You really need to stop inflicting your guesses upon the public as fact. There's a chance someone is going to believe you.

wtf?

实验中水压高于大气压的原因是，水所承受的重力。影响大气压（静态）的主要因素是温度、海拔高度和相对湿度（换说法就是大气密度和粘度），这三者在讨论机翼升力模型中应该看作一致的，所以如果空气如果不流动的话，上下压力一样，当流动时，迎风面下缘会使流速降低，上缘流速增加，流速慢的地方密度大，压力也大，这是伯努力原理，老师没讲错。

人才啊，进一步思考你就发现重力根本就他妈没有，反重力就是个屁，但是所有依靠这些技术吃饭的傻子都会拍死你

不就是因为流体速度大所以产生了低压区域，所谓背风区不就是低压区域吗，没有流速哪里来的低压区域，你这是要推翻伯努利原理是吧

実験していますが、歳差運動の慣性力でも理解できるようです。

The reason the manometer is low with flow is the pressure loss in the tube. A shorter tube should squirt farther with no pinching. so. . . If you can get the vertical tube manometer right at the bottom of the 'container' tank, the level in the manometer should stay near the top of the level in the container when you pinch the tube. If you also get the end of the hose close to that, his gets close to a constant pressure system and the 'pinched' water will not go farther. . Perhaps if you can also use a larger tube between the container and manometer to reduce the pressure loss with speed, due to the viscosity. . I believe that doing that demonstration will also improve the lesson. . I am always showing people this video.

Enbin, It is not clear when water is being drawn into your hose. It would be nice to have some particles in the water to see water movement.

当终焉的陨星在白垩纪降下，唯有自由的鸟儿跳出陨星中的灭亡

，

Very nice. I've seen this before HOWEVER, Enbin, PLEASE understand that it it the inertia that causes this for both the upper AND lower flows. INERTIA. Air has mass and follows Newton's First Law. It "wants to'" or "tries to" go straight.. .just like a brick. .. Here is mine that explains only the upper flow. kzbin.info/www/bejne/aX62opWkl7B3o68

The English subtitles are a little confusing, but because you compared the chain with a rope, I do not think you are on the right path. The rope will only achieve this effect at the very end of the rope. This U believe is because the rope has a certain amount of momentum pulling it upward over the lip of the beaker (or the edge of this table) overcoming the force of the tension put on it by the mass of rope resting on the table. When the rope gets to the end, and there is no longer any significant mass of rope left on the table, the rope is still carrying momentum and is now traveling with an upwards force which is greater than that needed to rise over the edge, because there is no longer any tension force acting against that upward movement, so the momentum provides it with the excess force needed to momentarily rise into the air. This is a completely different process than that which is acting on the beaded chain rises into the air long before it gets to the end. What is happening with the beaded chain is unique to this chain type and is due to its unique design and mode of articulation. Each bead is hollow, and each link is shaped like a barbell, so when the links are fully extended outside of the beads, they have no range of movement. For maximum range of movement and the the ability for the chain to curve, the links must be fully submerged inside the beads, with the ends of the "barbells" in the center of the beads where they have the most space to move. The more you extend the chain, and the further the links are extended outside of the beads, the less range of motion the chain has. This is all very evident and easy to see upon examination of one of these chains. Therefore it is my theory, that with forces pulling on both ends of the chain as it travels over the lip of the beaker, that this segment of chain becomes more fully extended, and we know when the chain is fully extended it is not possible for it to turn in any direction, so this segment of chain becomes a rigid tower. There is tension pulling it out of the beaker, and tension holding it down in the beaker, hence why it is fully extended was you can see in video. And to repeat what I said before, when fully extended, it cannot form a curved section of chain, so it keeps traveling upwards, this rigid tower growing taller and taller. The greater the distance the chain has to fall, the greater the mass of falling chain there is acting upon the chain coming out of the beaker, creating more tension from that end of the chain, which determines how tall the chain fountain can "grow". It will continue to grow until it reaches critical mass. That is, when the weight of the upward fountain segment (the rigid tower segment) begins to eclipse the tension acting on it, and it cannot support any additional links being fully extended outside of their links. So with further links traveling partially submerged inside of their beads, it allows the chain to curve downward.

