will attract the negative charged electron in the nucleus (means that will the electrons come in the nucleus area because of the strong attraction)?@@learn_trek
@tsmenxkrish62310 ай бұрын
@@learn_trekpls reply it will mean a lot as a student
@learn_trek10 ай бұрын
@@tsmenxkrish623 Good question..........electrons don't come in the nucleus area because electrons are continuously revolving around the nucleus at very high speed......the attraction of 6 protons is still not high enough to attract the 2 revolving electrons to come in the nucleus area .......................... Earth's gravitational force also attract moon & satellites in the space , but moon & satellites dont fall on the earth because both of them are continuously revolving around earth and earth's gravity in space is not strong enough to attract moon & satellites to come near earth (or fall on earth)
@tsmenxkrish62310 ай бұрын
@@learn_trek thankyou for response sir❤️.......it means a lot❤️
@Kevin-p2l5b11 ай бұрын
Okay.
@yashrajshah7766 Жыл бұрын
Very clear explanation without any nonsense 👍
@learn_trek Жыл бұрын
thankyou for your honest feedback ....it matters a lot for me
@mohdrehan7565 Жыл бұрын
Great explanation
@learn_trek Жыл бұрын
thankyou so much for your kind words
@PranjalRai-tu9ud Жыл бұрын
But you should also explain it in hindi then millions of viewers you get
@learn_trek Жыл бұрын
thankyou so much for your feedback , i will now start making videos in hindi
@Kevin-p2l5b Жыл бұрын
Awesome.
@learn_trek Жыл бұрын
Glad you think so! best wishes for your exams
@Arpita-7 Жыл бұрын
Useful for class 10😊
@learn_trek Жыл бұрын
Glad to hear that ..........thanks
@rahulstar3688 Жыл бұрын
Hindi me samjhaya
@learn_trek Жыл бұрын
ji .....jaldi se jaldi hindi mai bhi videos aayengi
@srijanraj9771 Жыл бұрын
Nice explanation in short videos... Appreciate your work
@learn_trek Жыл бұрын
thanks for your kind words .....it means a lot for me
@ashff8741 Жыл бұрын
u just clear my doubts! thanks for the video! keep up the work!
@learn_trek Жыл бұрын
thankyou so much .....it means a lot for me ❤
@chandraprakashbhatt1274 Жыл бұрын
Very clear explanation 🙏
@learn_trek Жыл бұрын
Glad you think so!
@hypeboy306 Жыл бұрын
it's very helpful to me
@learn_trek Жыл бұрын
Glad to hear that
@42356ikygjjjjj Жыл бұрын
Viewers may also visit 'Learner's Console ' for this chapter too 🙏
@Rkgamer007Coc Жыл бұрын
1:14:35 A) 4Na is oxidised B) CuO is reduced and H2 is oxidised
@idk51. Жыл бұрын
Thank you bro it help me alot ❤❤
@learn_trek Жыл бұрын
glad to hear 🙂
@seeker_quest Жыл бұрын
Very interesting thank uh
@learn_trek Жыл бұрын
thanks bhai
@recruitmentinfo3772 Жыл бұрын
Very helpful video sir😊
@learn_trek Жыл бұрын
thankyou bhai
@himanshubankoti3122 Жыл бұрын
Good❤
@learn_trek Жыл бұрын
thanks bhai
@simondobbs4480 Жыл бұрын
Your problem is that C4- anionic carbide ions do exist in, say magnesium carbide, Mg2C.
@learn_trek Жыл бұрын
you are absolutely right but keep in mind that ,this explanation video is made according to class 10 students ...The example you have given is beyond the scope of class 10 students, which they will study later in higher classes