Thank you for posting such clear and thorough lectures!
@abstract8357 жыл бұрын
such clearity=========
@Alkis057 жыл бұрын
This guy deserved a better cameraman. He didn't aim the camera on the professor during the whole intuitive explanation of what is a bundle.
@antoniolewis10167 жыл бұрын
Interesting points about the sociology of large physics projects, and about the military holding up gamma ray discoveries.
@antoniolewis10167 жыл бұрын
It's a shame this lecture cuts off at the end.
@antoniolewis10167 жыл бұрын
"He just looks, and you're dead!"
@rahnumarahman62277 жыл бұрын
Can anybody kindly tell me what literature is being followed here.......the lecture is great but It helps having a literature reference that you can look at.
@antoniolewis10167 жыл бұрын
I'd like to keep my nose, thanks.
@antoniolewis10167 жыл бұрын
I love that he had to clarify the stone has no free will, in case anyone was confused.
@antoniolewis10167 жыл бұрын
This man crafts his lectures from diamonds. He even has board cleaners!
@md2perpe7 жыл бұрын
"What brings you closer to God? A Hamiltonian!" :-D (@1:15:10)
@karimsouidi17 жыл бұрын
This is one of the best lectures ever !
@drlangattx3dotnet7 жыл бұрын
I am a hobbyist who never graduated college 40 years ago but I never lost my interest in math and physics. Yes sir, Professor Schuller. You are a very good teacher. THis is very special to us, your students. Thank you.
@drlangattx3dotnet7 жыл бұрын
Terrific instructor. Thank you sir.
@snaqvi697 жыл бұрын
Thanks for going out of your way to build physical intuition in the abstract concepts. Hallmark of a great teacher!
@viveknsharma7 жыл бұрын
Fantastically Well-Planned!
@arshnoorie7 жыл бұрын
Thank you so so much for such wonderful lectures. Your very great clarity about our imagination and the real world and the way you explained it was hugely motivating..
@吉田新一-l5w7 жыл бұрын
he is genius
@theleastcreative7 жыл бұрын
This whole lecture series is amazing
@pianoman18577 жыл бұрын
For the first example how can he define the set P as linear combinaison of whatever element whithout define an add and mult law on x^n ?
@theleastcreative7 жыл бұрын
Is there somewhere that the tutorial papers can be downloaded from? I'd love to print them off and work through them.
@xxqq967 жыл бұрын
What is the prerequisite for this course?
@theleastcreative7 жыл бұрын
Did anyone attend this and still have the questions from the tutorials?
@theleastcreative7 жыл бұрын
Did anyone attend this and still have the questions from the tutorials?
@nahakuma7 жыл бұрын
Maybe you refer to these ones: gravity-and-light.herokuapp.com/tutorials
@theleastcreative7 жыл бұрын
you're amazing!
@think20867 жыл бұрын
I agree with the commentators below. He is an incredible educator. His presentations are super crisp and efficient. Thank you for posting these! Deeply appreciated.
@think20867 жыл бұрын
For the circle to polar coordinates part, correct me if I'm wrong, but I think why people got confused is because arctan is defined only on the RIGHT hemisphere of the circle, with asymptotes on the output of arctan at -pi/2 and pi/2, so y(U) would only map between -pi/2 and pi/2 (180 degrees total) instead of from 0 to 2pi (360 degrees total). The line he removed in the domain should have been the VERTICAL axis (m=0), not the horizontal axis (n=0), to avoid dividing by zero in the ratio m/n. The other big problem with arctan is that it takes a single number, which is usually our ratio n/m. But if both n/m are negative, your result is positive. If either one of them is negative, than the result is negative. So there is information loss. Quadrant I and III look the same to arctan, as does II and IV. To go beyond this to map the entire circle to polar coordinates and use all of 0 to 2pi, you need more than just arctan... you need a sort of "enlightened" arctan that takes TWO parameters (so that the ratio m/n doesn't hide which of m or n is negative), or you need to do it piecewise with conditions that separate the four quadrants so you can treat quadrant I and quadrant III (both of which give m/n positive), and quadrant II and quadrant IV (both of which give m/n negative) distinctly. The two parameter version of arctan is better though as it also avoids the divide by zero issue (you pass in m and n separately, so no need to worry about n/m with m=0), which then allows you to avoid removing the m=0 line in the domain. In standard programming languages, this is called atan2(m, n). He should have used this instead of arctan to avoid all these issues. Or am I missing something?
@rishabhkumar95877 жыл бұрын
Exactly what I was thinking! Atan2(n, m) is exactly what is used in complex analysis for the definition of the argument of the complex number.
@antoniolewis10167 жыл бұрын
You are correct. Though if he had gone for a polar theta region of 0 to pi, it would have also worked.
@vs-cw1wc7 жыл бұрын
The expression for 3-velocity written down at 1:24:56 is not the correct form. The right hand side should be divided by the gamma factor.