Now you're getting it. I believe my roller coaster analogy is very good: *kzbin.info/www/bejne/aX62opWkl7B3o68*

不需要到太空，在地球上能做到接近真空

Also, Enbin. This explanation using the "narrow" and "wide" idea fails. This is because BELOW the trailing edge is *another *"narrow" BUT there is NO lowered pressure there - this would force the trailing edge *down*! This explanation, therefore would only rotate the wing clockwise. Sorry, but the narrowing, or 'pinching' above the wing is NOT the cause of the lowered pressure. The air far above the wing is not a hard wall, but it is very soft and allows air to flow easily. It is not a pipe wall. .. .. .. .. The cause of the lower pressure is the *turning* of the air. . I explain this in the video that I did. Inertia causes the lower pressure. Think VERY carefully about the roller coaster analogy. It provides a good analogy for the lowered pressure inside a curved flow. We feel that gravity is reduced at the op of the roller coaster, just like pressure reduces on the inside of a curved flow. . kzbin.info/www/bejne/aX62opWkl7B3o68 Best regards, Steve

為什麼由重力導致珠鏈向下的作用力會越來越小呢 1:02那邊

康达附壁效应

请答两个问题： 一，飞行动物除了飞鸟还有蝙蝠和会飞的昆虫,如蚊蝇蜂蝶，请问会飞的昆虫翅膀会在向上扇时弯曲吗？ 二，蜂鸟既能振翅而飞，又能振翅悬停，振翅中悬停意味着振翅不产生飞力，为什么？

Enbin, I wanted to show a friend your video like this that has a small hole after the edge and the water draws air from that hole. He had a question ant that video it would help him. It appears that you removed it?? Regards, Steve N. From Quora.

謝謝！～

啊不是inertia吗？🙃

小球和空气有什么关系？空气不受惯性引力，读完初中再来装逼吧

可以去看一下佑來了

這個影片講解好清楚，但是不太清楚球面ABCDE各角是指哪個角～

简单明了

Thank you for your video. I have linked in my text about the Bernoulli' principle. newtheories.info/community/main-forum/the-bernoullis-principle-can-be-found-in-the-electric-current-too/

Enbin, I think you mean Boyle's law. Unfortunately it is well known by direct measurements that the amount of density change around a subsonic wing is far below what it takes to explain lift. The pressure changes are much too small. .. The inverted two plate system will not levitate the free plate. The pressure above the plate is lower than the pressure in the center pipe now , thus pushing the plate down.

終於不用白努利就能懂了 太感謝了

我覺得不是，我自己在飾品材料工作，我拿了各式鍊條測，只有珠鍊不管粗細都有此現象，其他二十幾款鍊條都無此現象。

对

This is a very good demonstration. However, I suggest that it is not a good technique to use a formula to explain the science/physics. I suggest that the explanation is the fact that the pinching the tube is a restriction in the flow. This causes a reduced flow. Reduced flow causes less pressure loss in the tube from viscosity along the length of the tube. Less loss in the tube causes increased pressure at the end. Increased pressure causes greater velocity out. ..... We can see that there is significant pressure loss along the tube because it is so low in the manometer tube compared to the height of the water in the reservoir. Understanding this allow understanding why pressure drops in the standard Venturi tube. The narrow section is a restriction that raises the pressure in the wide section *before* the narrow section. Regards

這篇才是正解 網路很多解釋都是錯的

存在 离心力，没有‘向心力’。 在传统物理中，大家对一般的物理规律在'匀速直线运动'，或者叫'惯性'系统中适用， 而在'非匀速直线运动'，或者叫'非惯性‘系统中，物理规律依然适用。 因为我们可以等效的看成这是一个由'单个'或者'多个'引力场叠加的系统。__________引用爱因斯坦的'广义相对论'。 举个例子：当我们在一个'加速度=9.8m/s'的飞船上做物理实验时， 它的效果等同于在静止在地球表面做相同的物理实验。 或者说，一个均匀的引力场与一个等加速的非惯性参考系在力学上是完全等价的，这就是等效原理。 a = g '加速度'等效于'引力场' 现在看一个特殊的例子：匀速圆周运动 a = ω²r(a是加速度，v是B点处的线速度，ω是角速度，r是半径) A点在圆心 B点在圆周上 根据公式a = ω²r 在线段AB上，角速度处处相等，A点处的加速度等于0，随点到圆心的距离增加加速度的值增加，B点处的加速度达到最大值。 a'B' ＞ a'A' 等效原理， a = g （a'B' ＞ a'A'） = （g'B' ＞ g'A') 此时物体有从A点向B点移动的趋势，所受到的力，为‘离心力’。

