In many cases, alpha =0.05 is used as the cutoff for determining statistical significance which is what I am using here . There are many reasons for choosing this level of significance, you might come across them later on if you study inferential statistics as part of a course you are taking

why would you need a calculator to answer these lol it’s literally looking at the chart and what value matches the value you’re looking for. all she did was use excel to add when you can literally just write out the numbers and add. hope this helps

right lol this video was great @@kambam2336

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@@asmaalayeb7811 thanks very much indeed

81/985 =8.22%

@@asmaalayeb7811 Thank you so much I have a question regarding the problem because I know based on the meaning of the language of statistics, I could not find a example problem of the above question and before you could respond to me I made a guess and got it wrong so I am doing another question and I do not understand the probability lingo. is or & nor the same like; the pedestrian mor the driver was intoxicated? is the pedestrian and the driver were not intoxicated the same as both the pedestrian nor the driver were intoxicated while driving? i'm confused

The table summarizes results from 976 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Pedestrian Intoxicated? Yes No Yes 60 82 No 242 592 If one of the pedestrian deaths is randomly selected, find the probability that neither the pedestrian nor the driver was intoxicated. Please enter a decimal to 4 places.

@@tanjonzou9840 yes those are the same

So that would be 592/976 =0.6066

Age would be explanatory, mileage would be response since mileage is dependent on age , not the other way around

@@asmaalayeb7811 thank you !

Use =countifs( data , ">="&lower limit,data,"<="&upper limit). Make sure you lock your range

I have another video explaining it too

This process is just to integrate one course to D2L, so it will not work for site-wide integration. I don't think site wide is possible though, since MOM doesn't have the capacity of creating instructor accounts automatically . Each instructor has to sign up for MOM and get approved by one of the admins. You can sign up for a MOM account, then request the privilege of adding new users on behalf of school, so your instructors don't have to wait for an approval The integration of courses should be done by each instructor individually in that case I know I am not very helpful, sorry. I suggest that you direct this question to David Lippman or one of the other admins on MOM

Happy to help

Glad this helped you