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@harivarsha_ot7 Күн бұрын
that was a nice whole revision of transformers problems sir... thanks a lot
@meassavuth4649 10 күн бұрын
Thanks for your video ❤
@PurityMundia-h3t 14 күн бұрын
is it working on standstill or running condition?
@Mouninewchannel 22 күн бұрын
With neat explanation sir
@Mouninewchannel 22 күн бұрын
Thank you so much sir
@vishnusky 23 күн бұрын
In equation V is said to be rms. While doing problems. Why rms is not taken for V. 8:07
@bookotopia Ай бұрын
tysm
@CMBafana Ай бұрын
Where can i get the slides for the videos
@ZelalemAshetu-h6e Ай бұрын
Lagging angle is positive.
@ishitarath5186 Ай бұрын
Sir, can i use this video for gate preparation?
@Mouninewchannel Ай бұрын
Super sir thank you sir
@Mouninewchannel Ай бұрын
Super sir thank u so much sir
@Webduniatelugu-mr3di Ай бұрын
Sir,the alternator field rheostat position at maximum or minimum
@bogummyluvr 2 ай бұрын
autotransformer used to slowly vary the voltage so that in sc test the current is not more than rated curr.
@bogummyluvr 2 ай бұрын
rated curr=8.6amps
@bogummyluvr 2 ай бұрын
the transformer is of core type which is represented by two lines between the two coils(pri and sec)
@EngineeringDevotion 2 ай бұрын
calculate from kVA rating and voltage ratios
@bogummyluvr 2 ай бұрын
in sc test, the low voltage side is open circuited and all observations taken from h.v. side
@bogummyluvr 2 ай бұрын
unity power factor wattmeter is used
@bogummyluvr 2 ай бұрын
in oc test, the high voltage side is kept open and all the parameters are measured from the low voltage side.
@bogummyluvr 2 ай бұрын
low power factor wattmeter is used
@bogummyluvr 2 ай бұрын
o.c.t. used to find the shunt parameters and s.c.t. used to find series parameters.
@EngineeringDevotion 2 ай бұрын
shunt parameters give iron loss and series parameters give copper and leakage loss information.
@aadityachandak9296 2 ай бұрын
in Q1 ,sir aren't Zm and (Z2'+ZL') in parallel? how are you directly calculating the impedence by simply adding them?
@EngineeringDevotion 2 ай бұрын
Yes, you are correct they are in parallel, and the same has been considered. Addition is only intermediate step, for the ease of calculation. Zeq = (Z1*Z2)/(Z1+Z2), the denominator is calculated separately.
@Cadetmdrakib 3 ай бұрын
Sir I am btech 1st year student doing Btech in Marine engineering . In my course basic electronics include . I have watched and written notes till this lecture. Sir i have doubt when my professor teaches us mostly topic he didn't cover but chapter will end very soon .sir you each and every topic very briefly. sir this is relatable and beneficial for me ??
@EngineeringDevotion 2 ай бұрын
Obviously relatable and beneficial. All the very best !!
@CharanSatyaSaiHarsha 3 ай бұрын
sir, please tell the classes of electrical devices also sir
@EngineeringDevotion 2 ай бұрын
will cover here.
@BankoleSodiq 3 ай бұрын
Why did you use 48.8 for the value of Go in the last question instead of 21.2
@EngineeringDevotion 3 ай бұрын
Observe the formula carefully. It is just the conversion of natural logarithm value to a base-10 logarithm, you have to multiply with 2.303. So, 21.2*2.303 = 48.8
@BankoleSodiq 3 ай бұрын
Why did you use 48.8 for the value of Go in the last question instead of 21.2
@Jitan-ih5zb 3 ай бұрын
From which book sir you taken it
@EngineeringDevotion 3 ай бұрын
Please watch Lecture-1 of the playlist to know the different books from where the contents have been taken.
@mnada72 3 ай бұрын
Thank you for the valuable lectures. The solution of problem 7 should be 0.571 mA
@aashiqrasoolnajar3873 4 ай бұрын
👍🏻
@azysgaming8410 4 ай бұрын
Siir please continue this series. I have followed your EEE and EM both lecs and tut videos, they were very useful.