存在 离心力，没有‘向心力’。 在传统物理中，大家对一般的物理规律在'匀速直线运动'，或者叫'惯性'系统中适用， 而在'非匀速直线运动'，或者叫'非惯性‘系统中，物理规律依然适用。 因为我们可以等效的看成这是一个由'单个'或者'多个'引力场叠加的系统。__________引用爱因斯坦的'广义相对论'。 举个例子：当我们在一个'加速度=9.8m/s'的飞船上做物理实验时， 它的效果等同于在静止在地球表面做相同的物理实验。 或者说，一个均匀的引力场与一个等加速的非惯性参考系在力学上是完全等价的，这就是等效原理。 a = g '加速度'等效于'引力场' 现在看一个特殊的例子：匀速圆周运动 a = ω²r(a是加速度，v是B点处的线速度，ω是角速度，r是半径) A点在圆心 B点在圆周上 根据公式a = ω²r 在线段AB上，角速度处处相等，A点处的加速度等于0，随点到圆心的距离增加加速度的值增加，B点处的加速度达到最大值。 a'B' ＞ a'A' 等效原理， a = g （a'B' ＞ a'A'） = （g'B' ＞ g'A') 此时物体有从A点向B点移动的趋势，所受到的力，为‘离心力’。 没有离心力吗？为什么？ - 你好明天的回答 - 知乎 www.zhihu.com/question/20077058/answer/345060985

我認為其實曲線運動和杯子作用力都有對噴泉現象造成影響。 排除地面因素的原因是因為從高度超過珠鍊長度的地方落下仍會引發噴泉 ...不如說接觸地面反而會阻止噴泉現象的產生 至於杯子對於珠鍊的影響，我們可以將杯子傾斜，有人有這麼做過 在頂點之前那段珠鍊的上升方向，整個圓周的弧度會隨著杯子的傾斜角度而改變 也就是說增加杯子的斜率就會增加珠鍊的水平位移 因此可知杯子處也有一段向珠鍊作用的推力 而杯子端推力的來源和上升段產生的波有關 ~A-----B~ 若在一硬物的兩端繫上繩索，快速從A端向上拉起時 在該物呈順時針傾斜的同時整個物體會向右上方移動 這源自B端因角度關係而向左下施壓時產生的反作用力所致 因此這段曲線會朝向杯子底面產生力，而也有反作用力的產生 所以我認為珠鍊用杯裝或盤裝能夠增加噴泉的高度 當然，圓周運動的因素才是主要的成因啦 我只是覺得跟杯子也有點關係而已 提米有沒有哪裡說得不好呢~

拍得不清楚難以驗證有關白努力定律的現象

其實我還蠻認同你這個解釋方法的， 但是我想請問一下如果按照這個解釋方法， 那麼在「佑來了」的影片中， 所演示的「反作用力」，又是從何而來的呢?

kzbin.info/www/bejne/o2jYmpZuo7N9bJI 噴泉現象的反重力原因及升力的原因

這樣讓我覺得更需要杯子了，看起來很像甩出的波，給的反作用力

kzbin.info/www/bejne/pnucZ6CApcpgppI 康達效應的原因

kzbin.info/www/bejne/pnucZ6CApcpgppI 康達效應的原因

You talk a lot, but you don't say it clearly: When the water in the bucket spins, the water is Paraboloid. There is a pressure gradient (a normal pressure gradient on the bucket wall). This pressure gradient provides centripetal force. Without this pressure gradient, there is no centripetal force, and the water in the bucket can not rotate. Right? Are you sure about my point?

You didn't answer my question. Is there a pressure gradient in that bucket?

The pressure from the axis of rotation to the wall of the bucket rises, or there will be no centripetal force necessary for the rotation.

Note that, in order to simplify the problem, we here say fluid in the bucket is an ideal fluid, so we do not need to consider issues such as friction, so in this case there is no pressure gradient? Uniform motion exists, and ideal fluid can move at constant speed.

Strange, how come you don't know? That's common sense.In the gravitational field, assuming that the fluid in the bucket rotates at a constant rate and that the axis of rotation is parallel to the direction of the gravity field, the isobaric surface of the fluid is a paraboloid. In the vertical direction and in the direction of the rotating axis (in the horizontal direction), the pressure of the fluid is gradually decreasing. Is this also called the pressure gradient?

It is common knowledge that the constant pressure surface of a fluid rotating in a bucket is a paraboloid (the attention is to rotate at a constant speed rather than to accelerate it), which is known to all middle school students. It is also true that there is a pressure gradient. This is also very simple. Of course, the pressure gradient will have lift. The same is true of the lift force in the atmosphere, as there is motion along the normal direction of the wing, which results in a pressure gradient, and hence a lift. My understanding of lift is not wrong. As for what you are talking about, McLean, of course I will read his book. I suggest you give me a link to his book. I can understand his point of view. What's his title?

In the gravitational field, the isobaric surface of the stationary fluid in the bucket is a series of parallel planes, while the vertical pressure of the liquid is a series of paraboloid. It's not my guess, it's true.

In the gravitational field, the isobaric surface of the stationary fluid in the bucket is a series of parallel planes, while the vertical pressure of the liquid is a series of paraboloid. It's not my guess, it's true.