Link to download ppts/lecture notes: drive.google.com/drive/folders/1AtR1eq6ZvQf-5vjXEMUPXNj2S0d9rAMZ?usp=share_link

@StudywithDrDafda Thankyou so much sir ☺️☺️

OK. Will try.

Yes, the MATLAB function medfilt2() uses padding when performing median filtering. By default, it pads the input image with zeros around the border. This means that the edges of the image will be treated with a value of zero when calculating the median for the pixels at the border. You can specify different padding options by using additional arguments or by preprocessing the image before applying the median filter.

@@StudywithDrDafda what is padding sir?

Padding refers to the process of adding extra values around the border of an image (or matrix) to allow certain operations, such as filtering, to be performed at the edges or corners of the image. The added values are used to fill the region outside the original image boundary during operations like convolution, filtering, and other spatial operations, ensuring that every pixel in the image, including those near the edges, can be processed in the same way as those in the center.

Thank you.

OK. Thank you for the suggestion.

The book is, Digital Image Processing by Gonzalez and Woods.

Present in the video at 8:47

Thank you.

Thank you respected Sir.

Sorry, I do not know tamil. You can watch the Hindi playlist of Digital Image Processing, other than the English playlist.

Yes.

@@StudywithDrDafda oh really 😲 actually I live in gujrat that's why I asked you sir, but really your teaching skills are nice

Thank you.

Image negatives can make certain details more visible, especially in images where the background is dark and the foreground is light. In medical imaging, such as X-rays, image negatives can help highlight specific features that might be less visible in the original image.

​@@StudywithDrDafdathank you so much sir..

Thank you.

In chapter 2 Image enhancements and filtering, both spatial domain and frequency domain filtering ppts are present.

No. ND(P) are four diagonal neighbours, while N8(P) is all eight neighbours of P. That is N8(P)=N4(P)+ND(P). While considering neighbourhood pixels.

Yes, you can say that, while considering adjacency.

The set V is constant for range {0 to 10}, which means V can range only from 0 to 10. And we have to consider only values in between 0 to 10.

Code is present in the description box.

It is a inbuilt MATLAB function.

At 7:28, the 7 output value has FD in the dictionary, and not FDA. Check dictionary location number 7, it is FD and therefore always last character is required for correct decoding.

Thank you.

kzbin.info/www/bejne/q4XHc3mobauhY9k

You are most welcome

You can try to remember the concepts.

Replace that line with I=I+100; This should solve your error.

@@StudywithDrDafda still error sir imadd requires Image Processing Toolbox. Error in untitled (line 6) I = imadd(I=I+100);

Yes, it will require Image Processing Toolbox for execution. You need to install it .