@EngineeringDevotion 2 ай бұрын
Thank you, I will
@Luciusilver 4 ай бұрын
Sir please how do I know that the 6000V/400V represent the phase voltage or line voltage?
@EngineeringDevotion 4 ай бұрын
If you are dealing with 3-phase systems then the mentioned voltage will be always the line voltage, unless otherwise specified as phase voltage. Similarly, the power mentioned will be the three-phase power.
@Luciusilver 4 ай бұрын
@@EngineeringDevotion Thanks 🙏
@periskamau6067 4 ай бұрын
Thank you, sir.
@EngineeringDevotion 2 ай бұрын
Welcome!
@jayjayTT868 4 ай бұрын
Nice tutorial on 3PH I.M. numericals. @13:27, I think an error was made for the ratio "Full-Load Torque to Starting Torque". The Expression shown on screen is the ratio of Full-Load Torque to Maximum Torque.
@PRANAVSAIPALADUGU 4 ай бұрын
in @10:49 is it Volume or Voltge bcoz down below in the slide volume is mentioned
@EngineeringDevotion 4 ай бұрын
It will be volume, as eddy current loss is material specific.
@PRANAVSAIPALADUGU 4 ай бұрын
@@EngineeringDevotion Thank you Sir!!
@mnada72 4 ай бұрын
Sir, How these 2 machines are identical while their nameplates are slightly different
@EngineeringDevotion 4 ай бұрын
Identical machines means that both machines can be interchangebly be used as motor or generator.
@mnada72 5 ай бұрын
17:25 Sir , shouldn't this be 5 A , the same case if you connect 2 voltage sources of the same rating in parallel.
@EngineeringDevotion 5 ай бұрын
The two voltage source can be connected in parallel provided they are of same magnitude, and there will be currrent division as per KCL. The magnitude of the current depends upon the associated resistance with the voltage source as I = V/R.
@mnada72 4 ай бұрын
@@EngineeringDevotion I agree, but for the 2 current sources of the same rating 5 amp the result should be 5 amps not 10 amps if I understand correctly.
@mnada72 5 ай бұрын
In the load test it's noticed that when you increase the load on the generator the voltage dropes and the speed increases(strange behavior), you adjust the speed by decreasing the field current of the motor. My question will you be able to adjust the generator voltage by increasing the field current of the generator?
@mnada72 5 ай бұрын
I think somehow when you increase the load of the generator, the motor voltage increases which is responsible for the increase of the generator speed. This could be due to power source regulation issues.
@EngineeringDevotion 5 ай бұрын
Yes, Increasing Generator Field Current Can Increase Voltage Increasing the field current of a generator will indeed increase its output voltage. Understanding the Relationship Here's a breakdown of the key factors involved: Generated voltage (E) is directly proportional to the product of magnetic flux (Φ) and the rate of change of flux linkage (dΦ/dt). Magnetic flux (Φ) is directly proportional to the field current. Rate of change of flux linkage (dΦ/dt) is influenced by the generator's speed. Therefore, increasing the field current will increase the magnetic flux, which in turn will increase the generated voltage.
@mnada72 5 ай бұрын
@@EngineeringDevotion Thank you ❤️
@mnada72 5 ай бұрын
11:43 Is it armature slots or commutator segment?
@mnada72 5 ай бұрын
1:15 please suggest a course on "System theory" and "Logic theory"
@congvan62227 5 ай бұрын
Dear Sir, may I inquire about the formula Z1 = Zp + Zs/(a^2) shown at 25:14? I'm curious about its origin and the specific knowledge it relates to. I sincerely apologize, Sir, as I struggle with understanding your lectures, so I've only been able to grasp the information through your presentation slides.
@EngineeringDevotion 5 ай бұрын
The equivalent input impedance (Z1) on the primary side of the transformer is obtained by the given formula. Here, Zs/(a^2) is the "reflected impedance" on the primary side. To understand it better watch the video lecture on magnetically coupled circuits in the Leccture playlist of Electric Circuits & Networks.
@EngineeringDevotion 5 ай бұрын
To understand power system in a better way first you ahve understand electric circuits and basic electrical engineering. As they are the foundation for the power system course.