@md2perpe7 жыл бұрын
No, the gamma factor is implicit in epsilon.
@leanhdung98487 жыл бұрын
Very interesting and inspiring lecture.
@vs-cw1wc7 жыл бұрын
I like how they made an effort in showing the students' questions in text. Very sweet.
@RalphDratman8 жыл бұрын
Superb lecture
@rubenlimasca44888 жыл бұрын
Muy fácil.
@skun4068 жыл бұрын
Thanks for uploading those lectures.
@leebill1098 жыл бұрын
Very nice lectures
@travellcriner68498 жыл бұрын
I'm definitely a huge fan of these lectures and the amazing strength of intuition utilized. My hunger to learn is awakened by these lectures. I have to say though, I'm not a huge fan of the "noses" analogy. I think it hinders the talk of dimensionality especially around 29:00 .
@miz45358 жыл бұрын
Can someone explain how he obtained the second derivative at 35:00?
@brucexing69547 жыл бұрын
Because the components of the vector field r(t) along r are dxi/dt
@brucexing69547 жыл бұрын
using coordinate x1,…xn
@lokendrasunar54578 жыл бұрын
Great dedicated professor.Very comprehensive lecture .Lucky me.
@eenblanke8 жыл бұрын
Fantastic lectures! This is the way it should be done . So clear, concise and even entertaining at time. German efficiency and thoroughness shows through. Thanks so much to the folks that posted it
@amudan838 жыл бұрын
This is a really beautiful and insightful interpretation of Newton's laws. Thank you so much Prof. Schuller!
@Rubbergnome8 жыл бұрын
Wow. This lecture blew my mind. Awesome, I gotta check out this line of research!
@josephavant82508 жыл бұрын
This professor is EASILY one of the best I've ever seen - every student should be so lucky to study from such an articulate, patient, and clear instructor at some point in their academic career!
@luke0018 жыл бұрын
I thought that the tangent spaces TpM for all point p in a manifold M were automatically disjoint, ie they dont share any elements.
@travellcriner68498 жыл бұрын
You're correct, although some elements of TpM may look like elements of TqM. I believe the point here is to emphasize that they're not the same even though they look the same. I'll explain: 1) Recall our definition of an element of TpM, namely a velocity v_r,p(f) where r is a curve on M through p and f is in C^inf(M). I like, in this respect, to think of C^inf(M) as a collection of all possible landscapes over M. Then v_r,p tells us the change in height we'd feel over any inputted landscape taking the particular curve r through p. So really, v_r,p is a collection of rises/falls. 2) It's conceivable that TpM and TqM may appear to have some shared collection of rises/falls. Even if that's the case, we understand these collections (the velocities) are to be thought of as totally different -- for one is only relevant to the point p and the other to the point q. 3) Imagine I wanted to create a set containing a '1' for every star in the observable universe. You might try unioning lots of copies of {1} together. But {1}U...U{1} = {1}, because sets don't care for repetitions. To get around this, we may secretly add a bit of information about the star into each of the 1's and publicly refer to the unions as disjoint unions. I'm pretty sure this is the idea behind him stressing disjoint union. I would appreciate if someone with more expertise confirmed or correct this idea, and I hope I helped as well.
@MrAkashvj968 жыл бұрын
Yes you do not have to worry about disjoint condition in this case because it comes implicitly.
@wschadow8 жыл бұрын
A crystal clear series of lectures, thank you!
@EarlWallaceNYC8 жыл бұрын
I'm loving these lectures. They are rigorous, well organized and entertainingly presented. Where else can I find a reverence to Machiavelli in advanced mathematics.
@evilcman8 жыл бұрын
Does anybody have the exercise sheets?
@oliversimpson7308 жыл бұрын
Hi, I am struggling to prove that the map G is multilinear. Where does v,w and x fit into the vector space, are they each vectors or components? The map is defined using a1, b1,..., c2. What are these entries is terms of v, w, x? I understand what is to be proved I am just struggling to go through the necessary steps.
@time_traveller248 жыл бұрын
Thank you sir...your lectures were extraordinary
@giannisniper968 жыл бұрын
what did he do at 17:25? what's g(delta_x, gamma_dot)?
@MaxwellsWitch8 жыл бұрын
I love it when you give the axioms first before you start calculating shit, that removes ambiguity and confusion. thx m8.
@amolvaidya068 жыл бұрын
dx2/dy1 has me a bit confused on problem 3. Should it be -3a^2? The way I'm interpreting the symbol is that the second component of x o y^-1 should be derived with respect to u. Is this not correct?
@amolvaidya068 жыл бұрын
He fixes the mistake just a few minutes later.
@52wtf8 жыл бұрын
For anyone interested in the problem sheets: gravity-and-light.herokuapp.com/tutorials