@sumedh6878 5 ай бұрын
useless
@mnada72 5 ай бұрын
Are both the peaks of emf and torque occurs when the plane of the coil is parallel to the field lines ?
@methematics. 5 ай бұрын
hello sir i have a question and hopefully you can answer. When i have the phasor for one polar voltage how i can find the other voltage phasors ? (i only know that i have to use the law of cosines but when i try i get different results) , example 11.2 from the book power system analysis by john grainger & william stevenson
@EngineeringDevotion 5 ай бұрын
If I understood your question as how to find the voltage of the other phases having known the voltage of one phase, correct? So, for a balanced 3-phase system, for abc phase sequence, all the voltage magnitude will be same and diaplaced from each other at 120 degrees. If this is what you ask, then see my lecture on three-phase circuits for detail.
@mnada72 5 ай бұрын
3:11 if theta is the angle between the field lines an the velocity of the conductor then what is alpha ?
@mnada72 5 ай бұрын
3:15 why masses are involved here ?
@mnada72 5 ай бұрын
10:27 for theta 90/180/270/360 torque is zero not stabe 14:10 How this is stable position? 18:27 It's confusing to see magnetic field lines enter the North pole as indicated by the first figure. Also I think in the 3rd figure according to the electromagnet indicates the 180 degree not 270 degree Thank you, I am learning alot from this playlist ❤
@mnada72 5 ай бұрын
"The magnetic circuits are never excited by DC supply", is this always true? I thought there is no emf induced by there is flux by DC supply Also L depends on physical properties of the inductor but the behavior of the inductor depends on the type of the supply I find this part of the slide confusing
@EngineeringDevotion 5 ай бұрын
The magnetic circuits can be excited by a DC supply, but the nature of the excitation is different from that with an AC supply. With a DC supply, the magnetic flux is constant (once the transient period is over), while with an AC supply, the magnetic flux continuously changes. Your understanding is correct that while no EMF is induced in a steady-state DC condition, there is still a magnetic flux produced. Additionally, the inductance is a physical property of the inductor, but its behavior does indeed depend on whether the supply is DC or AC.
@congvan62227 5 ай бұрын
Hi Professor. I am a student in a university, I really enjoy watching your lectures on power transmission lines. I have watched the lectures on medium and long transmission lines, but I noticed that the parameter "conductance" is not mentioned. I would like to ask why this parameter is not discussed and whether or not it is important for medium and long transmission lines. In addition, I am also curious if not mentioning the "conductance" parameter has any impact on the discussion of "propagation constant," "attenuation constant," and "phase constant" in the "tuned power lines" lecture. I look forward to hearing from you soon.
@EngineeringDevotion 5 ай бұрын
Conductance (G = 1/R) is a shunt parameter along with capacitance. G is a representation of the "dielectric losses" that depends on several factors, such as humidity, temperature, etc. This has to be obtained through measurement and no direct formula is available to calculate it. Usualy, R value is very high in Mega-ohms, so G is very small, and hence usually neglected for approximate calculation.
@congvan62227 5 ай бұрын
@@EngineeringDevotion Thank you very so much
@mnada72 5 ай бұрын
8:47 How/why phi_1 =phi_2 ?
@EngineeringDevotion 5 ай бұрын
In a core with a very small air-gap, the flux remains constant or rather we assume it to be constant for calculation purpose.
@mnada72 5 ай бұрын
Inductance was not introduced in the lectures !
@EngineeringDevotion 5 ай бұрын
Inductance is discussed separately in a dedicate lecture in the same playlist. You may see that.
@Adnanwagle 5 ай бұрын
🔥
@EngineeringDevotion 5 ай бұрын
All the best !!
@bbalaraju2991 5 ай бұрын
Super explanation sir 🎉
@EngineeringDevotion 5 ай бұрын
All the best
@m.tharunnaik3365 5 ай бұрын
Nice explanation sir
@EngineeringDevotion 5 ай бұрын
All the best !!
@azysgaming8410 5 ай бұрын
At 9:38 why is i2' = -i2K why is the minus sign there
@EngineeringDevotion 5 ай бұрын
i2' is in antiphase (180 degrees) with i2. So, here negative sign indicates angle (or direction). The magnitude of i2' = k.i2. Since, we have to deal with vector arithmetic operation so proper sign is very important.